tim n de n+1;4n^2+8n+5 va 6n^2+12n+7 cung la so nguyen to
tim m,n thuôc Z de 1/m + n/6 = 1/2
tim m,n thuoc N de m/2 - 2/n = 1/2
cho A=6n-1/3n+1(n thuoc z) hoi a tim n de A nguyen b tim n de A co gia tri nho nhat
cho A=6n-1/3n+1(n thuoc z) hoi a tim n de A nguyen b tim n de A co gia tri nho nhat
Giải:Ta có:A=\(\frac{6n-1}{3n+1}=\frac{6n+2-3}{3n+1}=\frac{2\left(3n+1\right)}{3n+1}-\frac{3}{n+1}=2-\frac{3}{n+1}\)
a,Để A nguyên thì \(\frac{3}{n+1}\in Z\)\(\Rightarrow3⋮\left(n+1\right)\)
\(\Rightarrow n+1\inƯ\left(3\right)=\left\{-3,-1,1,3\right\}\)
\(\Rightarrow n\in\left\{-4,-2,0,2\right\}\)
b,Để A có GTNN thì \(\frac{3}{n+1}\) lớn nhất
\(\Rightarrow n+1\) bé nhất và n+1>0
\(\Rightarrow n+1=1\Rightarrow n=0\)
Nên GTNN của A=-1
cho A=n-1/n-4
tim n nguyen de A la mot phan so
tim n nguyen de n la mot so nguyen
Tim so tu nhien n de phan so A=\(\frac{2n+1}{n-3}+\frac{3n-5}{n-3}-\frac{4n-5}{n-3}\)
a/Tim n de A nhan gia tri nguyen
b/Tim n de A la phan so toi gian
Cho A= n-1/n+4
a) Tim n nguyen de A la mot phan so
b) Tim n nguyen de A la mot so nguyen
Cho A = n-1/n+4
a,tim n de A la so nguyen to
b,tim n nguyen de A la mot so nguyen
cho bieu thuc :A=2n+1/n-3+3n-5/n-3-4n-5/n-3.a, tim n de a nhan gia tri nguyen .b,tim n de a la phan so toi gian
cho bieu thuc :A=2n+1/n-3+3n-5/n-3-4n-5/n-3.a, tim n de a nhan gia tri nguyen .b,tim n de a la phan so toi gian
https://hoc24.vn/cau-hoi/bai-1-cho-bieu-thuc-p-11n-n-thuoc-z-a-tim-dieu-kien-cua-n-de-p-la-phan-sob-tim-phan-so-p-biet-n3-n5-n9c-tim-n-de-p-nguyen-bai-2.332315455557
Cho phan so A = n+1/n-3 (nCZ)
a) Tim cac gia tri cua n de A la phan so
b) Tim n de A co gia tri nguyen
a) Để A = \(\frac{n+1}{n-3}\) là phân số thì \(n-3\ne0\)hay\(n\ne3\)
b) Để A là số nguyên thì:
\(n+1⋮n-3\)
mà \(n-3⋮n-3\)
\(\Rightarrow\left(n+1\right)-\left(n-3\right)⋮n-3\) hay\(4⋮n-3\)
\(\Rightarrow n-3\inƯ_{\left(4\right)}\)
\(\Rightarrow n\in\){4;2;5;1;7;-1}