\(\left(x-\frac{1}{3}\right)\left(x+\frac{2}{5}\right)>0\)

\(\orbr{\begin{cases}x=\frac{1}{3}\\x=-\frac{2}{5}\end{cases}}\)

\(-\frac{2}{5}< x< \frac{1}{3}\)

\(\frac{2}{3}-\frac{1}{3}.\frac{x-3}{2}-\frac{1}{2}.2.x+1=5\)

\(\Leftrightarrow\frac{2}{3}-\frac{x-3}{3.2}-\frac{2.x}{2}+1=5\)

\(\Leftrightarrow\frac{2}{3}-\frac{x-3}{6}-x+1=5\)

\(\Leftrightarrow\frac{2}{3}-\frac{x-3}{6}-x=4\)

\(\Leftrightarrow\frac{4}{6}-\frac{x-3}{6}-\frac{6x}{6}=4\)

\(\Leftrightarrow\frac{4-\left(x-3\right)-6x}{6}=4\)

\(\Leftrightarrow\frac{4-x+3+6x}{6}=4\)

\(\Leftrightarrow\frac{4+3-x+6x}{6}=\frac{4}{1}\)

\(\Leftrightarrow\frac{7+5x}{6}=\frac{4}{1}\)

\(\Leftrightarrow7+5x=4.6\)

\(\Leftrightarrow7+5x=24\)

\(\Leftrightarrow5x=24-7\)

\(\Leftrightarrow5x=17\)

\(\Leftrightarrow x=\frac{17}{5}\)

Vậy \(x=\frac{17}{5}\)

Chúc bạn học tốt

(\(x\) + \(\dfrac{1}{2}\))² = \(\dfrac{1}{16}\)

\(\left[{}\begin{matrix}x+\dfrac{1}{2}=-\dfrac{1}{4}\\x+\dfrac{1}{2}=\dfrac{1}{4}\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=-\dfrac{1}{4}-\dfrac{1}{2}\\x=\dfrac{1}{4}-\dfrac{1}{2}\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=-\dfrac{3}{4}\\x=-\dfrac{1}{4}\end{matrix}\right.\)

Vậy \(x\) \(\in\) {- \(\dfrac{3}{4};-\dfrac{1}{4}\)}

\(x\) : (- \(\dfrac{1}{3}\))³  = - \(\dfrac{1}{3}\)

\(x\)              = (-\(\dfrac{1}{3}\)).(-\(\dfrac{1}{3}\))³

\(x\)             = \(\dfrac{1}{81}\)

Vậy \(x=\dfrac{1}{81}\)

(\(\dfrac{2}{3}\))⁵\(x\) = \(\dfrac{2}{5}\)

       \(x\) = \(\dfrac{2}{5}\) : (\(\dfrac{2}{3}\))⁵ 

       \(x\) = \(\dfrac{243}{80}\)

Vậy \(x\) = \(\dfrac{243}{80}\)

\(\left(\frac{3}{4}x-\frac{9}{16}\right)-\left(\frac{1}{3}+\frac{-3}{5}x\right)=0.\)

\(\frac{3}{4}x-\frac{9}{16}-\frac{1}{3}-\frac{-3}{5}x=0\)

\(\frac{27}{20}x-\frac{43}{48}=0\)

\(\frac{27}{20}x=\frac{43}{48}\)

\(x=\frac{215}{324}\)

mong ủng hộ mk 

(3 phần 4 nhân X - 9 phần 16 ) - (1 phần 3 + -3 phần 5 chia X ) = 0

=>\(\frac{3}{4}.x-\frac{9}{16}=\frac{1}{3}+\frac{-3}{5}:x\)

=\(\frac{3}{4}.x-\frac{9}{16}=\frac{-4}{15}:x\)

=>\(\frac{3}{4}.x-\frac{-4}{15}:x=\frac{9}{16}\)

Đến đây thì mk chịu =)

Dù sao thi cg ti.ck giúp mk tí

12 phần 25 trừ cho 14 phần 5 bằng bao nhiêu

8==D LOL

\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{x\left(x+2\right)}=\frac{11}{75}\)

\(\Leftrightarrow\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{11}{75}\)

\(\Leftrightarrow\frac{1}{3}-\frac{1}{x+2}=\frac{11}{75}:\frac{1}{2}=\frac{22}{75}\Leftrightarrow\frac{1}{x+2}=\frac{1}{25}\Leftrightarrow x=23\)

ý bạn bảo (x-2 và 1 phần 2) là hợp số hả :

ta có (x-2 và 1 phần 2) nhân (2x+3 và 1 phần 5) =0

\(\Leftrightarrow\) [2.(x-2) +1]. [5.(2x+3)+1]=0

\(\Leftrightarrow\)(2x-3)(10x+16)=0

\(\Leftrightarrow\)\(\orbr{\begin{cases}2x=3\\10x=-16\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{-8}{5}\end{cases}}\)

vậy