E = 1 + 2 - 3 - 4+ 5 - . . . + 2017 + 2018 - 2019 - 2020 + 2021
Những câu hỏi liên quan
a) 5+3.(-7)+4:(-2)
b)1-2-3+4+5-6-7+8.....+2017-2018-2019+2020+2021
Lời giải:
a.
$5+3(-7)+4:(-2)=5+(-21)+(-2)=5-(21+2)=5-23=-(23-5)=-18$
b.
$1-2-3+4+5-6-7+8+....+2017-2018-2019+2020+2021$
$=(1-2-3+4)+(5-6-7+8)+....+(2017-2018-2019+2020)+2021$
$=0+0+....+0+2021=2021$
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2+3-4+5+6-7+8+9-10+...+2015+2016-2017+2018+2019-2020+2021+2022
2021/2022 + 2020/2021 + 2019/2020 + 2018/2019 + 2017/2018 rôì so sánh với 5
A = 2021/2022+2020/2021+2019/2020+2018/2019+2017/2018
A<2022/2022+2021/2021+2020/2020+2019/2019+2018/2018
A<1+1+1+1+1
A<5
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Bài 1: Tính nhanh
A = 1 - 3 + 5 - 7+...- 2019 + 2021 - 2023
B = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 +...+ 2017 + 2018 + - 2019 - 2020
Help me :v
\(A=1-3+5-7+......-2019+2021-2023\)
\(A=\left(1-3\right)+\left(5-7\right)+....+\left(2021-2023\right)\)
\(A=-2+\left(-2\right)+....+\left(-2\right)\left(506 cặp\right)\)
\(A=-2.506\)
\(A=-1012\)
*) A=(1-3)+(5-7)+....+(2021-2023)
<=> A=-2+(-2)+...+(-2)
Dãy A có (2023-1):2+1=1012 số số hạng
=> Có 506 số (-2)
=> A=(-2).506=-1012
\(B=1+2-3-4+5+6-7-8+......+2017+2018-2019-2020\)
\(B=\left(1+2-3-4\right)+\left(5+6-7-8\right)+.....+\left(2017+2018-2019-2020\right)\)
\(B=-4+\left(-4\right)+.....+\left(-4\right)\left(505 cặp\right)\)
\(B=-4.505\)
\(B=-2020\)
a) A=2020-(2019+2020)+(1019-600)
b)B=48+/48-174/+(-74)
c)C=42019-42018-42017-...-4-1
d)D=2-5+8-11+...+2018-2021
a)1420
b)100
c) hỏi người khác í
d)-2022
CMR
\(\frac{1}{4040}< \left(\frac{1}{2}.\frac{3}{4}.\frac{5}{6}...\frac{2017}{2018}.\frac{2019}{2020}\right)^2< \frac{1}{2021}\)
chứng minh \
20182-1 chia hết cho 2017 và 2019
20203+1 chia hết cho 2021
20213-1 chia hết cho 2020
1+2-3-4+5+6-7-7+...+2018-2019-2020+2021
Sửa đề :
1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 - ... + 2018 - 2019 - 2020 + 2021
= 1 + ( 2 - 3 - 4 + 5 ) + ( 6 - 7 - 8 + 9 ) + ... + ( 2018 - 2019 - 2020 + 2021 )
= 1 + 0 + 0 + ... + 0
= 1
1-2-3+4+5-6-7+8+...+2018-2019-2020+2021+2022-2023
Sửa đề: 1-2-3+4+5-6-7+8+...-2018-2019+2020+2021-2022-2023
=(1-2-3+4)+(5-6-7+8)+...+(2017-2018-2019+2020)+(2021-2022-2023)
=0+0+...+0+(-1-2023)
=-2024
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