=> (35 : x + 3) . 19 = 152

=> 35 : x + 3 = 8

=> 35 : x = 5

=> x = 7

(35*x+3)*19=165-13

(35*x+3)*19=152

35*x+3=152/19

35*x+3=8

35*x=8-3

35*x=5

x=35/5

x=7

\(165-\left(35\div x+3\right).19=13\)

\(\Leftrightarrow\)\(\left(35\div x+3\right).19=165-13\)

\(\Leftrightarrow\)\(\left(35\div x+3\right).19=152\)

\(\Leftrightarrow\)\(\left(35\div x+3\right)=152\div19\)

\(\Leftrightarrow\)\(35\div x+3=8\)

\(\Leftrightarrow\)\(35\div x=8-3\)

\(\Leftrightarrow\)\(35\div x=5\)

\(\Leftrightarrow\)\(x=35\div5\)

\(\Leftrightarrow\)\(x=7\)

Đáp án là A

Ta có: 165 - (35:x + 3).19 = 13

     ⇔ (35:x + 3).19 = 165 - 13

     ⇔ (35:x + 3).19 = 152

     ⇔ (35:x + 3) = 152:19 = 8

     ⇔ 35:x = 5

     ⇔ x = 7

đáp án a nhé

165 - (35 : x + 3). 19 = 13

(35 : x + 3). 19 =165-13

(35 : x + 3). 19  =152

35:x+3= 152:19

35:x+3=8

35: x= 8-3

35:x= 5

x= 35:5

x= 7

Vậy..

\(165-\left(35:x+3\right).19=13\)

\(\Rightarrow\left(35:x+3\right).19=165-13\)

\(\Rightarrow\left(35:x+3\right).19=152\)

\(\Rightarrow\left(35:x+3\right)=152:19\)

\(\Rightarrow\left(35:x+3\right)=8\)

\(\Rightarrow35:x=8-3\)

\(\Rightarrow35:x=5\)

\(\Rightarrow x=35:5\)

\(\Rightarrow x=7\)

Vậy x = 7

165 - (35 : x + 3) * 19 = 13

=> (35 : x + 3) * 19 = 165 - 13 = 152

=> 35 : x + 3 = 152 : 19 = 8

=> 35 : x = 8 - 3 = 5

=> x = 35 : 5 = 7

\(165-\left(35:x+3\right)\times19=13\)

\(\Leftrightarrow\left(35:x+3\right)\times19=165-13\)

\(\Leftrightarrow\left(35:x+3\right)\times19=152\)

\(\Leftrightarrow\left(35:x+3\right)=152:19\)

\(\Leftrightarrow\left(35:x+3\right)=8\)

\(\Leftrightarrow35:x=8-3\)

\(\Leftrightarrow35:x=5\)

\(\Leftrightarrow x=35:5\)

\(\Rightarrow x=7\)

165 - ( 35 : x + 3 ) . 19 = 13

         ( 35 : x + 3 )  19  = 165 - 13

         ( 35 : x + 3 ) . 19 = 152

         ( 35 : x + 3 )        = 8

           35 : x                 = 5

                  x                 = 35 : 5

                  x                 = 7

\(165-\left(35:x+3\right).19=13\)

\(\Rightarrow\left(35:x+3\right).19=152\)

\(\Rightarrow35:x+3=152:19\)

\(\Rightarrow35:x+3=8\)

\(\Rightarrow35:x=5\)

\(\Rightarrow x=35:5\)

\(\Rightarrow x=7\)

165 - ( 35 : x + 3 ) x 15 = 15

=> ( 35 : x + 3) x 15 = 165 - 15 = 150

=> 35 : x + 3 = 150 : 15 = 10

=> 35 : x = 10 - 3 = 7

=> x = 35 : 7 = 5

Mik nghĩ bạn chép sai đề, có lẽ đề như thế này:

165-(35:x+3)x15=15

      (35:x+3)x15=165-15

      (35:x+3)x15=150

       35:x+3      =150:15

       35:x+3      =10

       35:x          =10-3

       35:x          =7

           x           =35:7

           x           =5

a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)

\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)

\(\Leftrightarrow\left(x:3+17\right):10+48=50\)

\(\Leftrightarrow\left(x:3+17\right):10=2\)

\(\Leftrightarrow x:3+17=20\)

\(\Leftrightarrow x:3=3\)

hay x=9

b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)

\(\Leftrightarrow119-\left(x-6\right)=102\)

\(\Leftrightarrow x-6=17\)

hay x=23

c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)

\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)

\(\Leftrightarrow\left(35:x+3\right)=8\)

\(\Leftrightarrow35:x=5\)

hay x=7

a)\(3:\left(2x+1\right)=72-69\)

\(3:\left(2x+1\right)=3\)

\(2x+1=3:3\)

\(2x+1=1\)

\(2x=1-1\)

\(2x=0\)

\(x=0:2\)

\(x=0\)

các bài còn lại giống như câu a nha nếu ko biết thì comment lại minhf sẽ giải cho . Nhớ k cho mình nha

(35:x+3).19=165-13=152

35:x+3=152:19=8

35:x=8-3=5

x=35:5=7