( 11 x 9 - 100 +1 ) x ( 1 x 2 x ... x10 ) = (99 + 1 - 100) x 1 x 2 x .... x 10

                                                             =  0 x 1 x 2 x ....... x 10

                                                             = 0

Ta có 

(11x9 -100+1)x (1x2x3x..x100)

= 0x ( 1x2x3x..x100)

=0

Minh lon la nhan 10 moi dung

Vào câu hỏi tương tự

a, (100 + 121 + 144) : ( 169 + 196 )

= 365 : 365

= 1

Các anh các cj giúp em nhé 
Em cảm ơn trước

Giải:

a) \(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)\) 

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}\) 

\(=\dfrac{1.2.3.4}{2.3.4.5}\) 

\(=\dfrac{1}{5}\) 

b) \(\left(1-\dfrac{3}{4}\right).\left(1-\dfrac{3}{7}\right).\left(1-\dfrac{3}{10}\right).\left(1-\dfrac{3}{13}\right).....\left(1-\dfrac{3}{97}\right).\left(1-\dfrac{3}{100}\right)\) 

\(=\dfrac{1}{4}.\dfrac{4}{7}.\dfrac{7}{10}.\dfrac{10}{13}.....\dfrac{94}{97}.\dfrac{97}{100}\) 

\(=\dfrac{1.4.7.10.....94.97}{4.7.10.13.....97.100}\) 

\(=\dfrac{1}{100}\) 

Chúc bạn học tốt!

A)

\(\left(1-\dfrac{1}{2}\right)x\left(1-\dfrac{1}{3}\right)x\left(1-\dfrac{1}{4}\right)x\left(1-\dfrac{1}{5}\right)\)

\(=\dfrac{1}{2}x\dfrac{1}{3}x\dfrac{1}{4}x\dfrac{1}{5}\)

\(=\dfrac{1x2x3x4}{2x3x4x5}\)

\(=\dfrac{1}{5}\)

B)

\(\left(1-\dfrac{3}{4}\right).\left(1-\dfrac{3}{7}\right).\left(1-\dfrac{3}{10}\right)......\left(1-\dfrac{3}{97}\right).\left(1-\dfrac{3}{100}\right)\)

\(\dfrac{1}{4}.\dfrac{1}{7}.....\dfrac{94}{97}.\dfrac{97}{100}\)

\(\dfrac{1}{100}\)

học tốt nhé!!!

        = 12/11

Thanks bạn!

b)

\(1+5+9+13+...+x=5050\)           

\(\Rightarrow1+\left(2+3\right)+\left(4+5\right)+\left(6+7\right)+...+\left(a+a+1\right)=5050\)

                             Có a+1 số hạng

\(\Rightarrow\left(a+1+1\right)\left(a+1\right)\div2=5050\)

\(\Rightarrow\left(a+2\right)\left(a+1\right)\div2=5050\)

\(\Rightarrow\left(a+2\right)\left(a+1\right)=5050.2\)

\(\Rightarrow\left(a+2\right)\left(a+1\right)=10100\)

\(\Rightarrow\left(a+2\right)\left(a+1\right)=101.100\)

\(\Rightarrow a+1=100\)

\(\Rightarrow a=99\)

\(\Rightarrow x=99+100\)

\(\Rightarrow x=199\)

Vậy \(x=199\)

a) x = 13 hoặc x = -11 . 

b) x = 199 . 

Mk làm được ý b trước khi bạn trả lời rồi , còn ý a nữa giúp mk nhé

B1

(x+2/10¹⁰)+(x+2/11¹¹)=(x+2/12¹²)+(x+2/13¹³)

=>(x+2/10¹⁰)+(x+2/11¹¹)-(x+2/12¹²)-(x-2/13¹³)=0

(x+2).[(1/10¹⁰)+(1/11¹¹)-(1/12¹²)-(1/13¹³)]

Vì [(1/10¹⁰)+(1/11¹¹)-(1/12¹²)-(1/13¹³) khác 0

=>x+2=0

=>x=-2

toán nâng cao ak

thui mk dốt toán lém

Bài 2.

ab=7

ac=5

bc=35

=>(abc)²=5.7.35

=>abc=-35(vì a,b,c là các số âm nên tích âm)

Mọi người ơi, giúp em với ạ

a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)

=\(9^4.13:9^3=13.9=117\)

b) 100-(75-25)=100-50=50

\(a,\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)

\(< =>\left(8\cdot6561+729\cdot45\right):\left(81\cdot10-81\right)\)

\(< =>\left(52488+32805\right):\left(810-81\right)\)

\(< =>85293:729\)

\(< =>117\)

\(b,100-\left[75-\left(7-2\right)^2\right]\)

\(< =>100-\left[75-\left(5\right)^2\right]\)

\(< =>100-\left[75-25\right]\)

\(< =>100-50\)

\(< =>50\)

\(c,\left(20\cdot2^4+12\cdot2^4\right)-\left(48\cdot2^2\right):8^2\)

\(< =>\left[2^4\cdot\left(20+12\right)\right]-\cdot\left(48\cdot4\right):8^2\)

\(< =>\left[2^4\cdot32\right]-192:8^2\)

\(< =>\left[16\cdot32\right]-192:64\)

\(< =>512-3\)

\(< =>509\)