Bạn ơi cả 3x-5  chia cho 12 hay chỉ có 5 chia cho 12 thui z ạ

\(\left(3x-\dfrac{5}{12}\right)^2-\dfrac{121}{64}=0\)

\(\left(3x-\dfrac{5}{12}\right)^2\) \(=0+\dfrac{121}{64}\)

\(3x-\dfrac{5}{12}\) \(=\sqrt{\dfrac{121}{64}}=\dfrac{11}{8}\)

\(3x\) \(=\dfrac{11}{8}+\dfrac{5}{12}=\dfrac{33+10}{24}=\dfrac{43}{24}\)

\(x\) \(\dfrac{3.43}{24}=\dfrac{43}{8}\)

a) x – 32 : 16 = 48 ó x – 2 = 48 ó x = 48 + 2 ó x = 50

b) 88 – 3.(7+x) = 64 ó 3.(7+x) = 88 – 64 ó 7 + x = 24:3 ó x = 8 – 7 ó x = 1

c) (5+4x) : 3 – 121 : 11 = 4 ó (5+4x) : 3 – 11 = 4 ó (5+4x) : 3 = 4 + 11 ó 5+4x = 15.3 ó 4x = 45 – 5 ó 4x = 40 ó x = 10

d) 15 – 2(3x+1) = 11.13 – 130 ó 15 – 2(3x+1) = 143 – 130 ó 15 – 2(3x+1) = 13

ó 2(3x+1) = 15 – 13 ó 3x + 1 = 2:2 ó 3x = 1 – 1 ó 3x = 0 ó x = 0

Lời giải:
a. $(x^2-9)(5x+15)=0$

$\Rightarrow x^2-9=0$ hoặc $5x+15=0$
Nếu $x^2-9=0$

$\Rightarrow x^2=9=3^2=(-3)^2$

$\Rightarrow x=3$ hoặc $-3$
Nếu $5x+15=0$

$\Rightarrow x=-3$
b.

$x^2-8x=0$
$\Rightarrow x(x-8)=0$

$\Rightarrow x=0$ hoặc $x-8=0$

$\Rightarrow x=0$ hoặc $x=8$

c. 

$5+12(x-1)^2=53$

$12(x-1)^2=53-5=48$

$(x-1)^2=48:12=4=2^2=(-2)^2$

$\Rightarrow x-1=2$ hoặc $x-2=-2$
$\Rightarrow x=3$ hoặc $x=0$

d.

$(x-5)^2=36=6^2=(-6)^2$
$\Rightarrow x-5=6$ hoặc $x-5=-6$

$\Rightarrow x=11$ hoặc $x=-1$

e.

$(3x-5)^3=64=4^3$

$\Rightarrow 3x-5=4$

$\Rightarrow 3x=9$

$\Rightarrow x=3$

f.

$4^{2x}+2^{4x+3}=144$
$2^{4x}+2^{4x}.8=144$

$2^{4x}(1+8)=144$

$2^{4x}.9=144$

$2^{4x}=144:9=16=2^4$

$\Rightarrow 4x=4\Rightarrow x=1$

(4x-12)(x³+64)=0

=> [_{x³+64=0=>x=4}^{x-12=0=>4x=12=>x=3}           olm bị lỗi nên em đừng có viết cách ra 1 quãng như kia nhé !

vậy x thuộc {3;4}

(3x-12)(x²-4)=0

=>[_{x²-4=0=>x²=4=>x=2 hoặc x=-2}^{3x-12=0=>3x=12=>x=4}

vậy x thuộc {4;2;-2}

(x+3)³:3-1=-10

(x+3)³:3=-9

(x+3)³=-9.3

=>(x+3)³=-27

=>x+3=-3

=>x=-6

(3x-1)³-2=-66

(3x-1)³=-64

(3x-1)³=-4³

=>3x-1=-4

=>3x=-3

=>x=-1

\(\left(4x-12\right)\left(x^3+64\right)=0\)

\(\Leftrightarrow4x-12=0\)

\(\Leftrightarrow4x=0+12\)

\(\Leftrightarrow4x=12\)

\(\Leftrightarrow x=12\div4\)

\(\Leftrightarrow x=3\)

\(\Leftrightarrow x^3+64=0\)

\(\Leftrightarrow x^3=0=64\)

\(\Leftrightarrow x^3=\left(-64\right)\)

\(\Leftrightarrow x^3=\left(-4\right)^3\)

\(\Leftrightarrow x=\left(-4\right)\)

\(\Rightarrow x\in\left\{-4;3\right\}\)

\(\Leftrightarrow\left(3x-12\right)\left(x^2-4\right)=0\)

\(\Leftrightarrow3x-12=0\)

\(\Leftrightarrow3x=0+12\)

\(\Leftrightarrow3x=12\)

\(\Leftrightarrow x=12\div3\)

\(x=4\)

\(\Leftrightarrow x^2-4=0\)

\(\Leftrightarrow x^2=0+4\)

\(\Leftrightarrow x^2=4\)

\(\Leftrightarrow x^2=2^2=\left(-2\right)^2\)

\(\Rightarrow x\in\left\{2;-2\right\}\)

\(\Rightarrow x\in\left\{-2;2;4\right\}\)

Các câu khác tương tự nhé !

a ) 18^2 : 9^2 .2^2 +12-12:3

= 4^2 :3 = 16/3

b) 5! +2^10 :2^8

= 120 + 4 = 124

c)28 :[ 117 - ( 117- 4) ] . 7 + 5^3 :125

= 28 : 4 * 7 + 1 = 50

d)3^3. 3^5.3 +2^7 :64

= 3^9 + 2^7 : 2^6 = 3^9 + 1 (tính nhé)

bài 2: tìm x thuôc N biết 

a) (2x -2^5). 5^3=2^3.5^3

2x - 2^5 = 2^3 

2x = 40 

x=20

b) 2^2x -4= 72:3^2

2^2 * x = 12 

x= 3

c)3^x + 3^x+1 =108

\(3^x+3^{x+1}=108\) (là thế này ak??)

3^x (1+3) = 108

3^x = 27

x=3 

d)(x -3).(3x+5) =0

\(\Rightarrow\orbr{\begin{cases}x-3=0\\3x+5\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-\frac{5}{3}\end{cases}}}\)

(x-1)⁵=1

(x-1)⁵=1⁵

x-1=1

x=1+1

x=2

(3x-1)²=121

(3x-1)²=11²

3x-1=11

3x=11+1

3x=12

x=12:3

x=4

4^2x+1=64

4^2x+1=4³

=>2x+1=3

=>2x=3-1

=>2x=2

=>x=2:2

=>x=1

(x-2)⁵=32

(x-2)⁵=2⁵

x-2=2

x=2+2

x=4