x=2993/225.

\(\frac{\frac{41}{10}}{\frac{9}{4}}=\frac{41}{10}\div\frac{9}{4}=\frac{41}{10}\times\frac{4}{9}=\frac{82}{45}\Rightarrow\frac{82}{45}=\frac{x}{7,3}\)

Đến đấy thôi

\(\frac{41}{\frac{10}{\frac{9}{4}}}=\frac{x}{7,3}\)

\(\frac{4,1}{2,25}=\frac{x}{7,3}\)

\(x=4,1\cdot7,3\div2,25\)

\(x=\frac{2993}{225}\)

X = 26937 / 400 hay = 67,3425

41/10 / 9/4 = x/7,3

4,1:2,25 = x:7,3

=> 4,1.7,3 = 2,25.x

29,93 = 2,25.x

x = 29,93:2,25

x = 13,30(2) hoặc x = \(\frac{2993}{225}\)

Tick hộ mik vs ạ thanks

a ) Ta có : \(\frac{x+11}{10}+\frac{x+21}{20}+\frac{x+31}{30}=\frac{x+41}{40}+\frac{x+101}{5}\) 

\(\Leftrightarrow\left(\frac{x+11}{10}-1\right)+\left(\frac{x+21}{10}-1\right)+\left(\frac{x+31}{30}-1\right)=\left(\frac{x+41}{40}-1\right)+\left(\frac{x+101}{50}-2\right)\)

\(\Leftrightarrow\frac{x+1}{10}+\frac{x+1}{20}+\frac{x+1}{30}=\frac{x+1}{40}+\frac{x+1}{50}\)

\(\Rightarrow\frac{x+1}{10}+\frac{x+1}{20}+\frac{x+1}{30}-\frac{x+1}{40}-\frac{x+1}{50}=0\)

\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{20}+\frac{1}{30}-\frac{1}{40}-\frac{1}{50}\right)=0\)

Mà \(\left(\frac{1}{10}+\frac{1}{20}+\frac{1}{30}-\frac{1}{40}-\frac{1}{50}\right)\ne0\)

Nên x + 1 = 0

=> x = -1

còn b vs c thì sao ạ

b) Sai đề à bạn đề \(\frac{x+2}{42}+\frac{x+4}{22}=\frac{x+5}{23}+\frac{x+3}{43}\)  hả đề này mk làm đc 

\(a,\)\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=-\frac{37}{45}\)

  \(x+\left(\frac{9-5}{5.9}+\frac{13-9}{9.13}+\frac{17-13}{13.17}+...+\frac{45-41}{41.45}\right)=-\frac{37}{45}\)

  \(x+\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+....+\frac{1}{41}-\frac{1}{45}\right)-\frac{37}{45}\)

 \(x+\left(\frac{1}{5}-\frac{1}{45}\right)=-\frac{37}{45}\)

 \(x+\frac{8}{45}=-\frac{37}{45}\)

\(x=-\frac{37}{45}-\frac{8}{45}\)

\(x=-1\)

thế phần b, c đâu bạn

\(b)\) Ta có: \(x-\frac{37}{45}=\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45\text{ }}\)

\(\Leftrightarrow x-\frac{37}{45}=\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{41}-\frac{1}{45}\)

\(\Leftrightarrow x-\frac{37}{45}=\frac{1}{5}-\frac{1}{45}\)

\(\Leftrightarrow x-\frac{37}{45}=1\)

\(\Leftrightarrow x=1+\frac{37}{45}\)

\(\Leftrightarrow x=\frac{82}{45}\)

Vậy \(x=\frac{82}{45}\)

Câu a nx bạn ơi

CHỉ có câu b thì mik ko cho bạn đc

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Xét vế phải

\(\frac{1}{9}+\frac{2}{8}+\frac{3}{7}+\frac{4}{6}+\frac{5}{5}+\frac{6}{4}+\frac{7}{3}+\frac{8}{2}+\frac{9}{1}\)
\(=\frac{1}{9}+\frac{2}{8}+\frac{3}{7}+\frac{4}{6}+\frac{5}{5}+\frac{6}{4}+\frac{7}{3}+\frac{8}{2}+9\)

\(=\frac{1}{9}+\frac{2}{8}+\frac{3}{7}+\frac{4}{6}+\frac{5}{5}+\frac{6}{4}+\frac{7}{3}+\frac{8}{2}+\left(1+1+...+1\right)\)

\(=\left(1+\frac{1}{9}\right)+\left(1+\frac{2}{8}\right)+\left(1+\frac{3}{7}\right)+\left(1+\frac{4}{6}\right)+\left(1+\frac{5}{5}\right)+\left(1+\frac{6}{4}\right)+\left(1+\frac{7}{3}\right)+\left(1+\frac{8}{2}\right)+1\)\(=\frac{10}{9}+\frac{10}{8}+\frac{10}{7}+\frac{10}{6}+\frac{10}{5}+\frac{10}{4}+\frac{10}{3}+\frac{10}{2}+\frac{10}{10}\)

\(=10\times\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}\right)\)

Thay vào bài ,ta được:

\(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}\right)\times x=10\times\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}\right)\)\(\Rightarrow x=10\)

Vậy x=10

chúc bạn học tốt

\(\frac{15}{41}+\frac{-138}{41}< x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)

\(\Leftrightarrow\frac{-123}{41}< x< \frac{1.3+1.2+1}{6}\)

\(\Leftrightarrow-3< x< 1\)

\(\Rightarrow x\in\left\{-2;-1;0\right\}\)

\(\frac{x}{5}=\frac{15}{2}-\frac{51}{10}\)

\(\frac{x}{5}=\frac{15.5-51}{10}\)

\(\frac{x}{5}=\frac{24}{10}\)

\(\frac{x}{5}=\frac{12}{5}\)

\(x=12\)

\(\frac{2x}{3}-\frac{1}{9}=\frac{59}{36}+\frac{1}{4}\)

\(\frac{2x}{3}-\frac{1}{9}=\frac{59+9}{36}\)

\(\frac{2x}{3}-\frac{1}{9}=\frac{68}{36}\)

\(\frac{2x}{3}=\frac{68}{36}+\frac{1}{9}\)

\(\frac{2x}{3}=\frac{68}{36}+\frac{4}{36}\)

\(\frac{2x}{3}=2\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

tập trung sẽ bt làm