\(\frac{27}{43}\). \(\frac{17}{29}\)-\(\frac{21}{41}\).\(\frac{1}{2}\)+\(\frac{9}{58}\): 1\(\frac{6}{37}\)- \(\frac{6}{29}\): 1\(\frac{20}{21}\)
Những câu hỏi liên quan
\(\frac{37}{43}\)\(\times\)\(\frac{17}{29}\)\(-\)\(\frac{21}{41}\)\(\times\)\(\frac{1}{2}+\frac{9}{58}\div\frac{16}{37}-\frac{6}{29}\div\frac{120}{21}\)
tích mình với
ai tích mình
mình tích lại
thanks
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tích mình đi
ai tích mình
mình ko tích lại đâu
thanks
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Tính:
a) \(\frac{-90}{189}+\frac{45}{84}-\frac{78}{126}\)
b) \(11\frac{7}{21}+8\frac{16}{24}-10\frac{21}{35}\)
c) \(\frac{37}{43}\cdot\frac{17}{29}-\frac{21}{41}\cdot\frac{1}{2}+\frac{9}{58}:1\frac{6}{37}-\frac{6}{2}:1\frac{29}{21}\)
d) \(\sqrt{\left(-5\right)^2}+\sqrt{5^2}-\sqrt{\left(-5\right)^2}-\sqrt{3^2}\)
a) -90/189 + 45/84 - 78/126
= -10/21 + 15/28 - 13/21
= (-10/21 - 13/21) + 15/28
= -24/21 + 15/28
= -17/28
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Tính:
A=\(\frac{-5}{12}+\frac{4}{37}+\frac{17}{12}-\frac{41}{37}\)
B=\(\frac{1}{2}-\frac{43}{101}+(\frac{-1}{3})-\frac{1}{6}\)
C=\(\frac{-5}{6}.\frac{12}{-7}.\frac{-21}{15}\)
\(A=\frac{-5}{12}+\frac{4}{37}+\frac{17}{12}-\frac{41}{37}=(\frac{-5}{12}+\frac{17}{12})+(\frac{4}{37}-\frac{41}{37})=\frac{12}{12}+\frac{-37}{37}=1+(-1)=0\)
\(B=\frac{1}{2}-\frac{43}{101}+\frac{-1}{3}-\frac{1}{6}=\frac{-43}{101}+(\frac{1}{2}+\frac{-1}{3}-\frac{1}{6})=\frac{-43}{101}+(\frac{3}{6}+\frac{-2}{6}-\frac{1}{6})=\frac{-43}{101}+0=\frac{-43}{101}\)
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\(A=\frac{-5}{12}+\frac{4}{37}+\frac{17}{12}-\frac{41}{37}.\)
\(A=\left(\frac{-5}{12}+\frac{17}{12}\right)-\left(\frac{41}{37}-\frac{4}{37}\right)\)
\(A=1-1=0\)
\(B=\frac{1}{2}-\frac{43}{101}+\left(\frac{-1}{3}\right)-\frac{1}{6}\)
\(B=\left(\frac{1}{2}+\left(\frac{-1}{3}\right)-\frac{1}{6}\right)-\frac{43}{101}\)
\(A=0-\frac{43}{101}=\frac{-43}{101}\)
\(C=\frac{-5}{6}\cdot\frac{12}{-7}\cdot-\frac{21}{15}\)
\(C=\frac{-5}{2.3}\cdot\frac{3.2.2}{-7}\cdot\frac{3.\left(-7\right)}{3.5}\)
\(C=\frac{-2}{1}=-2\)
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Tiếp:
\(C=\frac{-5}{6}.\frac{12}{-7}.\frac{-21}{15}=\frac{(-5).12.(-21)}{6.(-7).15}=\frac{1.2.3}{1.1.(-3)}=\frac{2}{-1}=-2\)
_Học tốt_
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\(\frac{-21+\frac{7}{17}-\frac{7}{29}+\frac{7}{2018}}{27-\frac{9}{17}+\frac{9}{29}-\frac{9}{2018}}-\frac{2}{9}\)
Tính giá trị biểu thức1.Afrac{1}{5}+frac{3}{17}-frac{4}{3}+left(frac{4}{5}-frac{3}{17}+frac{1}{3}right)-frac{1}{7}+left[frac{-14}{30}right]2.Bleft(frac{5}{8}-frac{4}{12}+frac{3}{2}right)-left(frac{5}{8}+frac{9}{13}right)-left[frac{-3}{2}right]+frac{7}{-15}3.Cfrac{5}{18}+frac{8}{19}-frac{7}{21}+left(frac{-10}{36}+frac{11}{19}+frac{1}{3}right)-frac{5}{8}4.Dfrac{1}{9}-left[frac{-5}{23}right]-left(frac{-5}{23}+frac{1}{9}+frac{25}{7}right)+frac{50}{14}-frac{7}{30}5.Efrac{1}{13}+left(frac{-5}{18}-frac...
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Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
Tính nhanh
1, \(10\frac{5}{4}-4\frac{9}{14}-6\frac{5}{7}+\frac{7}{3}\)
2, \(\frac{29}{32}\left(\frac{41}{36}-\frac{32}{58}\right)-\frac{41}{36}\left(\frac{29}{32}+\frac{18}{41}\right)\)
a,\(\frac{1}{2}-\left(\frac{-2}{5}\right)+\frac{1}{3}+\frac{5}{7}-\left(\frac{-1}{6}\right)+\frac{-4}{35}+\frac{1}{41}\)
b,\(0,75.\frac{3}{37}-\frac{3}{4}.\frac{29}{37}-\frac{15}{20}.\frac{11}{37}-0.25\)
a)\(\frac{-1}{2}+\frac{-1}{3}+\frac{-5}{4}\) b)\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\)
c)\(\frac{17}{7}+\frac{15}{4}-\frac{20}{4}+\frac{1}{4}-3\) d)\(\frac{29}{32}\left(\frac{41}{36}-\frac{32}{58}\right)-\frac{41}{36}\left(\frac{29}{32}+\frac{18}{41}\right)\)
a) \(\frac{-1}{2}+\frac{-1}{3}+\frac{-5}{4}\)
\(=\left(\frac{-1}{2}+\frac{-1}{3}\right)+\frac{-5}{4}\)
\(=\frac{-5}{6}+\frac{-5}{4}\)
\(=\frac{-50}{24}=\frac{-25}{12}\)
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A)\(\frac{-1}{2}+\frac{-1}{3}+\frac{-5}{4}\)
\(=\frac{-6}{12}+\frac{-4}{12}+\frac{-15}{12}\)
\(=\frac{-25}{12}\)
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b) \(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\)
\(=\frac{13}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\)
\(=\frac{13}{3}.\frac{-1}{3}\)
\(=\frac{-13}{3}\)
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a) Efrac{1}{1.2.3}+frac{1}{2.3.4}+...+frac{1}{48.49.50}
b) Ffrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}
c) Gfrac{636363.37-373737.63}{1+2+3+...+2017}
d) Hleft(frac{12+frac{12}{19}-frac{12}{37}-frac{12}{53}}{3+frac{1}{3}-frac{3}{37}-frac{3}{53}}:frac{4+frac{4}{17}+frac{4}{19}+frac{4}{2016}}{5+frac{5}{17}+frac{5}{19}+frac{5}{3016}}right).frac{124242423}{237373735}
giúp mk với ! Help me!
Đọc tiếp
a) \(E=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{48.49.50}\)
b) \(F=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
c) \(G=\frac{636363.37-373737.63}{1+2+3+...+2017}\)
d) \(H=\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2016}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{3016}}\right).\frac{124242423}{237373735}\)
giúp mk với ! Help me!
c) G = \(\frac{636363.37-373737.63}{1+2+3+...+2017}\)
G = \(\frac{63.10101.37-37.10101.63}{1+2+3+...+2017}\)
G = \(\frac{0}{1+2+3+...+2017}\)
=> G = 0
Vậy G = 0
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a) \(E=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{48.49.50}\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{48.49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}.\frac{612}{1225}\)
\(\Rightarrow E=\frac{306}{1225}\)
Vậy...
b) \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
d) Bạn xem lại đề nhé
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