a: (-17)+5+8+17

\(=\left(-17+17\right)+\left(5+8\right)\)

=0+13

=13

b: \(\left(-24\right)+6+10+24\)

\(=\left(-24+24\right)+\left(6+10\right)\)

=0+16

=16

c: \(\left(-24\right)+6+\left(-10\right)+24\)

\(=\left(-24+24\right)+\left(6-10\right)\)

=0+(-4)

=-4

d: \(\left(-456\right)+2021-544\)

\(=2021-\left(456+544\right)\)

=2021-1000

=1021

e: \(\left(-1075\right)-29-\left(-1075\right)\)

\(=-1075+1075-29\)

=0-29

=-29

f: \(\left(-135\right)+48+140-\left(-5\right)\)

\(=48+\left(-135+140+5\right)\)

=48+10

=58

g: \(329+64+\left(-394\right)+36\)

\(=\left(329-394\right)+\left(64+36\right)\)

=100-65

=35

h: \(\left(-427\right)+\left(-123\right)+23+27\)

\(=\left(-427+27\right)+\left(-123+23\right)\)

=-400-100

=-500

Trả lời :

a) 4³ . 101 - 64

= 64 . 101 - 64

= 64 . ( 101 - 1 )

= 64 . 100 = 6400

b) \(\frac{5^8}{5^5}+3^2.3^3-\left(30-19\right)^2\)

= 5³ + 3⁵ - 11²

= 125 + 243 - 121

= 247 

a) 4³ .101 - 64 =

= 4³ . 101 - 4³ 

= 4³ .( 101 - 1 ) 

= 4³ .100

= 6400

c) 100 - [( 64 - 48 ) . 5 + 88 ] : 28

= 100 - ( 16 . 5 + 88 )  : 28

= 100 - ( 80 + 88 ) : 28

= 100 - 168 : 28

= 100 - 6

= 94

1: \(=\dfrac{272-168+186}{30}\cdot\dfrac{7}{9}=\dfrac{29}{3}\cdot\dfrac{7}{9}=\dfrac{203}{27}\)

2: \(=\dfrac{9-55}{33}\cdot\dfrac{6-5}{8}-\dfrac{4}{5}\cdot\dfrac{1}{24}=\dfrac{-4}{3}\cdot\dfrac{1}{8}-\dfrac{1}{30}=\dfrac{-1}{6}-\dfrac{1}{30}=\dfrac{-6}{30}=-\dfrac{1}{5}\)

3: \(=\dfrac{7}{3}\left(\dfrac{6}{25}+\dfrac{19}{25}\right)=\dfrac{7}{3}\cdot1=\dfrac{7}{3}\)

Bài 2:

a: =76266-34578=41688

=126x37=4662

4kg x 9 – 28kg = 36kg – 28kg = 8kg

3 x 8 : 4 = 24 : 4 = 6

5 × 8 + 8 = 40 + 8 = 48

28 - 2 × 4 = 28 – 8 = 20

\(a)\)\(47-\left[\left(45.2^4-5^2.12\right)\div14\right]\)

\(=\)\(47-\left[\left(45.16-25.12\right)\div14\right]\)

\(=\)\(47-\left[\left(720-300\right)\div14\right]\)

\(=\)\(47-\left[420\div14\right]\)

\(=\)\(47-30\)

\(=\)\(17\)

\(b)\)\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]\div28\)

\(=\)\(10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]\div28\)

\(=\)\(10-\left[16.5+\left(80+8\right)\right]\div28\)

\(=\)\(10-\left[16.5+88\right]\div28\)

\(=\)\(10-\left[80+88\right]\div28\)

\(=\)\(10-168\div28\)

\(=\)\(10-6\)

\(=\)\(4\)

c) \(2345-1000:\left[19-2\left(21-18\right)^2\right]\)

=     \(2345-1000:\left[19-2.3^2\right]\)

 =    \(2345-1000:\left[19-2.9\right]\)

=     \(2345-1000:\left[19-18\right]\)

=      \(2345-1000:1\)

=      \(1345\)

\(c)\)\(2345-1000\div\left[19-2\left(21-18\right)^2\right]\)

\(=\)\(2345-1000\div\left[19-2.3^2\right]\)

\(=\)\(2345-1000\div\left[19-2.9\right]\)

\(=\)\(2345-1000\div\left[19-18\right]\)

\(=\)\(2345-1000\div1\)

\(=\)\(2345-1000\)

\(=\)\(1345\)

\(d)\)Bài này sai đề thì phải

\(177\div\left[2.\left(4^2-9\right)+3^2\left(16-10\right)\right]\)

\(=\)\(177\div\left[2.\left(16-9\right)+9.6\right]\)

\(=\)\(177\div\left[2.7+54\right]\)

\(=\)\(177\div\left[14+54\right]\)

\(=\)\(177\div68\)

\(=\)\(\frac{177}{68}\)

Nếu làm như thế này thì mình nghĩ sẽ đúng với đề bài hơn

 \(177\div\left[2.\left(4^2-9\right)+3^2\left(15-10\right)\right]\)

\(=\)\(177\div\left[2.\left(16-9\right)+9\left(15-10\right)\right]\)

\(=\)\(177\div\left[2.7+9.5\right]\)

\(=\)\(177\div\left[14+45\right]\)

\(=\)\(177\div59\)

\(=\)\(3\)