Tính:
a) 930 + 1023 - 192
b) 8291 + \(\left(-\frac{2}{9}\right)\)- 98
c) -291 + 910 - 920
d) 819 + 9182 - 920
Ai lm đúng thì mk sẽ cho link Google Drive
Tìm x
a) 92x + 92 = 9292
b) 892 + x = 928
c) -192 + x = 921
d) 2030(x + 829) = 82937
e) 7283 - 8x = 3
f) 829 - x = 109
Ai lm đúng thì mk sẽ cho link Google Drive :>
a, 92x+92=9292
92x=9200
x=100
vậy...
b,892+x=928
x=36
vậy...
c,-192+x=921
x=1113
d,2030(x+829)=82937
x+829=82937/2030
x=82937/2030-829
e,7283-8x=3
8x=7280
x=910
f, 829-x=109
x=720
vậy ...........
tìm x
a) 92x + 92 = 9292
92x = 9200
x = 9200 : 92
x = 100
vậy x = 100
b) 892 + x = 928
x = 928 - 892
x = 36
vậy x = 36
c) -192 + x = 921
x = 921 -(-192)
x = 1113
vậy x = 1113
d) 2030 . ( x + 829 ) = 82937
x + 829 = 82937 : 2030
x + 829 = 82937/2030
x = 82937/2030 - 829
x = .....
e) 7283 - 8x = 3
8x = 7283 - 3
8x = 7280
x = 7280 : 8
x = 910
vậy x = 910
f) 829 - x = 109
x = 829 - 109
x = 720
vậy x = 720
k cho mk nha
Tính
a) 92019 + 9304 - 432
b) 504 + 204 - (-2940)
c) -20439 + 920349 . 3
d) 9230 + 920 - 897
e) 67 - 192 + 9284 . 93
f) 39020 : 20 + 10202
g) 9804 + 9103 - 902 : 2
h) 930 - 929 + 1 . 90129
i) 910 + 239 - 928
j) 2934 - 920
k) 10002 : 1000000 - 1
l) 1204 - 829
m) 2839 - 1029 + (-201)
n) 2019 - 2018 + 2019
o) [1029 - (-1029)] : 2
p) 1920 - 2091 + 102891
q) 2910 + 239 - 929
r) 10002 : 100000
s) 109 - 910201021
t) 819 - 919 + 100
u) 819 - 119 + 300
v) 9102 - 9120 + 19
w) 892 - 910 + 9919
x) 1928 + 9821
y) 2192 + 201 - 9182 + 9182192
z) 9182 - 9192
Zúp mk dzới nha ;>
Bài này easy mà =v máy tiính đâu =3
a)100891
b)3648
c)2740608
d)9253
e)863287
f)1042351
g)18456
h)90130
i)221
j)7370049881
k)0
l)207359171
m)1609
n)2020
o)1029
p)102720
q)2220
r)10
s)89798979
t)-10
u)1000
v)1
w)11721
x)11749
y)9175403
z)-10
k cho mk nha,ấn mỏi tay r
tính:A=\(\left(1-\frac{1}{1+2}\right)\cdot\left(1-\frac{1}{1+2+3}\right)\cdot\cdot\cdot\left(1-\frac{1}{1+2+3+...+2006}\right)\)
Mọi người giúp mk nha!
ai lam đúng và nhanh nhất mk sẽ tick cho(giải chi tiết)
THANKS.
\(a_{n-1}=\frac{1}{1+2+3+...+n}=\frac{2}{n\left(n+1\right)}\)=>\(1-a_{n-1}=1-\frac{2}{n\left(n+1\right)}=\frac{n\left(n+1\right)-2}{n\left(n+1\right)}=\frac{\left(n-1\right)\left(n+2\right)}{n\left(n+1\right)}\)
\(A=\left(1-\frac{2}{2.3}\right)\left(1-\frac{2}{3.4}\right)........\left(1-\frac{2}{2006.2007}\right)\)
\(=\left(\frac{1.4}{2.3}\right)\left(\frac{2.5}{3.4}\right)\left(\frac{3.6}{4.5}\right)........\left(\frac{2005.2008}{2006.2007}\right)\)\(=\frac{\left(1.2.3......2005\right)\left(4.5.6.....2008\right)}{\left(2.3.4.....2006\right)\left(3.4.5....2007\right)}=\frac{1.2008}{2006.3}=\frac{1004}{3009}\)
Tính nhanh:
\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7\cdot5^2\cdot2^9}\)
Giúp cái nka mấy bn!!!Lm xog giúp mk sẽ chp 5 tik nka!!!Thanks trước...
\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2.2^9}\)
=\(\frac{\left(\frac{2}{5}.5\right)^7+\left(\frac{9}{4}:\frac{3}{16}\right)^3}{2^7.5^2.2^9}\)
=\(\frac{2^7+\left(\frac{9}{4}.\frac{16}{3}\right)^3}{2^7.5^2.2^9}\)
=\(\frac{2^7+3^3.4^3}{2^7.5^2.2^9}\)
=\(\frac{2^7+3^3.2^6}{2^7.5^2.2^9}\)
=\(\frac{2^6.\left(27+2\right)}{2^6.5^2.2^{10}}\)
=\(\frac{29}{25600}\)
Đoạn \(\frac{2^6\cdot\left(27+2\right)}{2^6\cdot5^2\cdot2^{10}}\)là sai rồi bn ơi!!!
Bn phải lm như mục trên là:
\(\frac{2^6\left(2+3^3\right)}{2^7\left(5^2+2^2\right)}\)\(=\frac{2^6\cdot29}{2^7\cdot29}=\frac{1}{2}\)
Nhưng dù sao cx c.ơn bn vì đã giúp mk,mk sẽ cho bn 1 ths nka!!!
tính
1/\(\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{9}}{\left(\frac{1}{4}+\frac{1}{7}-\frac{-3}{35}\right).\left(-1\frac{1}{3}\right)}\)
2/\(\frac{0,6-\frac{1}{3}+\frac{3}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\)
các bn lm giúp mk vs!!!!
mk đang cần gấp lắm nha!!!!!!!!!
ai lm nhanh nhất đúng đủ trình bày khoa học mk tick cho !!!!!!!1
Tính:
a)\(\left( { - 3,5} \right).\left( {1\frac{3}{5}} \right);\) b) \(\frac{{ - 5}}{9}.\left( { - 2\frac{1}{2}} \right).\)
a)
\(\left( { - 3,5} \right).\left( {1\frac{3}{5}} \right) = \frac{{ - 7}}{2}.\frac{8}{5} = \frac{{ - 7.8}}{{2.5}} = \frac{{ - 7.4.2}}{{2.5}} = \frac{{ - 28}}{5}\)
b) \(\frac{{ - 5}}{9}.\left( { - 2\frac{1}{2}} \right) = \frac{{ - 5}}{9}.\frac{{ - 5}}{2} = \frac{{25}}{{18}}\)
Tính:
a)\(\frac{2}{{15}} + \left( {\frac{{ - 5}}{{24}}} \right)\)
b) \(\left( {\frac{{ - 5}}{9}} \right) - \left( { - \frac{7}{{27}}} \right);\)
c)\(\left( { - \frac{7}{{12}}} \right) + 0,75\)
d)\(\left( {\frac{{ - 5}}{9}} \right) - 1,25\)
e)\(0,34.\frac{{ - 5}}{{17}}\)
g) \(\frac{4}{9}:\left( { - \frac{8}{{15}}} \right);\)
h)\(\left( {1\frac{2}{3}} \right):\left( {2\frac{1}{2}} \right)\)
i) \(\frac{2}{5}.\left( { - 1.25} \right)\)
k) \(\left( {\frac{{ - 3}}{5}} \right).\left( {\frac{{15}}{{ - 7}}} \right).3\frac{1}{9}\)
\(a)\frac{2}{{15}} + \left( {\frac{{ - 5}}{{24}}} \right) = \frac{{16}}{{120}} + \left( {\frac{{ - 25}}{{120}}} \right) = \frac{{ - 9}}{{120}} = \frac{{ - 3}}{{40}}\)
b) \(\left( {\frac{{ - 5}}{9}} \right) - \left( { - \frac{7}{{27}}} \right) = \left( {\frac{{ - 15}}{{27}}} \right) + \frac{7}{{27}} = \frac{{ - 8}}{{27}}\)
c)\(\left( { - \frac{7}{{12}}} \right) + 0,75 = \left( { - \frac{7}{{12}}} \right) + \frac{75}{100} \\= \left( { - \frac{7}{{12}}} \right) + \frac{3}{4} \\= \left( { - \frac{7}{{12}}} \right) + \frac{9}{{12}} = \frac{2}{{12}} = \frac{1}{6}\)
d)\(\left( {\frac{{ - 5}}{9}} \right) - 1,25 =\left( {\frac{{ - 5}}{9}} \right) - \frac{125}{100} = \left( {\frac{{ - 5}}{9}} \right) - \frac{5}{4}\\ = \left( {\frac{{ - 20}}{{36}}} \right) - \frac{{45}}{{36}} = \frac{{ - 65}}{{36}}\)
e)\(0,34.\frac{{ - 5}}{{17}} =\frac{{34}}{{100}}.\frac{{ - 5}}{{17}} = \frac{{17}}{{50}}.\frac{{ - 5}}{{17}} = \frac{{ - 1}}{{10}}\)
g) \(\frac{4}{9}:\left( { - \frac{8}{{15}}} \right) = \frac{4}{9}.\left( { - \frac{{15}}{8}} \right) = \frac{{ - 5}}{6}\)
h)\(\left( {1\frac{2}{3}} \right):\left( {2\frac{1}{2}} \right) = \frac{5}{3}:\frac{5}{2} = \frac{5}{3}.\frac{2}{5} = \frac{2}{3}\)
i) \(\frac{2}{5}.\left( { - 1,25} \right) = \frac{2}{5}.\frac{{ - 125}}{100} = \frac{2}{5}.\frac{{ - 5}}{4} = \frac{{ - 1}}{2}\)
k) \(\left( {\frac{{ - 3}}{5}} \right).\left( {\frac{{15}}{{ - 7}}} \right).3\frac{1}{9} = \left( {\frac{{ - 3}}{5}} \right).\left( {\frac{{15}}{{ - 7}}} \right).\frac{{28}}{9}\\ = \frac{{ - 3.3.5.7.4}}{{5.\left( { - 7} \right).3.3}} = 4\)
\(\left[\left(\frac{2}{1001}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1008}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)
giải hộ vs :((( tỉ mỉ nha !
Lm đúng mk tick cho
\(\left[\left(\frac{2}{1001}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1008}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)
\(=\left[\left(\frac{4}{2002}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{14}{2016}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)
\(=\left(\frac{1}{2002}.\frac{1001}{17}+\frac{33}{34}\right):\left(\frac{25}{2016}.\frac{1008}{25}+\frac{1009}{2016}\right)\)
\(=\left(\frac{1}{34}+\frac{33}{34}\right):\left(\frac{1}{2}+\frac{1009}{2016}\right)\)
\(=1:\frac{2017}{2016}\)
\(=\frac{2016}{2017}\)
Câu này bạn có thể áp dụng phương pháp phân phối để rút gọn các phân số cho dễ nhé. Còn bạn cũng có thể áp dụng cách quy đồng cũng ko sai. Sorry bn nhé mình đang bận nên ko trình bày rõ đc ạ
\(\left[\left(\frac{2}{1001}-\frac{3}{2002}\right).\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{1008}+\frac{11}{2016}\right).\frac{1008}{25}+\frac{1009}{2016}\right]\)
\(=\left[\frac{1001}{17}.\frac{2}{1001}-\frac{3}{2002}.\frac{1001}{17}+\frac{33}{34}\right]:\left[\left(\frac{1008}{25}.\frac{7}{1008}+\frac{1008}{25}.\frac{11}{2016}+\frac{1009}{2016}\right)\right]\)
\(=\left[\frac{2}{17}-\frac{3}{34}+\frac{33}{34}\right]:\left[\frac{7}{25}+\frac{11}{50}+\frac{1009}{2016}\right]\)
\(=\left[\frac{2}{17}+\frac{15}{17}\right]:\left[\frac{14}{50}+\frac{11}{50}+\frac{1009}{2016}\right]\)
\(=1:\left[\frac{1}{2}+\frac{1009}{2016}\right]\)
\(=1:\left[\frac{1008}{2016}+\frac{1009}{2016}\right]\)
\(=1:\frac{2017}{2016}\)
\(=\frac{2016}{2017}\)
Học tốt nha!!!
Tính:
a)\(A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right);\) b) \(B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\)
a)
\(\begin{array}{l}A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right)\\A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\frac{{ - 23}}{5}\\A = \frac{{5.\left( { - 3} \right).11.\left( { - 23} \right)}}{{11.23.5.5}}\\A = \frac{3}{5}\end{array}\)
b)
\(\begin{array}{l}B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\\B = \frac{{13}}{{25}}.\left( {\frac{{ - 7}}{9} - \frac{2}{9}} \right)\\B = \frac{{13}}{{25}}.(-1)\\B = \frac{{-13}}{{25}}.\end{array}\)