\(\frac{4}{7}x-x=\frac{-4}{49}\)
Những câu hỏi liên quan
\(x^2+7x+13=x^2+2.x.\frac{7}{2}+\frac{49}{4}-\frac{49}{4}+13\)
\(=\left(x+\frac{7}{2}\right)^2+\frac{3}{4}\)
Vì \(\left(x+\frac{7}{2}\right)^2\ge0;\forall x\)
\(\Rightarrow\left(x+\frac{7}{2}\right)^2+\frac{3}{4}\ge\frac{3}{4}>0;\forall x\)
\(\Rightarrow x^2+7x+13>0\left(đpcm\right)\)
Tìm x
\(\frac{4-x}{6-x}=\frac{x-3}{x-8}\)
Rút gọn
\(\frac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)
Tìm x:
\(\dfrac{4-x}{6-x}\)=\(\dfrac{x-3}{x-8}\)\(\Rightarrow\)(4-x)(x-8)=(6-x)(x-3)
\(\Rightarrow\)12x-x2-32=9x-x2-18
\(\Rightarrow\)3x=14\(\Rightarrow\)x=\(\dfrac{14}{3}\).
\(\dfrac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{48}}\)
=\(\dfrac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{48}}\)
=\(\dfrac{7^{48}.5^{30}.2^8.\left(1-7.2^2\right)}{5^{29}.2^8.7^{48}}\)
=5.(1-7.22) = 5.(1-28) = 5.(-27) = -135
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Tìm x, biết :
a, \(60\%x+0,4x+x:3=2\)
b, \(\left|2x-5\right|-7=\left(\frac{1}{49}-\frac{1}{3^2}\right)\left(\frac{1}{49}-\frac{1}{4^2}\right)...\left(\frac{1}{49}-\frac{1}{2015^2}\right)\)
c, \(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+...+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
a. 60%x + 0,4x + x : 3 = 2
0.6x + 0,4x + x : 3 = 2
x(0,6 + 0,4 : 3 ) = 2
\(x.\frac{1}{3}=2=>x=2:\frac{1}{3}=\frac{1}{6}\)
câu B tự làm nha .
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Tính các tổng sau:Cfrac{5}{7}.frac{5}{11}+frac{5}{7}.frac{2}{11}-frac{5}{7}.frac{14}{11}Tìm xx-frac{3}{10}frac{5}{7}x+frac{3}{22}frac{27}{121}.frac{11}{9}frac{8}{23}.frac{46}{24}-xfrac{1}{3}1-xfrac{49}{65}.frac{5}{7}x+frac{4}{5.9}+frac{4}{9.13}+frac{4}{13.17}+...+frac{4}{41.45}frac{-37}{45}
Đọc tiếp
Tính các tổng sau:
\(C=\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
Tìm x
\(x-\frac{3}{10}=\frac{5}{7}\)
\(x+\frac{3}{22}=\frac{27}{121}.\frac{11}{9}\)
\(\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\)
\(1-x=\frac{49}{65}.\frac{5}{7}\)
\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=\frac{-37}{45}\)
1, Tính tổng:
\(C=\frac{5}{7}\cdot\frac{5}{11}+\frac{5}{7}\cdot\frac{2}{11}-\frac{5}{7}\cdot\frac{14}{11}\)
\(=\frac{5}{7}\cdot\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)=\frac{5}{7}\cdot\frac{-7}{11}=\frac{-5}{11}\)
2, Tìm x:
\(x+\frac{5}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+...+\frac{4}{41\cdot45}=\frac{-37}{45}\)
\(\Rightarrow x+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+...+\frac{1}{41}-\frac{1}{45}=\frac{-37}{45}\)
\(\Rightarrow x+\frac{1}{5}-\frac{1}{45}=\frac{-37}{45}\Rightarrow x+\frac{9}{45}-\frac{1}{45}=\frac{-37}{45}\)
\(\Rightarrow x+\frac{8}{45}=\frac{-37}{45}\Rightarrow x=\frac{-37}{45}-\frac{8}{45}=\frac{-45}{45}=-1\)
- Các bài tìm x còn lại bạn cứ theo trình tự thực hiện phép tính mà làm nhé!
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\(C=\frac{5}{7}\cdot\frac{5}{11}+\frac{5}{7}\cdot\frac{2}{11}-\frac{5}{7}\cdot\frac{14}{11}\)
\(=\frac{5}{7}\cdot\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)\)
\(=\frac{5}{7}\cdot-\frac{7}{11}\)
\(=-\frac{5}{11}\)
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\(C=\frac{5}{7}.\frac{5}{11}+\frac{5}{7}.\frac{2}{11}-\frac{5}{7}.\frac{14}{11}\)
\(\Leftrightarrow C=\frac{5}{7}\left(\frac{5}{11}+\frac{2}{11}-\frac{14}{11}\right)\)
\(\Leftrightarrow C=\frac{5}{7}\times\frac{-7}{11}\)
\(\Leftrightarrow C=\frac{-35}{77}=\frac{-5}{11}\)
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Xem thêm câu trả lời
Rút gọn biểu thức:
A = \(\frac{1^4+4}{5^4+4}\)X \(\frac{5^4+4}{7^4+4}\)X \(\frac{9^4+4}{11^4+4}\)X .....X \(\frac{49^4+4}{51^4+4}\)
(X là dấu nhân )
b1: rút gọn biểu thức:
\(A=\frac{1-\frac{1}{\sqrt{49}}+\frac{1}{49}-\frac{1}{\left(7.\sqrt{7}\right)^2}}{\frac{\sqrt{64}}{2}-\frac{4}{7}+\left(\frac{2}{7}\right)^2-\frac{4}{343}}\)
b2: tìm x, y, z thỏa mãn:
\(\sqrt{\left(x-\sqrt{2}\right)^2}_{ }\)+ \(\sqrt{\left(y+\sqrt{2}\right)^2}^{ }\)+ |x+y+z| = 0
nhanh nhé, ai đúng mk t*** cho !!!
Tìm \(x,y,z\)biết : \(\frac{x}{7}=\frac{-y}{4}=-\frac{8}{z}=\frac{-28}{49}\)
\(\frac{x}{7}=\frac{-y}{4}=\frac{-8}{z}=\frac{-28}{49}\)
Cái này thì phải làm ngược từ phải sang trái =))
* \(\frac{-8}{z}=\frac{-28}{49}\Leftrightarrow-28z=-8\cdot49\Leftrightarrow-28z=-392\Leftrightarrow z=14\)
* \(\frac{-y}{4}=\frac{-8}{14}\Leftrightarrow-14y=-8\cdot4\Leftrightarrow-14y=-32\Leftrightarrow y=\frac{16}{7}\)
* \(\frac{x}{7}=\frac{-\frac{16}{7}}{4}\Leftrightarrow4x=-\frac{16}{7}\cdot7\Leftrightarrow4x=-16\Leftrightarrow x=-4\)
\(\frac{x}{7}=\frac{-y}{4}=\frac{-8}{z}=\frac{-28}{49}\)
\(\Rightarrow\frac{x}{7}=\frac{-28}{49};\frac{-y}{4}=\frac{-28}{49};\frac{-8}{z}=\frac{-28}{49}\)
+)\(\frac{x}{7}=\frac{-28}{49}\Rightarrow49x=\left(-28\right).7\Rightarrow49x=-196\Rightarrow x=\frac{-196}{49}=-4\)
+)\(\frac{-y}{4}=\frac{-28}{49}\Rightarrow-49y=\left(-28\right).4\Rightarrow-49y=-112\Rightarrow y=\frac{-112}{49}\)
+)\(\frac{-8}{z}=\frac{-28}{49}\Rightarrow-28z=49.\left(-8\right)\Rightarrow-28z=-392\Rightarrow z=\frac{-392}{-28}=14\)
Vậy x=-4;y=\(\frac{-112}{49}\);z=14
Chúc bạn học tốt
1)\(\frac{4}{7}:\frac{-15}{28}x\left(-3\right)^2\) 2)\(\frac{15}{49}x1,4-\left(\frac{2}{3}+\frac{4}{5}\right);\frac{22}{10}\) 3)\(\frac{1}{4}-\frac{7}{4}:\left(-7\right)-3:\frac{3}{4}x\left(-2\right)^{^2}\)
4)\(\frac{5}{1x3}+\frac{5}{3x5}+\frac{5}{5x7}+....\frac{5}{197x199}\)
ok ai giải được giúp mik nha chiều mai mik phải nộp rồi
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27 tháng 2 2019 lúc 22:36
\(\frac{x}{3}+\frac{3}{x}+\frac{x}{4}+\frac{4}{x}=\frac{49}{12}\)
\(\frac{x}{3}+\frac{3}{x}+\frac{x}{4}+\frac{4}{x}=\frac{49}{12}\)
\(\Leftrightarrow\frac{x}{3}+\frac{x}{4}+\frac{7}{x}=\frac{49}{12}\)
\(\Leftrightarrow\frac{7x^2+84}{12x}=\frac{49}{12}\)
\(\Leftrightarrow84x^2+1008=588x\)
\(\Leftrightarrow84x^2-588x+1008=0\)
\(\Leftrightarrow84\left(x^2-7x+12\right)=0\)
\(\Leftrightarrow84\left(x-4\right)\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\x-3=0\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=4\\x=3\end{cases}}\)
N0 pt là:S={3;4}
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