a,=16.(64+17)+81.84
   =16.81+81.84
   =81(16+84)
   =81.100=8100
b,=32.19+32
   =32.(19+1)
   =32.20=640
c,=12.19+12.37+44.12
   =12.(19+37+44)
   =12.100=1200
d, Khoảng cách là:
        5-1=4;9-5=4
    Số số hạng là:
        (81-1):4+1=21(số)
    Tổng dãy số là:
        (81+1).21:2=861

a

\(\text{=16.(64+17)+81.84}\)
\(\text{=16.81+81.84}\)
\(\text{ =81.(16+84)}\)
 \(\text{=81.100=8100}\)

b

\(\text{=32.19+32}\)
\(\text{ =32.(19+1)}\)
\(\text{ =32.20=640}\)
c

\(\text{=12.19+12.37+44.12}\)
\(\text{ =12.(19+37+44)}\)
\(\text{ =12.100}\)

\(=1200\)

d
Có tất cả số hạng là

\(\text{( 81 - 1 ) : 4 + 1 = 21 (số )}\)

Tổng là

\(\text{( 81 + 1 ) x 21 : 2 = 861}\)

\(\dfrac{1}{10}+\dfrac{4}{20}+\dfrac{9}{30}+\dfrac{16}{40}+\dfrac{25}{50}+\dfrac{36}{60}+\dfrac{49}{70}+\dfrac{64}{80}+\dfrac{81}{90}\)
\(=\dfrac{1}{10}+\dfrac{1}{5}+\dfrac{3}{10}+\dfrac{2}{5}+\dfrac{1}{2}+\dfrac{3}{5}+\dfrac{7}{10}+\dfrac{4}{5}+\dfrac{9}{10}\)
\(=\left(\dfrac{1}{10}+\dfrac{3}{10}+\dfrac{7}{10}+\dfrac{9}{10}\right)+\left(\dfrac{1}{5}+\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{4}{5}\right)+\dfrac{1}{2}\)
\(=2+2+\dfrac{1}{2}\)
\(=4+\dfrac{1}{2}\)
\(=\dfrac{8}{2}+\dfrac{1}{2}=\dfrac{9}{2}\)

\(\frac{1}{10}+\frac{4}{20}+\frac{9}{30}+\frac{16}{40}+\frac{25}{50}\) \(+\frac{36}{60}+\frac{49}{70}+\frac{64}{80}+\frac{81}{90}\)

\(=\frac{1}{10}+\frac{1}{5}+\frac{3}{10}+\frac{2}{5}+\frac{1}{2}+\frac{3}{5}+\frac{7}{10}+\frac{4}{5}+\frac{9}{10}\)

\(=\left(\frac{1}{10}+\frac{9}{10}\right)+\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{3}{10}+\frac{7}{10}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{2}\)

\(=1+1+1+1+0,5\)

\(=4+0,5\)

\(=4,5\)

80

146

712

1057

Tính :

20 + 60 = 80

65 + 81 = 146

34 + 678 = 712

64 + 41 +952 = 1057

=80

=146

=712

=1057

a.2^3. 19 - 2^3.14 + 1^200

 =2^3.19-2^3.14+1

 =2^3.(19-14)+1

 =2^3.5+1

 =8.5+1

 =40+1

 =41

b. (-45)+81+(-64)+(-91)+(-220)

= 36+ (-155)+ (-220)

= -339