1) \(2^3\times x-5^2\times x=2\times\left(5^2+2^2\right)-33\)

\(x\times\left(2^3-5^2\right)=2\times\left(25+4\right)-33\)

\(x\times\left(8-25\right)=2\times29-33\)

\(x\times-17=25\)

\(x=-\dfrac{25}{17}\)

2) \(15\div\left(x+2\right)=\left(3^3+3\right)\div1\)

\(15\div\left(x+2\right)=\left(27+3\right)\div1\)

\(15\div\left(x+2\right)=30\div1\)

\(15\div\left(x+2\right)=30\)

\(x+2=\dfrac{1}{2}\)

\(x=-\dfrac{3}{2}\)

3) \(20\div\left(x+1\right)=\left(5^2+1\right)\div13\)

\(20\div\left(x+1\right)=\left(25+1\right)\div13\)

\(20\div\left(x+1\right)=26\div13\)

\(20\div\left(x+1\right)=2\)

\(x+1=20\div2\)

\(x+1=10\)

\(x=9\)

4) \(320\div\left(x-1\right)=\left(5^3-5^2\right)\div4+15\)

\(320\div\left(x-1\right)=\left(125-25\right)\div4+15\)

\(320\div\left(x-1\right)=100\div4+15\)

\(320\div\left(x-1\right)=25+15\)

\(320\div\left(x-1\right)=40\)

\(x-1=8\)

\(x=9\)

5) \(240\div\left(x-5\right)=2^2\times5^2-20\)

\(240\div\left(x-5\right)=4\times25-20\)

\(240\div\left(x-5\right)=100-20\)

\(240\div\left(x-5\right)=80\)

\(x-5=30\)

\(x=35\)

6) \(70\div\left(x-3\right)=\left(3^4-1\right)\div4-10\)

\(70\div\left(x-3\right)=\left(81-1\right)\div4-10\)

\(70\div\left(x-3\right)=80\div4-10\)

\(70\div\left(x-3\right)=20-10\)

\(70\div\left(x-3\right)=10\)

\(x-3=7\)

\(x=10\)

a) 2 + 4 + 6 + ... + x = 240

số số hạng : ( x - 2 ) : 2 + 1 = x : 2 ( số )

tổng : ( x + 2 ) . x : 2 = 240

        ( x + 2 ) . x = 240 x 2

       ( x + 2 ) . x = 480

Mà .... ( đề sai )

b) 1 + 2 + 3 + ... + x = 306

số số hạng : ( x - 1 ) : 1 + 1 = x ( số )

tổng : ( x + 1 ) . x : 2 = 306

( x + 1 ) . x = 306 . 2

( x + 1 ) . x = 612

Mà .... ( đề sai )

Ban kia lam dung roi do

k tui nha

thanks

Đéo biếttttttttttt

\(\left(x\times1\right)+\left(x\times2\right)+\left(x\times3\right)+....+\left(x\times10\right)=240\)

\(\left(x\times x\times x\times....\times x\right)\times\left(1+2+3+...+10\right)=240\)

\(1x\times\frac{\left(10+1\right).10}{2}=240\)

\(1x\times55=240\)

\(1x=240\div55\)

\(1x=\frac{48}{11}\)

\(\Rightarrow x=\frac{48}{11}\)

\(1,x.34-x.10=240\)

\(\Rightarrow x.\left(34-10\right)=240\)

\(\Rightarrow x.24=240\)

\(\Rightarrow x=240:24=10\)

\(2,4^{x+1}=16\)

\(\Rightarrow4^{x+1}=4^2\)

\(\Rightarrow x+1=2\Rightarrow x=1\)

\(3,\left(x+1\right)^3=27=3^3\)

\(\Rightarrow x+1=3\Rightarrow x=2\)

 1.x=10 nha bạn

 2.x=1 nha

3.x=2 đó

Ta có : \(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right).......\left(1-\frac{1}{100}\right)\)

\(=\frac{1}{2}\frac{2}{3}.\frac{3}{4}.......\frac{99}{100}\)

\(=\frac{1}{100}\)

1)240x15-80x6x3-60x4

=240x15-80x3x6-240x1

=240x15-240x6-240x1

=240x(15-6-1)

=240x8

=1920

2)150x5x3x6-15x11

150x5x6x3-15x10-150x0,2

=150x5x6x3-150x1-150x0,2

=150x(5+6+3-1-0,2)

=150x12,8

=1980

cho mình kết bạn với

240-[23+(13+24.3-x)]=132

240-[23+(13+168-x)]=132

240-[23+(181-x)]=132

|

x-8:4-(46-23.2+6.3)=0

\(x-8:4-\left(46-23.2+6.3\right)=0\)

\(x-2-\left(46-46+18\right)=0\)

\(x-2-18=0\)

\(x-2=0+18\)

\(x-2=18\)

\(x=18+2\)

\(x=20\)

\(240-\left[23+\left(13+24.3-x\right)\right]=132\)

\(240\left[23+\left(13+82-x\right)\right]=132\)

\(23+\left(95-x\right)=132:240\)

\(23+\left(95-x\right)=\frac{132}{240}=\frac{11}{30}\)

\(23+\left(95-x\right)=\frac{11}{30}\)

\(95-x=\frac{11}{30}-23\)

\(95-x=\frac{11}{30}-\frac{690}{30}\)

\(95-x=-\frac{679}{30}\)

\(x=95+\frac{679}{30}\)

\(x=\frac{2850}{30}+\frac{679}{30}\)

\(x=\frac{3529}{30}=\)tự rút gọn ( nếu có thể )

Bài này số to, mũ to nên UCT khá mệt:

Lấy pt (1) - 8 lần pt (2) ta được:

\(\left(x-2\right)^4=\left(y-4\right)^4\Rightarrow\left[{}\begin{matrix}y=x+2\\y=6-x\end{matrix}\right.\)