\(201^{60}=\left(201^4\right)^{15}=1944810000^{15}\)

\(398^{45}=\left(398^3\right)^{15}=63044792^{15}\)

Do \(1944810000>63044792\)

\(\Rightarrow1944810000^{15}>63044792^{15}\)

\(\Rightarrow201^{60}>398^{45}\)

Ta có:

\(201^{60}>200^{60};398^{45}< 400^{45}\)

\(200^{60}=\left(2.100\right)^{60}=2^{60}.100^{60}=2^{60}.\left(10^2\right)^{60}\)

\(=2^{60}.10^{120}=2^{60}.10^{30}.10^{90}\)

\(400^{45}=\left(2.100\right)^{45}=2^{45}.100^{45}=2^{45}.\left(10^2\right)^{45}\)

\(=2^{45}.10^{90}\)

Mà \(2^{60}.10^{30}.10^{90}>2^{45}.10^{90}\)

\(\Rightarrow200^{60}>400^{45}\)

\(\Rightarrow201^{60}>200^{60}>400^{45}>398^{45}\)

\(\Rightarrow201^{60}>398^{45}\)

`#3107`

\(201^{60}\text{ và }398^{45}\)

Ta có:

\(201^{60}=\left(201\right)^{15\cdot4}=\left(201^4\right)^{15}=1632240801^{15}\)

\(398^{45}=\left(398\right)^{15\cdot3}=\left(398^3\right)^{15}=63044792^{15}\)

Vì `63044792 < 1632240801 \Rightarrow`\(1632240801^{15}< 63044792^{15}\)

\(\Rightarrow201^{60}>398^{45}\)

Vậy, \(201^{60}>398^{45}.\)

\(\frac{-189}{398}< \frac{-187}{394}\)

-189/398<-187/394

C1: So sánh hai phân số \(\frac{-7}{11}\)và\(\frac{13}{-17}\)

    Đổi: \(\frac{13}{-17}\)=\(\frac{-13}{17}\)

 Ta có: BCNN (11;17) = 187

\(\Rightarrow\)\(\frac{-7}{11}\)= \(\frac{-7\times17}{11\times17}\)=\(\frac{-119}{187}\)                                              \(\Rightarrow\)\(\frac{-13}{17}\)= \(\frac{-13\times11}{17\times11}\)= \(\frac{-143}{187}\)

 Vì (-119) >(-143) nên \(\frac{-119}{187}\)>\(\frac{-143}{187}\)hay  \(\frac{-7}{11}\)>\(\frac{13}{-17}\)

 Mình chỉ giúp bạn được thế thôi, ko k cũng được, hoặc k càng tốt