1.4x - 3.2x = 2.5 - 4.5
✳ LƯU Ý : DẤU CHẤM LÀ DẤU NHÂN NHÉ !
1/1.2 +1/2.3+1/2.4+.....+1/x+(x+1) =122/123 các bạn hãy giải ra luôn nhé mik xin cảm ơn mik cần rất gấp.
MIk lưu ý dấu chấm là dấu nhân nhé còn dấu chấm đằng sau là ko phải dấu nhân nhé
\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+.......+\dfrac{1}{x\cdot\left(x+1\right)}=\dfrac{122}{123}\)
\(\Leftrightarrow1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{122}{123}\)
\(\Leftrightarrow1-\dfrac{1}{x+1}=\dfrac{122}{123}\)
\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{123}\)
\(\Leftrightarrow x=122\)
câu 1 : lưu ý là dấu . tương ứng với dấu nhân nhé
55.x-4.(2.x+8)=32x
câu 2 :lưu ý là dấu chấm tương ứng với dâu nhân câu 1 cũng thế
240-(5.x+2).20=64.x-21.(x+3)
các bạn trình bay rỏ ràng nhé mk link liike cho
\(\frac{2003.14+1988+2001.2002}{2002+2002.503+504.2002}\)
lưu ý dấu chấm là dấu nhân hi hi nhớ cả đầy đủ chi tiết nhé ai giải đc mink tick
1) A= 1/3.4 + 1/4.5 +.....+ 1/39.40
2) B= 1/4.7 + 1/7.10 + .....+ 1/37.40
3) C= 2/4.7 + 2/7.10 +.......+ 2/37.40
Lưu ý: dấu chấm là dấu nhân( nếu bạn nào ko biết)
Mình cần gấp, nhờ các bạn. Phải đúng nhá
Thanks you
1)
A= \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{39.40}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-...+\frac{1}{39}-\frac{1}{40}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{40}\)
=> A= 27/120
A = \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{39.40}\)
= \(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{39}-\frac{1}{40}\)
= \(\frac{1}{3}-\frac{1}{40}\)
= \(\frac{37}{120}\)
B = \(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{37.40}\)
= \(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
= \(\frac{1}{3}\left(\frac{1}{4}-\frac{1}{40}\right)\)
= \(\frac{1}{3}.\frac{9}{40}=\frac{3}{40}\)
C = \(\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{37.40}\)
= \(\frac{2}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
= \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{40}\right)\)
= \(\frac{2}{3}.\frac{9}{40}=\frac{3}{20}\)
1) A = \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{39.40}\)
A = \(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{39}-\frac{1}{40}\)
A = \(\frac{1}{3}-\frac{1}{40}\)
A = \(\frac{37}{120}\)
2) B = \(\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{7}\right)+\frac{1}{3}.\left(\frac{1}{7}-\frac{1}{10}\right)+...+\frac{1}{3}.\left(\frac{1}{37}-\frac{1}{40}\right)\)
B = \(\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
B = \(\frac{1}{3}.\frac{9}{40}\)
B = \(\frac{3}{40}\)
3) C = \(\frac{2}{4.7}+\frac{2}{7.10}+...+\frac{2}{37.40}\)
C = \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{7}\right)+\frac{2}{3}.\left(\frac{1}{7}-\frac{1}{10}\right)+...+\frac{2}{3}.\left(\frac{1}{37}-\frac{1}{40}\right)\)
C = \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{37}-\frac{1}{40}\right)\)
C = \(\frac{2}{3}.\left(\frac{1}{4}-\frac{1}{40}\right)\)
C = \(\frac{2}{3}.\frac{9}{40}\)
C = \(\frac{3}{20}\)
Tìm X
2/5.1/x+1/x.2+2/5=0,5
các bạn trả lời nhah hộ mik nhé mik đang cần gấp.
Lưu ý: dấu chấm là dấu nhân.
\(\frac{2}{5}.\frac{1}{x}+\frac{1}{x}.2+\frac{2}{5}=0,5\)
\(\Rightarrow\frac{2}{5x}+\frac{2}{x}+\frac{2}{5}=\frac{1}{2}\)
\(\Rightarrow2.\left(\frac{1}{5x}+\frac{1}{x}+\frac{1}{5}\right)=\frac{1}{2}\)
\(\Rightarrow\frac{1}{5x}+\frac{5}{5x}+\frac{x}{5x}=\frac{1}{2}:2=\frac{1}{4}\)
\(\Rightarrow\frac{1+5+x}{5x}=\frac{1}{4}\)
\(\Rightarrow4.\left(1+5+x\right)=5x\)
\(\Rightarrow4+20+4x=5x\)
\(\Rightarrow24+4x=5x\)
\(\Rightarrow5x-4x=24\)
\(\Rightarrow x=24\)
Trả lời
2/5.1/x+1/x.2+2/5=0,5
1/x.(2/5+2)+2/5 =1/2
1/x.12/5+2/5 =1/2
1/x.12/5 =1/2-2/5
1/x.12/5 =1/10
1/x =1/10:12/5
1/x =1/24.
Hình như mk làm sai !
\(\frac{2}{5}.\frac{1}{x}+\frac{1}{x}.2+\frac{2}{5}=0,5\)
\(\Rightarrow\frac{1}{x}\left(\frac{2}{5}+\frac{4}{2}\right)=\frac{1}{2}-\frac{2}{5}\)
\(\Rightarrow\frac{1}{x}.\frac{12}{5}=\frac{1}{10}\)
\(\Rightarrow\frac{1}{x}=\frac{1}{24}\)
\(\Rightarrow x=24\)
~Study well~
Tính:
\(\frac{7256.4375-725}{3650+4375.7255}\)(Lưu ý: dấu chấm là dấu nhân)
\(\frac{7256.4375-725}{3650+4375.7255}\)
\(=\frac{\left(7255+1\right).4375-725}{3650+4375.7255}\)
\(=\frac{7255.4375+4375-725}{3650+4375.7255}\)
\(=\frac{7255.4375+3650}{3650+4375.7255}\)
\(=1\)
\(\frac{7256.4375-725}{3650+4375.7255}=1\)
\(\frac{7256.4375-725}{3650+4375.7255}\)
\(=\frac{\left(7256-1\right).4375+4375-725}{3650+4375.7255}\)
\(=\frac{7255.4375+3650}{3650+4375.7255}\)
\(=1\)
làm giúp mình bài này nhé
tính nhanh
43.17+29.57+13.43+57
lưu ý dấu chấm trên đó là nhân đó nha
43.17+29.57+13.43+57
=43.(17+13)+57.(29+1)
=43.30+57.30
=30.(43+57)
=30.100=3000
\(43.17+29.57+13.43+57\)
\(=43.\left(17+13\right)+57.\left(29+1\right)\)
\(\text{= 43.30 + 57.30}\)
\(=30.\left(47+57\right)\)
\(=30.100\)
\(=3000\)
Hok tốt !
\(43.17+29.57+13.43+57\)
\(=\left(43.17+13.43\right)+\left(29.57+57\right)\)
\(=43.\left(17+13\right)+57.\left(29+1\right)\)
\(=43.30+57.30\)
\(=30.\left(43+57\right)=30.100=3000\)
E = 5 / 2.3 + 5/3.4 + 5/ 4.5 ..... 5/ 49.50
dấu chấm là phép nhân nhé
1) Tính nhanh:
a) A = \(\frac{3}{2}+\frac{3}{6}+\frac{3}{12}+\frac{3}{20}+....+\frac{3}{90}\)
b) B = \(\frac{2}{2.5}+\frac{2}{5.8}+\frac{2}{8.11}+\frac{2}{11.14}+\frac{2}{14.17}\)
Lưu ý: Dấu chấm là dấu nhân nha mọi người
\(a,A=\frac{3}{2}+\frac{3}{6}+\frac{3}{12}+\frac{3}{20}+...+\frac{3}{90}\)
\(A=3.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\right)\)
\(A=3.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(A=3.\left(1-\frac{1}{10}\right)\)
\(A=3.\frac{9}{10}=\frac{27}{10}\)
\(b,B=\frac{2}{2.5}+\frac{2}{5.8}+\frac{2}{8.11}+\frac{2}{11.14}+\frac{2}{14.17}\)
\(B.\frac{3}{2}=\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}\)
\(B.\frac{3}{2}=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}\)
\(B.\frac{3}{2}=\frac{1}{2}-\frac{1}{17}\)
\(B=\frac{15}{34}:\frac{3}{2}=\frac{5}{17}\)