\(\dfrac{2^3.9^3.45}{9^2.10-9^2}=\dfrac{2^3.3^6.3^2.5}{9^2\left(10-1\right)}=\dfrac{2^3.3^8.5}{9^3}=\dfrac{2^3.3^8.5}{3^6}\)

\(=2^3.3^2.5=360\)

Chào em

Anh có thể giúp j cho em

kết quả bằng 117

học tốt

\(25.2^3+75.2^3=2^3.\left(25+75\right)=8.100=800\)

\(3^2.187-87.3^2=3^2.\left(187-87\right)=9.100=900\)

\(4^2.19+80.4^2+4^2=4^2\left(19+80+1\right)=16.100=1600\)

\(73.5^2+5^2.28-5^2=5^2\left(73+28-1\right)=25.100=2500\)

\(6^2.48+51.6^2+36=6^2\left(48+51+1\right)=36.100=3600\)

\(113.7^2-7^2.12-49=49.\left(113-12-1\right)=4900\)

a. 25.2³ + 75.2³

= 2³(25 + 75)

= 8 . 100

= 800

b. 3² . 187 - 87.3² 

= 3² . (187 - 87)

= 9 . 100

= 900

c. 4² . 19 + 80 . 4² + 4²

= 4² . (19 + 80 + 1)

= 16 . 100

= 1600

d. 73 . 5² + 5². 28 - 5²

= 5² . (73 + 28 - 1)

= 25 . 100

= 2500

e. 6² . 48 + 51 . 6² + 36

= 36 . 48 + 51 . 36 + 36

= 36 . (48 + 51 + 1)

= 36 . 100

= 3600

g. 113.7² - 7².12 - 49

= 113 . 49 - 49 . 12 - 49

= 49. (113 - 12 - 1)

= 49 . 100

= 4900

j. (2³ . 9⁴ + 9³ . 45) : (9² . 10 - 9²)

= (2³ . 9⁴ + 9³ . 9.5) : [9²(10 - 1)]

= [9. (2³ . 9³ + 9² . 9.5)] : (9² . 9)

= {9. [9² (2³ + 9.5)]} : (9² . 9)

= (9. 9² . 53): 9³

= 9³ . 53 : 9³

= (9³:9³) . 53

= 53

a, 25 . 2³ + 75 . 2³ 
 = 2³ . (25 + 75)
 = 8 . 100
 = 800
b, 3² . 187 - 87. 3² 
 = 3² . (187 - 87)
 = 27 . 100
 = 2700
c, 4² . 19 + 80. 4² + 4² 
 = 4² . (19 + 80 +1)
 = 16 . 100
 = 1600
d, 73 . 5² + 5² . 28 - 5² 
 = 5² . (73 + 28 - 1)
 = 25 . 100
 = 2500
e, 6² .48 + 51. 6² + 36
 = 6² .48 + 51. 6² + 6² 
 = 6² . (48 + 51 + 1)
 = 36 . 100
 = 3600
g, 113. 7² - 7² .12 - 49
 = 113. 7² - 7² . 12 - 7² 
 = 7² . (113 - 12 - 1)
 = 49 . 100
 = 4900
h, (2³ . 9⁴ + 9³ .45): (9² .10 - 9² )
 = (8 . 9⁴ + 9³ . 9.5) : [9² .(10 - 1)]
 = (8 . 9⁴ + 9⁴ .5) : (9² . 9)
 = [9⁴ . (8 + 5)] : 9³ 
 =(6561 . 13) : 729
 = 85293 : 729
 = 117
Chúc bạn học tốt

a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)

\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)

\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)

\(=\frac{-60}{45}=\frac{-4}{3}\)

b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)

\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)

\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)

\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)

=\(=\frac{10}{6}=\frac{5}{3}\)

C =[125.(73-75)]:(-25)2

=125.(-2):(-25).2

=-250:(-50)

=5

E=125.9.(-4).(-8).25.7

=125.(-8).25.(-4).7.9

=-1000.(-100).63

=6300000

C = ( 125 . 73 - 125 . 75 ) : ( -50)

C = 125 .( -2 ) : (-50)

C = -250 : -50

C =  50

G = ( -3 )²+( -5)³: l -5 l

G = 9 + ( -125) : 5

G = 9 + ( -25 )

G= ( -16 )

E = 125 .9.*( -4 ) . ( -8) .25.7

E = 25.5 .( -4 ) .9 .2. ( -4 ) .25 .7

E =( -100 ).10.( -100).63

E = 10000.630

E = 630000

**** mha

\(B=\dfrac{-1}{9}\cdot\dfrac{-17}{19}\cdot\dfrac{58}{51}=\dfrac{1}{9}\cdot\dfrac{1}{3}\cdot\dfrac{58}{13}=\dfrac{58}{351}\)