Tính hợp lý nhất:
\(\frac{230^5}{23^5}\)
Tính hợp lý giá trị biểu thức sau
\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
1135/23-167/32+330/23
=(1135/23-330/23)+167/32
=805/23+167/32
=35+167/32
=1120/32+167/32
=1287/32
Thực hiện phép tính (hợp lý nếu có thể): \(\frac{4-\frac{1}{23}-\frac{5}{39}-\frac{25}{47}}{\frac{5}{69}+\frac{5}{117}+\frac{5}{141}}.\)
Ai làm nhanh và đúng cho 3 tick.
Thực hiện phép tính (Tính hợp lý):
a)\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
b)\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
(\(\frac{2}{5}\))6 . (\(\frac{25}{4}\))2 (câu này tính hợp lý nếu có thể)
\(\frac{100}{123}:\left(\frac{3}{4}+\frac{7}{12}\right)+\frac{23}{123}:\left(\frac{9}{5}-\frac{7}{15}\right)\)(câu này tính hợp lý nếu có thể)
Tính hợp lý
\(\frac{3}{5}+\frac{3}{11}-\left(\frac{-3}{7}\right)+\left(\frac{2}{97}\right)-\frac{1}{35}-\frac{3}{4}+\left(\frac{-23}{44}\right)\)
\(\frac{3}{5}+\frac{3}{11}-\left(\frac{-3}{7}\right)+\frac{2}{97}-\frac{1}{35}-\frac{3}{4}+\left(\frac{-23}{44}\right)\)
\(=\frac{3}{5}+\frac{3}{11}+\frac{3}{7}+\frac{2}{97}-\frac{1}{35}-\frac{3}{4}-\frac{23}{44}\)
\(=\left(\frac{3}{5}+\frac{3}{7}-\frac{1}{35}\right)+\left(\frac{3}{11}-\frac{3}{4}-\frac{23}{44}\right)+\frac{2}{97}\)
\(=\left(\frac{21}{35}+\frac{15}{35}-\frac{1}{35}\right)+\left(\frac{12}{44}-\frac{33}{44}-\frac{23}{44}\right)+\frac{2}{97}\)
\(=\frac{35}{35}+\left(\frac{-44}{44}\right)+\frac{2}{97}=1+\left(-1\right)+\frac{2}{97}=\frac{2}{97}\)
\(=\left(\frac{3}{5}+\frac{3}{7}-\frac{1}{35}\right)+\left(\frac{3}{11}-\frac{3}{4}-\frac{23}{44}\right)+\frac{2}{97}\)
\(=\left(\frac{21}{35}+\frac{15}{35}-\frac{1}{35}\right)+\left(\frac{12}{44}-\frac{33}{44}-\frac{23}{44}\right)+\frac{2}{97}\)
\(=-1+1+\frac{2}{97}\)
\(=\frac{2}{97}\)
=[3/5+(-3/7)-1/35]+[3/11-3/4-(-23/44)]+2/97
=[21/35+(-15/35)-1/35]+[12/44-33/44-(-23/44)+2/97
=(-1)+1+2/97
=0+2/97
=2/97
Bài 13 : TÍnh hợp lý giá trị của các biểu thức sau :
A = \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\) ; B = \(6\frac{3}{8}+5\frac{1}{2}\)
A= \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
=\(\frac{1135}{32}-\left(\frac{167}{32}+\frac{330}{23}\right)\)
=\(\frac{1135}{23}-\frac{167}{32}-\frac{330}{23}\)
=\(\left(\frac{1135}{23}-\frac{330}{23}\right)-\frac{167}{32}\)
=\(\frac{805}{23}-\frac{167}{32}\)
=\(\frac{953}{32}\)
B=\(6\frac{3}{8}+5\frac{1}{2}\)
=\(\frac{51}{8}+\frac{11}{2}\)
=\(\frac{51}{8}+\frac{44}{8}\)
=\(\frac{51+44}{8}\)
=\(\frac{95}{8}\)
Tính hợp lý:
a) \(\left(4\frac{2}{3}-2\frac{2}{5}+7\frac{7}{13}\right)-\left(3\frac{5}{23}-6\frac{6}{13}\right)\)
b) \(\frac{-17,5+\frac{5}{3}+2\frac{1}{7}}{7,0-\frac{2}{3}+\frac{6}{7}}\)
a) \(\left(4\frac{2}{3}-2\frac{2}{5}+7\frac{7}{13}\right)-\left(3\frac{5}{23}-6\frac{6}{13}\right)\)
= \(4\frac{2}{3}-2\frac{2}{5}+7\frac{7}{13}-3\frac{5}{23}+6\frac{6}{13}\)
= \(\left(4\frac{2}{3}-2\frac{2}{5}\right)+\left(7\frac{7}{13}+6\frac{6}{13}\right)-3\frac{5}{23}\)
= \(2\frac{4}{15}+14-3\frac{5}{23}\)
= \(16\frac{4}{15}-3\frac{5}{23}\)
= \(13\frac{17}{345}\)
XIN LỖI NHA, MÌNH KO LÀM ĐƯỢC XONG CÂU b) , MONG BẠN THÔNG CẢM CHO MÌNH, KHI NÀO MÌNH NGHĨ RA CÂU b) MÌNH SẼ TRẢ LỜI
Tính hợp lý
a) \(\left(\frac{2}{5}\right)^6.\left(\frac{25}{4}\right)^2\)
b) \(\frac{100}{123}:\left(\frac{3}{4}+\frac{7}{12}\right)+\frac{23}{123}:\left(\frac{9}{5}-\frac{7}{15}\right)\)
\(a,\left(\frac{2}{5}\right)^6.\left(\frac{25}{4}\right)^2=\left(\frac{2}{2.3}\right)^6.\left(\frac{5}{2}\right)^4\)
\(=\frac{1}{3^6}.\frac{5^4}{2^4}=\frac{5^4}{3^6.2^4}\)
\(b,\frac{100}{123}:\left(\frac{3}{4}+\frac{7}{12}\right)+\frac{23}{123}:\left(\frac{9}{5}-\frac{7}{15}\right)\)
\(=\frac{100}{123}:\left(\frac{9+7}{12}\right)+\frac{23}{123}:\left(\frac{27-7}{15}\right)\)
\(=\frac{100}{123}:\frac{16}{12}+\frac{23}{123}:\frac{20}{15}\)
\(=\frac{100.12}{123.16}+\frac{23.15}{123.20}\)
\(=\frac{5.5.4.3.4}{41.3.4.4}+\frac{23.3.5}{41.3.4.5}\)
\(=\frac{25}{41}+\frac{23}{164}=\frac{25.4+23}{164}\)
\(=\frac{123}{164}=\frac{3}{4}\)
tính hợp lý A=\(\frac{1+3+5+...+29}{21+23+...+49}\)
A=\(\frac{\left(1+29\right)\left[\left(29-1\right):2+1\right]:2}{\left(49+21\right)\left[\left(49-21\right):2+1\right]:2}\)
A=\(\frac{30.15:2}{70.15:2}\)
A=\(\frac{30:2}{70:2}\)
A=\(\frac{15}{35}\)
A=\(\frac{3}{7}\)
Vậy A=\(\frac{3}{7}\)