1) Phân tích thành X Tử
a) 3x^2 + 13x + 10
b) x^2 - 10x + 21
c) 6x^2 - 5x + 1
Help me !! Cần gấp
1. phân tích thành x tử
a, 3x2+13x+10( tách hạng tử)
b, x2-10x+21(tách hạng tử )
c, 6x2-5x+1( tách hạng tử)
2.phân tích thành x tử
a, x8+4
b, x4+182
c,x4+3x2+4( thêm bớt x2)
d, x4-72+1( thêm bớt 2x2)
a, 3x^2 + 13x + 10
= 3x^2 + 3x + 10x + 10
= 3x(x + 1) + 10(x + 1)
= (3x + 10)(x + 1)
b, x^2 - 10x + 21
= x^2 - 3x - 7x + 21
= x(x - 3) - 7(x - 3)
= (x - 7)(x - 3)
c, 6x^2 - 5x + 1
= 6x^2 - 3x - 2x + 1
= 3x(2x - 1) - (2x - 1)
= (3x - 1)(2x - 1)
Bạn đăng 1 lần nhiều bài như vậy làm người khác nản lắm đấy =) đơn giản bài rất dài mà mik cx ko chắc là bản thân mik có đc k hay ko nên phải nản vậy thôi :)
1a)\(3x^2+13x+10=3x^2+3x+10x+10\)
\(3x\left(x+1\right)+10\left(x+1\right)=\left(3x+10\right)\left(x+1\right)\)
b)\(x^2-10x+21=x^2-3x-7x+21\)
\(=x\left(x-3\right)-7\left(x-3\right)=\left(x-7\right)\left(x-3\right)\)
c)\(6x^2-5x+1=6x^2-3x-2x+1\)
\(=3x\left(2x-1\right)-\left(2x-1\right)=\left(3x-1\right)\left(2x-1\right)\)
1,
\(a,3x^2+13x+10=3x^2+3x+10x+10\)
\(=3x\left(x+1\right)+10\left(x+1\right)\)
\(=\left(x+1\right)\left(3x+10\right)\)
\(b,x^2-10x+21=x^2-7x-3x+21\)
\(=x\left(x-7\right)-3\left(x-7\right)\)
\(=\left(x-7\right)\left(x-3\right)\)
\(c,6x^2-5x+1=6x^2-2x-3x+1\)
\(=2x\left(3x-1\right)-\left(3x-1\right)\)
\(=\left(3x-1\right)\left(2x-1\right)\)
2,
\(a,x^8+4=\left(x^4\right)^2+4x^4+2^2-4x^4\)
\(=\left(x^4+2\right)^2-4x^4\)
\(=\left(x^4+2-2x^2\right)\left(x^4+2+2x^2\right)\)
\(b,x^4+18^2=\left(x^2\right)^2+36x^2+18^2-36x^2\)
\(=\left(x^2+18\right)-36x^2\)
\(=\left(x^2+18-6x\right)\left(x^2+18+6x\right)\)
\(c,x^4+3x^2+4=x^4+4x^2+4-x^2\)
\(=\left(x^2+2\right)-x^2\)
\(=\left(x^2+2-x\right)\left(x^2+2+x\right)\)
Toán Học Team
phân tích đa thức thành nhân tử
1)ab(a+b)-2bc(b-2c)-2ca(a-2c)-4abc
2)a^2b+2ab^2+4b^2c+4bc^2+2c^2a+ca^2+4abc
3)(x^2-6x+5)(x^2-10x+21)-20
4)4(x^2+x+1)^2+5x(x^2+x+1)+x^2
5)x^4+5x^3-12x^2+5x+1
6)(x+1)(x-4)(x+2)(x-8)+4x^2
7)4x^3+5x^2+10x-12
8)(x+3)^2(3x+8)(3x+10)-8
9)(4x+1)(12x-1)(3x+2)(x+1)-4
Help me ~~~
Phân tích đa thức thành nhân tử
a)x^4-3x^3+4x^2-3x+1
b)x^4+2021x^2-2020x+2021
c)6x^4+5x^3-38x^2+5x+6
Nhanh mk tick
a) \(=x^4-x^3-2x^3+2x^2+2x^2-2x-x+1\)
\(=x^3\left(x-1\right)-2x^2\left(x-1\right)+2x\left(x-1\right)-\left(x-1\right)\)
\(=\left(x^3-2x^2+2x-1\right)\left(x-1\right)\)
\(=\left(x^3-x^2-x^2+x+x-1\right)\left(x-1\right)\)
\(=\left(x^2-x+1\right)\left(x-1\right)^2\)
c)
\(=6x^4-12x^3+17x^3-34x^2-4x^2+8x-3x+6\)
\(=6x^3\left(x-2\right)+17x^2\left(x-2\right)-4x\left(x-2\right)-3\left(x-2\right)\)
\(=\left(6x^3+17x^2-4x-3\right)\left(x-2\right)\)
\(=\left(6x^3+18x^2-x^2-3x-x-3\right)\left(x-2\right)\)
\(=\left(6x^2-x-1\right)\left(x+3\right)\left(x-2\right)\)
\(=\left(2x-1\right)\left(3x+1\right)\left(x+3\right)\left(x-2\right)\)
b)
\(=x^4+1011x^2+1011+\left(1010x^2-2020x+1010\right)\)
\(=x^4+1011x^2+1011+1010\left(x^2-2x+1\right)\)
\(=x^4+1011x^2+1011+1010\left(x-1\right)^2\)
CÓ: \(x^4+1010\left(x-1\right)^2+1011x^2\ge0\forall x\)
=> \(x^4+1010\left(x-1\right)^2+1011x^2+1011\ge1011>0\forall x\)
=> ĐA THỨC b > 0 => Ko ph được thành nhân tử.
Phân tích đa thức thành nhân tử
a) \(x^2-6x+4\)
b) \(x^2-4x+3\)
c) \(6x^2-5x+1\)
d) \(3x^2+13x-10\)
Bài làm:
a) \(x^2-6x+4=\left(x^2-6x+9\right)-5=\left(x-3\right)^2-\left(\sqrt{5}\right)^2\)
\(=\left(x-3-\sqrt{5}\right)\left(x-3+\sqrt{5}\right)\)
b) \(x^2-4x+3=x^2-x-3x+3=\left(x-1\right)\left(x-3\right)\)
c) \(6x^2-5x+1=6x^2-3x-2x+1=\left(2x-1\right)\left(3x-1\right)\)
d) \(3x^2+13x-10=3x^2+15x-2x-10=\left(x-5\right)\left(3x-2\right)\)
Cần gấp TvT mk thanks trước nha ^^
Phân tích thành nhân tử:
ab(a + b) - 2bc(b - 2c) - 2ca(a - 2c) - 4abca2b + 2ab2 +4b2c +4bc2 + 2c2a +ca2 + 4abc(x2 - 6x + 5)(x^2 - 10x +21) - 204(x^2 +x + 1)2 + 5x(x^2 +x + 1) + x^2x^4 + 5x^3 - 12x^2 + 5x +14x^3 + 5x^2 + 10x -12(x + 3)2 (3x + 8)(3x + 10) - 8 ( 4x + 1 )( 12x - 1)(3x + 2)(x + 1) - 4Cho a, b, c khác 0 thỏa: a3 + 8b3 + 27c3 = 18abcTính K = \(\left(1+\frac{a}{2b}\right)\left(1+\frac{2b}{3c}\right)\left(1+\frac{3c}{a}\right)\)
phân tích đa thức thành nhân tử
a, 5x^3-45x
b, 3x^2 - 7x -6
c, 10x^2 - 29x+10
d, x^5+x+1
e, (x+1)(x+3)(x+5)(x+7)+15
mn giúp mk vs nha mk đang cần gấp :)
Ta có : 5x3 - 45x
= 5x(x2 - 9)
= 5x(x - 3)(x + 3)
b ) Ta có : 3x2 - 7x - 6
= 3x2 - 9x + 2x - 6
= 3x (x - 3) + 2(x - 3)
= (x - 3)(3x + 2)
bài 1: phân tích đa thức thành nhân tử bằng cách ( phân tích đa thức bậc 2 )
a, x^2 + 5x + 4
b, x^2 - 6x + 5
c, x^2 + 7x + 12
d, 2x^2 - 5X + 3
e, 7x - 3x^2 - 4
f, x^2 - 10x + 16
a, x^2 + 5x +4
= x^2 + 1x + 4x + 4
= (x^2 + 1x) + (4x + 4)
= x ( x + 1 ) + 4 ( x + 1 )
= (x + 1) (x + 4)
b, x^2 - 6x + 5
= x^2 - 1x - 5x + 5
= (x^2 - 1x) - (5x - 5)
= x (x - 1) - 5 (x - 1)
= (x - 1) (x - 5)
c, x^2 + 7x + 12
= x^2 + 3x + 4x + 12
= (x^2 + 3x) + (4x + 12)
= x (x + 3) + 4 (x + 3)
= (x + 3) (x + 4)
d, 2x^2 - 5x + 3
= 2^x2 - 2x - 3x + 3
= 2x (x - 1) - 3 (x - 1)
= (x-1) (2x - 3)
e, 7x - 3x^2 - 4
= 3x + 4x - 3x^2 - 4
= (3x - 3x^2) + (4x - 4)
= 3x (1 - x) + 4 (x - 1)
= 3x (1-x) - 4 (1 - x)
= (1 - x) (3x - 4)
f, x^2 - 10x + 16
= x^2 - 2x - 8x + 16
= (x^2 - 2x) - (8x - 16)
= x (x - 2) - 8 (x - 2)
= (x - 2) (x - 8)
a, (x+1)(x+4)
b,(x-5)(x-1)
c,(x+3)(x+4)
d,(2x-3)(x-1)
e,(-3x+4)(x-1)
f, (x-8)(x-2)
1) x2 -7x + 10 = x2 - 2x - 5x + 10 = x(x - 2) - 5(x - 2) = (x - 5)(x - 2)
2) x2 + 3x + 2 = x2 + 2x + x + 2 = x(x + 2) + (x + 2) = (x + 1)(x + 2)
3) x2 - 7x + 12 = x2 - 3x - 4x + 12 = x(x - 3) - 4(x - 3) = (x - 3)(x - 4)
4) x2 + 7x + 12 = x2 + 3x + 4x + 12 = x(x + 3) + 4(x + 3) = (x + 3)(x + 4)
5) 16x - 5x2 - 3 = 15x - 5x2 + x - 3 = -5x(x - 3) + (x - 3) = (x - 3)(1 - 5x)
6) 6x2 + 7x - 3 = 6x2 - 2x + 9x - 3 = 2x(3x - 1) + 3(3x - 1) = (2x + 3)(3x - 1)
7) 3x2 - 3x - 6 = 3x2 - 6x + 3x - 6 = 3x(x - 2) + 3(x - 2) = (x - 2)(3x + 3) = 3(x - 2)(x + 1)
8) 3x2 + 3x - 6 = 3x2 - 3x + 6x - 6 = 3x(x - 1) + 6(x - 1) = (x - 1)(3x + 6) = 3(x - 1)(x + 2)
9) 6x2 - 13x + 6 = 6x2 - 9x - 4x + 6 = 3x(2x - 3) - 2(2x - 3) = (3x - 2)(2x - 3)
10) 6x2 + 15x + 6 = 6x2 + 12x + 3x + 6 = 6x(x + 2) + 3(x + 2) = (x + 2)(6x + 3) = 3(x + 2)(3x + 1)
11) 6x2 - 20x + 6 = 6x2 - 18x - 2x + 6 = 6x(x -3) - 2(x - 3) = (6x - 2)(x - 3) = 2(3x - 1)(x - 3)
12) 8x2 + 5x - 3 = 8x2 + 8x - 3x - 3 = 8x(x + 1) - 3(x + 1) = (x + 1)(8x - 3)
phân tích thành nhân tử : a) x^2 + 6x + 9 b) x^3 + 3x^2 + 3x + 1 c) 8x^3 - 1/8 d) 10x - 25 - x^2 e) 1/25x^2 - 64y^2
a) \(x^2\)\(+\)\(6x\)\(+\)\(9\)
\(=\left(x+3\right)^2\)
b) \(x^3\)\(+\)\(3x^2\)\(+\)\(3x\)\(+\)\(1\)
\(=\left(x+1\right)^3\)
c) \(8x^3\)\(-\)\(\frac{1}{8}\)
\(=\left(2x-\frac{1}{2}\right)\left(4x^2+x+\frac{1}{4}\right)\)
d) \(10x\)\(-\)\(25\)\(-\)\(x^2\)
\(=\)\(-x^2\)\(+\)\(10\)\(-\)\(25\)
\(=-\left(x^2-10+25\right)\)
\(=-\left(x-5\right)^2\)
e) \(\frac{1}{25}x^2\)\(-\)\(64y^2\)
=\(\left(\frac{1}{25}x-8y\right)\left(\frac{1}{5}x+8y\right)\)