Bài 1 tìm x, biết
a,350:[19-(7x-3)]=350
b,7.[109-(x-9)]-420=0
c,254-2{200-4.[90-7.(19-9)]}.x=4
Câu 1:tìm x , biết
a,150:[17-(2x-3)]=350
b, 4.[105-(x-9)]-486=0
c,1000-2{600- 4.[198-7.(21-7)]}.x=200
Câu 2:Tìm x, biết
a,350:[19-(7x-3)]=350
b, 7.[109-(x-9)]-420=0
c,254-2{200-4.[90-7.(19-9)]}.x=54
a) 150 : [17 - (2x - 3)] = 350
=> 17 - (2x - 3) = \(\frac{150}{350}=\frac{3}{7}\)
=> 2x - 3 = \(17-\frac{3}{7}=\frac{116}{7}\)
=> 2x = \(\frac{116}{7}+3\)
=> 2x = \(\frac{137}{7}\)
=> x = \(\frac{137}{7}:2=\frac{137}{14}\)
b) 4 . [105 - (x - 9)] - 486 = 0
=> 4. [105 - (x - 9)] = 486
=> 105 - (x - 9) = 243/2
=> x - 9 = \(105-\frac{243}{2}=-\frac{33}{2}\)
=> x = \(-\frac{33}{2}+9=-\frac{15}{2}\)
c) 1000 - 2{600 - 4.[198 - 7.(21 - 7)]}.x = 200
=> 1000 - 2{600 - 4.[198 - 7.14]}.x = 200
=> 1000 - 2{600 - 4.[198 - 98].x = 200
=> 1000 - 2{600 - 4.100}.x = 200
=> 1000 - 2{600 -400}.x = 200
=> 1000 - 2.200.x = 200
=> 2.200.x = 800
=> 400.x = 800
=> x = 2
Câu 2 :
a) 350 : [19 - (7x - 3)] = 350
=> 19 - (7x - 3) = 1
=> 7x - 3 = 18
=> 7x = 21
=> x = 3
b) 7.[109 - (x - 9)] - 420 = 0
=> 7.[109 - (x - 9)] = 420
=> 109 - (x - 9) = 60
=> x - 9 = 49
=> x = 49 + 9 = 58
c) 254 - 2{200 - 4.[90 - 7.(19 - 9)]}.x = 54
=> 254 - 2{200 - 4.[90 - 7.10]}.x = 54
=> 254 - 2{200 - 4[90 - 70]} . x= 54
=> 254 - 2{200 - 4.20} . x = 54
=> 254 - 2{200 - 80}.x = 54
=> 254 - 2.120 . x= 54
=> 2.120.x = 200
=> 240.x = 200
=> \(x=\frac{5}{6}\)
Bài 1 tính hợp lí
a) 2017.;1-2018)+2018.2017+(-1)*2017
b) 7/19 8/11+3/11:19/7-2/-19
c) (6 và 4/9+3 và 7/11)-5 và4/9
Bài 2 tìm x
a) 5/6-x=-5/12-1/-4
b) x-2 trên phần -5=6/7
c) 1/2.x-3/4.x=-5/6
1b)\(\frac{7}{19}x\frac{8}{11}+\frac{3}{11}:\frac{19}{7}-\frac{2}{-19}=\frac{7}{19}x\frac{8}{11}+\frac{3}{11}x\frac{7}{19}+\frac{2}{19}=\left(\frac{8}{11}+\frac{3}{11}\right)\frac{7}{19}+\frac{2}{19}=\frac{7}{19}+\frac{2}{19}=\frac{9}{19}\)
c)\(4\left(\frac{4}{9}+\frac{7}{11}-\frac{4}{9}\right)=4\frac{7}{11}\)
từ rồi làm tiếp
2)
a)\(\frac{5}{6}-x=-\frac{5}{12}-\frac{1}{-4}=-\frac{5}{12}+\frac{1}{4}=-\frac{5}{12}+\frac{3}{12}=-\frac{1}{6}.\)
\(x=\frac{5}{6}--\frac{1}{6}=\frac{5}{6}+\frac{1}{6}=1\)
b)\(\frac{x-2}{-5}=\frac{6}{7}\)
\(\frac{\left(x-2\right)\left(-7\right)}{35}=\frac{30}{35}\)
\(\Rightarrow\left(x-2\right)\left(-7\right)=30\)
c)\(\frac{1}{2}x-\frac{3}{4}x=-\frac{5}{6}\)
\(\left(\frac{1}{2}-\frac{3}{4}\right)x=-\frac{5}{6}\)
\(-\frac{1}{4}x=-\frac{5}{6}\)
\(x=\frac{20}{6}=\frac{10}{3}\)
vậy \(x=\frac{10}{3}\)
Tìm x biết:
a) 7x.(2x - 3) - (4x2 - 9) = 0
b) (2x - 7).(x - 2).(x2 - 4) = 0
c) (9x2 - 25) - (6x - 10) = 0
a) \(7x\left(2x-3\right)-\left(4x^2-9\right)=0\Rightarrow7x\left(2x-3\right)-\left(2x-3\right)\left(2x+3\right)=0\Rightarrow\left(2x-3\right)\left(7x-2x+3\right)=0\Rightarrow\left[{}\begin{matrix}2x-3=0\\5x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{5}\end{matrix}\right.\)
b) \(\left(2x-7\right).\left(x-2\right)\left(x^2-4\right)=0\Rightarrow\left(2x-7\right)\left(x-2\right)^2\left(x+2\right)=0\Rightarrow\left[{}\begin{matrix}2x-7=0\\\left(x-2\right)^2=0\\x+2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=2\\x=-2\end{matrix}\right.\)
c)\(\left(9x^2-25\right)-\left(6x-10\right)=0\Rightarrow\left(3x-5\right)\left(3x+5\right)-2\left(3x-5\right)=0\Rightarrow\left(3x-5\right)\left(3x+5-2\right)=0\Rightarrow\left[{}\begin{matrix}3x-5=0\\3x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=1\end{matrix}\right.\)
a: Ta có: \(7x\left(2x-3\right)-\left(4x^2-9\right)=0\)
\(\Leftrightarrow7x\left(2x-3\right)-\left(2x-3\right)\left(2x+3\right)=0\)
\(\Leftrightarrow\left(2x-3\right)\left(5x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{3}{5}\end{matrix}\right.\)
b: Ta có: \(\left(2x-7\right)\left(x-2\right)\left(x^2-4\right)=0\)
\(\Leftrightarrow\left(2x-7\right)\left(x-2\right)^2\cdot\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=2\\x=-2\end{matrix}\right.\)
c: Ta có: \(\left(9x^2-25\right)-\left(6x-10\right)=0\)
\(\Leftrightarrow\left(3x-5\right)\left(3x+5-2\right)=0\)
\(\Leftrightarrow\left(3x-5\right)\left(3x+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=-1\end{matrix}\right.\)
Bài 1 tìm x biết
a> x=7/25+-1/5
b> x=5/11+4/-9
c> x/3=2/3+-1/7
d> x/5=5/6+-19/30
e> x/6=3/2+-7/15
Bài 2 cộng các phân số sau
a> -650/1430+588/686
b> 2004/2010+8/-670
Bài 3 tìm x biết
a> -5/13+-4/13 < x/13 < 2/13+-7/13
b> 3/2+-1/3 <x/6 < 1/9+31/18
c> -5/19+3/19 < x/19 bé hơn hoặc bằng 13/19+-11/19
d> -7/8+5/6 bé hơn hoặc bằng x/24 bé hơn hoặc bằng 5/8+-5/12
Bài 1 :
\(a)x=\frac{7}{25}+\left(-\frac{1}{5}\right)\)
\(x=\frac{2}{25}\)
\(b)x=\frac{5}{11}+\left(\frac{4}{-9}\right)\)
\(x=\frac{1}{99}\)
Mấy câu kia dễ tự làm :>
tính nhanh
a, 2/4+-3/4+15/9+1/9+3/4+7/-10
b, 5/19+-7/15+-19/37+18/-37+14/19+8/15
tìm số nguyên x,biết
-1/8+1/3+(-1)<=x/4,=5/12=-1/6
chiều mik cần gấp òi
Bài 1: Tính
a) (5^19 : 5^17 + 3) : 7
b) 7^9 : 7^7 - 3^2 + 2^3 . 5^2
c) 1200 : 2 + 6^2 . 2^1 + 18
d) 5^9 . 5^7 + 12 . 3 + 7^0
Bài 2: Tìm x
a) 200 - (2x + 6) = 4^3
b) 2x - 7^2 = 5 - 3^2
c)4 . (x + 41) = 2^2 . 10^2
d) 3^x+2 = 9
Bài 3: Tìm * thích hợp để 199* chia hết cho 2 và 3
a) (519:517+3):7
=(52+3):7
=(25+3):7
=28:7
=4
b) 79:77–32+23.52
=72–9+8.25
=49–9+8.25
=48+200
=248
c) 1200:2+62.21+18
=600+36.2+18
=600+72+18
=690
d) 59.57+12.3+70
=516+36+1
=516+37
=...
2.
a) 200–(2x+6)=43
200–(2x+6)=64
2x+6=200–64
2x+6=136
2x=136–6
2x=130
x=130:2
x=65
b) 2x—72=5–32
2x—49=5–9
2x—49=—4
2x=-4+49
2x=45
x=45:2
x=22,5
c) 4.(x+41)=22.102
.......
3.
Ta có: Để 199* chia hết cho 2
Thì 199* là số chẵn
==> * € {0;2;4;6;8}
Do đó: 199*=1990;1992;1994;1996;1998
Mà 199* chia hết cho 3
Nên 199*€{1992;1998}
Vậy các số cần tìm là 1992;1998
Bài tìm x biết
a) x/5 = 5/6+ -19/30
b)x-4 1/5=-2/3
c) 3 1/5-x=1 1/3+7/10
d) 9/x=2/5+-7/20
a)\(\frac{X}{5}=\frac{5}{6}+\frac{-19}{30}\)
\(\frac{X}{5}=\frac{1}{5}\)
Vậy \(X=1\)
b)\(X-\frac{41}{5}=\frac{-2}{3}\)
\(X=\frac{-2}{3}+\frac{41}{5}\)
\(X=\frac{113}{15}\)
Vậy \(X=\frac{113}{15}\)
c)\(\frac{31}{5}-X=\frac{11}{3}+\frac{7}{10}\)
\(\frac{31}{5}-X=\frac{131}{30}\)
\(X=\frac{31}{5}-\frac{131}{30}\)
\(X=\frac{11}{6}\)
Vậy \(X=\frac{11}{6}\)
d)\(\frac{9}{X}=\frac{2}{5}+\frac{-7}{20}\)
\(\frac{9}{X}=\frac{1}{20}\)
\(X=9:\frac{1}{20}\)
\(X=180\)
Vậy \(X=180\)
Hc tốt
Bài 1:Tìm x
a) 5x+x=39-3^11:3^9
b) 7x-x=5^21:5^19+3.2^2-7^0
c) 7x-2x =6^17:6^15+44:11
Bài 1: Thực hiện phép tính
a, (-1/2)^4 - |-2/3| + 2016^0
b, (2/3 - 5/7) (2/7 + 5/21 -1)
c, 6^3 . 27/2^4 . 3^6
Bài 2: chứng minh rằng
A= 3/1^2. 2^2 + 5/2^2 . 3^2 + 7/3^2 . 4^2 + ... + 19/9^2 . 10^2 < 1
Bài 3: tìm x biết
a, -1/2x - 3/5 = -4/5
b, 1-5x/2 = 7x+ 3/9
c, (2x-1)^5 = 243
d, (x+1)^2016 = 1
Bài 1: Thực hiện phép tính
a, (-1/2)^4 - |-2/3| + 2016^0=1/16-2/3+1
=19/48
b, (2/3 - 5/7) (2/7 + 5/21 -1)=-1/21.-10/21
=-11/21