Tim x biet |2x-1|+|1-2x|=8
Tim so nguyen x biet : -x/2+2x/3+x+1/4+2x+1/6=3/8
12x/6 + 4x/6 - 3x/6 = 3/8 - 1/4 - 1/6
13x/6 = (9 - 6 - 4)/24 = -1/24
--> x = -1/52
Tim x, biet: I 2x-1 I + I 1-2x I = 8
\(\)tim x biet \(|2x-1|+|1-2x|=8\)
Ta có : | 2x - 1 | + | 1 - 2x | = 8
\(\Leftrightarrow\)| 2x - 1 | + | 2x - 1 | = 8
\(\Leftrightarrow\)2 . | 2x - 1 | = 8
\(\Leftrightarrow\)| 2x - 1 | = 4
\(\Rightarrow\)2x - 1 = 4 hoặc 2x - 1 = - 4
\(\Rightarrow\)x = 5 / 2 hoặc x = - 3 / 2
Vậy : x = 5 / 2 hoặc x = - 3 / 2
tim x biet (6x)^3:8=(2x-1)^3
Lời giải:
$(6x)^3:8=(2x-1)^3$
$\Rightarrow (\frac{6x}{2})^3=(2x-1)^3$
$\Rightarrow (3x)^3=(2x-1)^3$
$\Rightarrow 3x=2x-1$
$\Rightarrow x=-1$
a,tim x biet |x-2|+|3-2x|=2x+1
b,tim x,y thuoc Z biet xy+2x-y=5
c, tinh A=(1-1/15)(1-1/21)(1-1/28).....(1-1/210)
tim cap so x,y nguyen biet :
a,\(|2x+3|+|2x-1|=\frac{8}{2|x-5|+2}\)
tim x biet :
a) |x+1| +|x-5| = 7
b)|2x + 5|=3x-8
B, => 2x+5=3x-8
2x-3x=-8-5
-x=-13
=>x=13
hoặc 2x+5=-3x+8
2x+3x=8-5
5x=3
x=\(\frac{3}{5}\)
\(\left|x+1\right|+\left|x-5\right|=7.\)
\(Th1:x+1< 0;x-5< 0\)
\(x< -1;x< 5\Rightarrow x< -1\)
\(\left|x+1\right|+\left|x-5\right|=7\)
\(-\left(x+1\right)-\left(x-5\right)=7\)
\(-x-1-x+5=7\)
\(-2x+4=7\)
\(-2x=3\)
\(x=-1,5\left(tm\right)\)
\(Th2:x+1>0;x-5>0\)
\(x>-1;x>5\Rightarrow x>5\)
\(\left|x+1\right|+\left|x-5\right|=7\)
\(x+1+x-5=7\)
\(2x-4=7\)
\(2x=11\)
\(x=5,5\)\(\left(tm\right)\)
\(Th3:x+1\le0;x-5>0\)
\(x\le-1;x>5\)(không xảy ra)
\(Th4:x+1>0;x-5\le0\)
\(x>-1;x\le5\Rightarrow-1< x\le5\)
\(\left|x+1\right|+\left|x-5\right|=7\)
\(-\left(x+1\right)+x-5=7\)
\(-x-1+x-5=7\)( không xảy ra)
Vậy x = -1,5 hoặc x = 5,5
\(\)
\(\left|2x+5\right|=3x-8.\)
\(Th1:\)
\(2x+5=-\left(3x-8\right)\)
\(2x+5=-3x+8\)
\(2x+3x=8-5\)
\(5x=3\)
\(x=\frac{3}{5}\)
\(Th2:\)
\(2x+5=3x-8\)
\(2x-3x=-8-5\)
\(-x=-13\)
\(x=13\)
Vậy x = 13 hoặc x = \(\frac{3}{5}\)
tim x biet (2x+1)+(2x+2)+...+(2x+2015)
tim x biet (2x+1)+(2x+2)+...+(2x+2015)=0
Có 2015 số hạng
Tổng là (2x+1+2x+2015).2015:2=0
4x+2016=0
4x=-2016
x=-504
Ủng hộ mk nha
( 2x + 1 ) + ( 2x + 2 ) + ... + ( 2x + 2015 ) = 0
=> ( 2x + 2x + .. + 2x ) + ( 1 + 2 + ... + 2015 ) = 0
2015 số 2x
=> 2x . 2015 + 2031120 = 0
=> 2x . 2015 = 0 - 2031120
=> 2x . 2015 = - 2031120
=> 2x = ( - 2031120 ) : 2015
=> 2x = - 1008
=> x = ( - 1008 ) : 2
=> x = - 504
=> ( 2x + 2x + .... + 2x + 2x ) + ( 1 + 2 + 3 + .... + 2015 ) = 0
=> ( 2x.2015 ) + { [ 2015.( 2015 + 1 ] : 2 } = 0
=> 4030x + [ ( 2015 . 2016 ) : 2 ] = 0
=> 4030x + ( 4062240 : 2 ) = 0
=> 4030x + 2031120 = 0
=> 4030x = - 2031120
=> x = - 2031120 : 4030 = - 504
Vậy x = - 504