x/120=-7/24*-6/11

x/120=7/44

x=7*120:44

x=210/11

a) \(\frac{X}{2}-\frac{11}{5}=\frac{7}{8}\cdot\frac{64}{49}\)

\(\Rightarrow\frac{x}{2}-\frac{11}{5}=\frac{8}{7}\)

\(\Rightarrow\frac{x}{2}=\frac{8}{7}+\frac{11}{5}\)

\(\Rightarrow\frac{x}{2}=\frac{117}{35}\)\(\Rightarrow x=\frac{117}{35}\cdot2=\frac{234}{35}\)

b)\(\frac{x}{5}+\frac{9}{2}=\frac{6}{7}\cdot\frac{36}{49}\)

\(\Rightarrow\frac{x}{5}+\frac{9}{2}=\frac{216}{343}\)

\(\Rightarrow\frac{x}{5}=\frac{216}{343}-\frac{9}{2}=\frac{-2655}{686}\)

\(\Rightarrow x=\frac{-2655}{686}\cdot5=\frac{-13275}{686}\)

        x/2 - 11/5 = 7/8 . 64/49

        x/2 - 11/5 = 8/7

        x/2          =8/7 + 11/5

        x/2          = 117/35

        x             = 2.117/35 ( tính chất phân số bằng nhau)

        x             = 234/35 

       x/5 + 9/2 = 6/7 . 36/49

       x/5 + 9/2 = 216/343

        x/5         = 216/343 - 9/2

        x/5         = -2655/686

        x           = 5.(-2655)/686

        x           = -13275/686 

tui trả lời trước mà ko tk

x - (17 - x) = x - 7

x = x - 7 + 17 - x

x = (-7 + 17) + (x - x)

x = 10 + 0

x = 10

Vậy x = 10.

( 4,5 - 2.x ) . 11/7 = 11/14

4,5 - 2.x               = 11/14 : 11/7= 1/2

         2.x             =  4,5 - 1/2 =4

             x  = 4:2=2

\(\left(4,5-2x\right).1\frac{4}{7}=\frac{11}{14}\)

\(\Rightarrow\left(4,5-2x\right).\frac{11}{7}=\frac{11}{14}\)

\(\Rightarrow4,5-2x=\frac{11}{14}:\frac{11}{7}\)

\(\Rightarrow4,5-2x=\frac{11}{14}.\frac{7}{11}\)

\(\Rightarrow4,5-2x=\frac{1}{2}\)

\(\Rightarrow2x=4,5-\frac{1}{2}\)

\(\Rightarrow2x=4,5-0,5\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=4:2\)

\(\Rightarrow x=2\)

a, 11/12 - ( 2/5 + x ) = 2/3

<=> \(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}=\frac{1}{4}\)

=> x=\(\frac{1}{4}-\frac{11}{12}=-\frac{2}{3}\)

b, 2x . ( x - 1/7 ) = 0

<=>\(\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)<=> \(\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)

vậy x={\(0;\frac{1}{7}\)}

c, 3/4 + 1/4 : x = 2/5

<=>\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)

<=> \(x=\frac{1}{4}:\left(-\frac{7}{20}\right)=-\frac{5}{7}\)

vậy x=-5/7

a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\Leftrightarrow\frac{11}{12}-\frac{2}{5}-x=\frac{2}{3}\)

\(\Leftrightarrow-x=\frac{2}{3}-\frac{11}{12}+\frac{2}{5}=\frac{3}{20}\)

\(\Leftrightarrow x=-\frac{3}{20}\)

b) \(2x\left(x-\frac{1}{7}\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x-\frac{1}{7}=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0\\x=\frac{1}{7}\end{array}\right.\)

c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\Leftrightarrow\frac{1}{4x}=\frac{2}{5}-\frac{3}{4}=-\frac{7}{20}\)

\(\Leftrightarrow4x=\frac{-20}{7}\)

\(\Leftrightarrow x=-\frac{5}{7}\)

a) \(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{11}{12}-\frac{2}{3}\)

\(\frac{2}{5}+x=\frac{1}{4}\)

\(x=\frac{1}{4}-\frac{2}{5}\)

\(x=-\frac{3}{20}\)

Vậy \(x=-\frac{3}{20}\)

b) \(2x\left(x-\frac{1}{7}\right)=0\)

\(\Rightarrow\begin{cases}2x=0\\x-\frac{1}{7}=0\end{cases}\Rightarrow\begin{cases}x=0\\x=\frac{1}{7}\end{cases}\)

Vậy x = 0 hoặc \(x=\frac{1}{7}\)

c) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)

\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)

\(\frac{1}{4}:x=-\frac{7}{20}\)

\(x=\frac{1}{4}:\left(-\frac{7}{20}\right)\)

\(x=-\frac{5}{7}\)

Vậy \(x=-\frac{5}{7}\)

( x + 7 ) chia hết cho ( x + 1 )

Ta có : ( x + 7 ) = ( x + 1 ) + 6

                          Mà ( x + 1 ) + 6 chia hết cho x + 1 và x + 1 chia hết cho x + 1

                          => 6 phải chia hết cho x + 1

                          => x + 1 = { 1 ; 2 ; 3 ; 6 }

Nếu x + 1 = 1 thì x = 1 - 1 = 0 ( được )

Nếu x + 1 = 2 thì x = 2 - 1 = 1 ( được )

Nếu x + 1 = 3 thì x = 3 - 1 = 2 ( được )

Nếu x + 1 = 6 thì x = 6 - 1 = 5 ( được )

Vậy x = { 0 ; 1 ; 2 ; 5 }

x=7+1=8

á à thằng tuấn kiệt

Ai nhanh mk k

                                                 GIẢI:

  Theo đề bài ta có: (x+7) chia hết cho (x+4)

suy ra: [(x+4)+3] chia hết cho (x+4)

Vì (x+4) chia hết cho (x+4) nên 3 chia hết cho (x+4)

Do đó x+4 E Ư(3)={-1;1;3;-3}

x+4=-1 thì x=-5

x+4=1 thì x=-3

x+4=-3 thì x=-7

x+4=3 thì x=-1

Vậy.............................................

Ta có:

x + 7 = x + 4 + 3

Để (x + 7) ⋮ (x + 4) thì 3 ⋮ (x + 4)

⇒ x + 4 ∈ Ư(3) = {-3; -1; 1; 3}

⇒ x ∈ {-7; -5; -3; -1}