a)(1/16)²⁰⁰=(1²/16²)¹⁰⁰=(1/256)¹⁰⁰

(1/2)¹⁰⁰⁰=(1¹⁰/2¹⁰)¹⁰⁰=(1/1024)¹⁰⁰

vì 1/256>1/2014 nên (1/256)¹⁰⁰>(1/1024)¹⁰⁰

hay (1/16)²⁰⁰>(1/2)¹⁰⁰⁰

trieu dang làm đúng rồi đó các bạn **** cho trieu dang đi

Ta có: (1/16)^200 = (1/2)^800 < (1/2)^1000 ( do 1/2 = 1/2; 800 < 1000 )

Suy ra: (1/6) ^ 200 < ( 1/2)^ 1000

câu d thì dễ

Thế giúp vs bn ơi

mk bn lớp mấy

#)Giải :

Ta có : 18³⁹ > 16³⁹ = 2¹⁵⁶ > 2¹³⁵ = 32²⁷

            18³⁹ > 32²⁷ => (-18)³⁹ < (-32)²⁷

Vậy : (-18)³⁹ < (-32)²⁷

         #~Will~be~Pens~#

Trả lời : 

Ta có: 32²⁷=(2⁵)²⁷=2¹³⁵<2¹⁵⁶=2^4.39=16³⁹<18³⁹

=>(-32)²⁷>(-18)³⁹

Vậy (-32)²⁷>(-18)³⁹

\(\downarrow\)

Ta có \(32^{27}=\left(2^5\right)^{27}=2^{135}< 2^{136}=\left(2^4\right)^{39}=16^{39}< 18^{39}\)

\(\Rightarrow\left(-32\right)^{27}>\left(-18\right)^{39}\)

a, Có : (1/60)^200 = [(1/2)^4]^200 = (1/2)^800

Vì 0 < 1/2 < 1 nên (1/2)^800 > (1/2)^1000

=> (1/16)^200 > (1/2)^1000

Tk mk nha

a) \(\left(\frac{1}{16}\right)^{200}=\left(\frac{1}{2}\right)^{800}< \left(\frac{1}{2}\right)^{1000}\)

a) \(\left(\frac{1}{16}\right)^{200}=\frac{1}{16^{200}}\)

\(\left(\frac{1}{2}\right)^{1000}=\frac{1}{2^{1000}}\)

có : \(16^{200}=\left(2^4\right)^{200}=2^{800}\)

ta thấy \(2^{800}< 2^{1000}\)

\(\Rightarrow16^{200}< 2^{1000}\)

\(\Rightarrow\frac{1}{16^{200}}>\frac{1}{2^{1000}}\)

\(\Rightarrow\left(\frac{1}{16}\right)^{200}>\left(\frac{1}{2}\right)^{100}\)

a) Ta có \(0,625^{200}=\left(\dfrac{5}{8}\right)^{200}\) và \(0,5^{1000}=\left(\dfrac{1}{2}\right)^{1000}=\left(\dfrac{1}{2}\right)^{5.200}\) \(=\left[\left(\dfrac{1}{2}\right)^5\right]^{200}\) \(=\left(\dfrac{1}{32}\right)^{200}\). Mà hiển nhiên \(\left(\dfrac{5}{8}\right)^{200}>\left(\dfrac{1}{32}\right)^{200}\) nên suy ra \(0,625^{200}>0,5^{1000}\)

b) Ta thấy \(\left(-32\right)^{27}< 0\) trong khi \(\left(-27\right)^{32}>0\) nên đương nhiên \(\left(-32\right)^{27}< \left(-27\right)^{32}\)

c) Ta thấy \(-\dfrac{3}{2}>-2\) nên \(\left(-\dfrac{3}{2}\right)^5>\left(-2\right)^5\)

2¹⁵⁶=2^4*39=(2⁴)³⁹=16³⁹

Vì 18>16 nên 18³⁹>16³⁹ hay 18³⁹>2¹⁵⁶