Câu 3: 

#include <bits/stdc++.h>

using namepsace std;

double a,b,c,p,s;

int main()

{

cin>>a>>b>>c;

p=(a+b+c)/2;

s=sqrt(p*(p-a)*(p-b)*(p-c));

cout<<fixed<<setprecision(2)<<s;

return 0;

}

Câu 3: 

#include <bits/stdc++.h>

using namepsace std;

double a,b,c,p,s;

int main()

{

cin>>a>>b>>c;

p=(a+b+c)/2;

s=sqrt(p*(p-a)*(p-b)*(p-c));

cout<<fixed<<setprecision(2)<<s;

return 0;

}

Câu 1: 

uses crt;

var a,b:integer;

begin

clrscr;

readln(a,b);

write(a+b);

readln;

end.

Câu 2:

uses crt;

var a,b,c:integer;

begin

clrscr;

readln(a,b,c);

writeln(a+b-c);

readln;

end.

Câu 3: 

uses crt;

var a,b:integer;

begin

clrscr;

readln(a,b);

writeln(a-b);

readln;

end.

Câu 4: 

uses crt;

var x,y,z:integer;

begin

clrscr;

readln(x,y,z);

writeln((x+y)*z);

readln;

end.

Bài 3: 

uses crt;

const fi='teptong.txt'

var a,b:integer;

f1:text;

begin

clrscr;

assign(f1,fi); rewrite(f1);

readln(a,b);

writeln(a+b);

writeln(f1,a+b);

close(f1);

readln;

end.

#include <bits/stdc++.h>

using namespace std;

long long a,b;

int main()

{

cin>>a>>b;

cout<<a*b<<endl;

cout<<fixed<<setprecision(2)<<(a*1.0)/(b*1.0);

return 0;

}

Bài 1: 

uses crt;

var a:array[1..100]of integer;

i,n,min:integer;

begin

clrscr;

write('n='); readln(n);

for i:=1 to n do 

begin

write('A[',i,']='); readln(a[i]);

end;

min:=a[1];

for i:=1 to n do 

if min>a[i] then min:=a[i];

writeln(min);

readln;

end.

Bài 2: 

uses crt;

var a:array[1..100]of integer;

i,n,max:integer;

begin

clrscr;

write('n='); readln(n);

for i:=1 to n do 

begin

write('A[',i,']='); readln(a[i]);

end;

max:=a[1];

for i:=1 to n do 

 if max<a[i] then max:=a[i];

writeln(max);

readln;

end.

#include <bits/stdc++.h>

using namespace std;

long long c,a,b;

int main()

{

cin>>a>>b;

c=a-b;

cout<<c;

return 0;

}