Tìm Y:
54 + Y = 79
Y + 27 = 59
2.tim y
a,y-254=812+54
b,487+y-54=600
c,87-59=y+145
a: =>y-254=866
hay y=1120
b: =>433+y=600
nên y=167
c: =>y+145=28
hay y=-117
a: =>y-254=866
hay y=1120
b: =>433+y=600
nên y=167
c: =>y+145=28
hay y=-117
Tìm các số nguyên x và y biết được là 7/x = y/27 = -42/54
\(\frac{7}{-9}=\frac{-21}{27}=\frac{-42}{54}\)
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`A)2/3=x/60`
`=>40/60=x/60`
`=>x=40`
`B)-1/2=y/18`
`=>-9/18=y/18`
`=>y=-9`
`C)3/x=y/35=-36/84`
Mà `-36/84=(-3 xx 12)/(7 xx 12)=-3/7`
`=>3/x=-3/7`
`=>x=-7`
`y/35=-3/7=-15/35`
`=>y=-15`
`D)7/x=y/27=-42/54`
Mà `-42/54=(-7 xx 6)/(9 xx 6)=-7/9`
`=>7/x=-7/9`
`=>x=-9`
`y/27=-7/9=-21/27`
`=>y=-21`
a) Ta có: \(\dfrac{2}{3}=\dfrac{x}{60}\)
\(\Leftrightarrow x=\dfrac{2\cdot60}{3}=40\)
Vậy: x=40
tìm số nguyên x, y biết 7/x = y /27 = -42/54
em đang cần gấp ạ, giúp em với !
\(\frac{7}{x}=\frac{y}{27}=\frac{-42}{54}\)
+) => \(\frac{y\cdot2}{27\cdot2}=\frac{-42}{54}\)
=> \(y\cdot2=-42\)
\(\Rightarrow y=-21\)
+) \(\frac{7}{x}=\frac{-21}{27}\)
=> \(\frac{7\cdot\left(-3\right)}{x\cdot\left(-3\right)}=\frac{-21}{27}\)
=> \(x\cdot\left(-3\right)=27\)
=> \(x=-9\)
* Lớp 6 chưa học đến tỉ lệ thức nên đây là cách đơn giản nhất r *
\(\frac{y}{27}\)=\(\frac{-42}{54}\)=>\(\frac{2y}{54}\)=\(\frac{-42}{54}\)=>2y= -42 y= \(\frac{-42}{2}\)= -21 \(\frac{7}{x}\)=\(\frac{-21}{27}\)=> -21x=7*27=189 x=\(\frac{189}{-21}\)= -9 Vậy x= -9, y= -21
B1 So sanh cac so sau
a) x=-3/17; y =-15/14
b) x=29/59;y=47/93
c) x=-79/137;y-1/1000
d)x= 415/326;y=294/487
tìm các số nguyên x và y biết : 7/x=y/27=-42/54
các bạn làm ơn trả lời nhanh giúp mình nha
7/x=y/27=-42/54=-7/9
7/x=-7/9 nên x=-9
y/27=-7/9=-21/27 nên y=-21
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\(\frac{7}{x}\)=\(\frac{y}{27}\)=\(\frac{-42}{54}\)
tìm x và y
Ta có:
\(\frac{y}{27}=\frac{-42}{54}\)
\(\Rightarrow y=\frac{-42.27}{54}=-21\)
Lại có:
\(\frac{7}{x}=\frac{-21}{27}\)
\(\Rightarrow x=\frac{7.27}{-21}=-9\)
Vậy .....
Tìm x:
\(\frac{7}{x}\)= \(\frac{-42}{54}\)
\(\Rightarrow\)\(\frac{7.\left(-6\right)}{x.\left(-6\right)}\) = \(\frac{-42}{54}\)
\(\Rightarrow\)\(x.\left(-6\right)=54\)
\(\Rightarrow x=54\div\left(-6\right)\)
\(\Rightarrow x=-9\)
Tìm y:
\(\frac{y}{27}=\frac{-42}{54}\)
\(\Rightarrow\frac{y.2}{27.2}=\frac{-42}{54}\)
\(\Rightarrow y.2=-42\)
\(\Rightarrow y=\left(-42\right)\div2\)
\(\Rightarrow y=-21\)
\(Họctốtnhé\)
\(\frac{7}{x}=\frac{y}{27}=\frac{-42}{54}\)
Ta có:
\(\frac{7}{x}=\frac{-42}{54}\)
\(\Rightarrow\frac{7}{x}=\frac{-7}{9}\)
\(\Rightarrow-7.x=7.9\)
\(\Rightarrow-7.x=63\)
\(\Rightarrow x=63:\left(-7\right)=-9\)
\(\frac{y}{27}=\frac{-42}{54}\)
\(\Rightarrow\frac{y}{27}=\frac{-7}{9}\)
\(\Rightarrow9.y=-7.27\)
\(\Rightarrow9.y=-189\)
\(\Rightarrow y=-189:9=-21\)
Vậy x = -9; y = -21
Tìm x,y:
a.42/54=7/x
b.x/15=-2/3
c.x/27=-5/9=-45/y
GIÚP MK VỚI
a, \(\frac{42}{54}\)= \(\frac{7}{x}\)=> 42x=7.54 => x=\(\frac{7.54}{42}\)= 9. Vậy x=9 b, \(\frac{x}{15}\)= \(\frac{-2}{3}\)=> 3x= (-2).15 => x= \(\frac{\left(-2\right).15}{3}\)= -10. Vậy x=-10 c, \(\frac{x}{27}\)= \(\frac{-5}{9}\)=> 9x=(-5).27 => x\(\frac{\left(-5\right).27}{9}\)= -15 Thay x = -15 vào biểu thức ta có: \(\frac{-15}{27}\)= \(\frac{-45}{y}\)=> -15y= (-45).27 => y= \(\frac{\left(-45\right).27}{-15}\)=81 Vậy x=-15, y = -81 .KÍCH NKA PẠN
Tim x,y:
7/x=y/27=-42/54