Tính nhanh
11/24-5/41+13/24+0,5-36/41
Những câu hỏi liên quan
11/24 - 5/41+13/24+0,5 - 36/41
Ta có : \(\frac{11}{24}+\frac{13}{24}-\frac{5}{41}-\frac{36}{41}+0,5\)
= \(\left(\frac{11}{24}+\frac{13}{24}\right)-\left(\frac{5}{41}+\frac{36}{41}\right)+0,5\)
= 1 - 1+0,5
= 0,5
Chúc bạn học tốt 
11/24 - 5/41+13/24+0,5 - 36/41
\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
\(=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)
\(=1+\left(-1\right)+0,5\)
\(=0,5=\frac{1}{2}\)
Mình làm đầy đủ nhé.
11/24-5/41+13/24+0,5-36/41
11/24 - 5/41 + 13/24 + 0,5 - 36/41
= 11/24 +13/24 -5/41 - 36/41 +0,5
= 24/24 - ( 5/41 + 36/41 ) + 0,5
= 1 - 1 + 0,5
= 0 +0,5
= 0,5
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11/24-5/41+13/24+0,5-36/41
ai giúp mình tính theo bước đi mình cần gấp!
\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
Bài làm:
Ta có: \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
\(=\left(\frac{11}{24}+\frac{13}{24}\right)-\left(\frac{5}{41}+\frac{36}{41}\right)+0,5\)
\(=1-1+\frac{1}{2}\)
\(=\frac{1}{2}\)
\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
\(=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(\frac{-5}{41}-\frac{36}{41}\right)+0,5\)
\(=1-1+0,5\)
\(=0,5\)
Học tốt
11/41-5/41+13/24+0,5-36/41
(11/24+13/24)-(5/41+36/41)-0,5
0-0-0,5
-0,5
Thực hiện phép tính (Tính hợp lý):
a)\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
b)\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
11/24-5/41+13/24+0.5-36/41
\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0.5-\frac{36}{41}\)
\(=\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+\frac{1}{2}-\frac{36}{41}\)
\(=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+\left(\frac{13}{24}+\frac{1}{2}\right)\)
\(=1+\left(-1\right)+\frac{23}{24}\)
\(=\frac{23}{24}\)
(Bài này lớp 4 mình đã học rồi, nói chi gì đến lớp 7!)
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11/24-5/41+13/24+0.5-36/41
=11/24-5/41+13/24+1/2-36/41
=(11/24+13/24)-(-5/41-36/41)+(13/24+1/2)
=1-1+23/24(ở đây mình làm tắt không ghi 1+(-1) vì hai cái đều bằng 0)
=23/24
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\(\frac{11}{24}\)- \(\frac{5}{41}\)+ \(\frac{13}{24}\)+ \(0,5\)- \(\frac{36}{41}\)
11/24-5/41+13/24+0,5-36/4
=11/24-5/41+13/24+1/2-36/4
=-625/82
kb mình nha
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Câu 1)1) dfrac{11}{24}−dfrac{5}{41}+dfrac{13}{24}+0,5−dfrac{36}{41}2)12÷left(dfrac{3}{4}-dfrac{5}{6}right)^23) (1+dfrac{2}{3}-dfrac{1}{4})left(0,8-dfrac{3}{4}right)^2 4)16dfrac{2}{7}÷(dfrac{-3}{5})+28dfrac{2}{7}÷dfrac{3}{5}5)left(2^2divdfrac{4}{3}-dfrac{1}{2}right)timesdfrac{6}{5}-176)left(dfrac{1}{3}right)^{50}timesleft(-9right)^{25}-dfrac{2}{3}div4
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Câu 1)
1) \(\dfrac{11}{24}\)−\(\dfrac{5}{41}\)+\(\dfrac{13}{24}\)+0,5−\(\dfrac{36}{41}\)=
2)12÷\(\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)=
3) (\(1+\dfrac{2}{3}-\dfrac{1}{4}\))\(\left(0,8-\dfrac{3}{4}\right)^2\) =
4)\(16\dfrac{2}{7}\)÷(\(\dfrac{-3}{5}\))+\(28\dfrac{2}{7}\)÷\(\dfrac{3}{5}\)
5)\(\left(2^2\div\dfrac{4}{3}-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
6)\(\left(\dfrac{1}{3}\right)^{50}\times\left(-9\right)^{25}-\dfrac{2}{3}\div4\)
1: \(\dfrac{11}{24}-\dfrac{5}{41}+\dfrac{13}{24}+0,5-\dfrac{36}{41}\)
\(=\left(\dfrac{11}{24}+\dfrac{13}{24}\right)-\left(\dfrac{5}{41}+\dfrac{36}{41}\right)+\dfrac{1}{2}\)
\(=1-1+\dfrac{1}{2}=\dfrac{1}{2}\)
2: \(12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
\(=12:\left(\dfrac{9}{12}-\dfrac{10}{12}\right)^2\)
\(=12:\left(-\dfrac{1}{12}\right)^2=12:\dfrac{1}{144}=12\cdot144=1368\)
3: \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)\cdot\left(0,8-\dfrac{3}{4}\right)^2\)
\(=\dfrac{12+8-3}{12}\cdot\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
\(=\dfrac{17}{12}\cdot\left(\dfrac{16-15}{20}\right)^2\)
\(=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{4800}\)
4: \(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\dfrac{5}{3}\cdot\left(-16-\dfrac{2}{7}\right)+\dfrac{5}{3}\cdot\left(28+\dfrac{2}{7}\right)\)
\(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\)
\(=12\cdot\dfrac{5}{3}=20\)
5: \(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\dfrac{5}{2}\cdot\dfrac{6}{5}-17=3-17=-14\)
6: \(\left(\dfrac{1}{3}\right)^{50}\cdot\left(-9\right)^{25}-\dfrac{2}{3}:4\)
\(=\left(\dfrac{1}{3}\right)^{50}\cdot\left(-1\right)\cdot3^{50}-\dfrac{2}{3\cdot4}\)
\(=-1-\dfrac{2}{12}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
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