13/120+11/24-17/30

13/120+55/120-68/120

68/120-68/120

0

18/100+9/45-2/25

TL:

= -3/17 - 2/13 - (-20/17) - 11/13

= -3/17 + 20/17 - ( 2/13 + 11/13)

= 1 - 1 = 0

_HT_

a) \(\dfrac{\dfrac{3}{14}-\dfrac{3}{17}+\dfrac{3}{19}}{\dfrac{5}{19}+\dfrac{5}{14}-\dfrac{5}{17}}=\dfrac{3\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}{5\left(\dfrac{1}{14}-\dfrac{1}{17}+\dfrac{1}{19}\right)}=\dfrac{3}{5}\)

c) \(\dfrac{\dfrac{2}{7}+\dfrac{2}{5}+\dfrac{2}{17}-\dfrac{2}{193}}{\dfrac{3}{7}+\dfrac{3}{5}+\dfrac{3}{17}-\dfrac{3}{293}}=\dfrac{2\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}{3\left(\dfrac{1}{7}+\dfrac{1}{5}+\dfrac{1}{17}-\dfrac{1}{193}\right)}=\dfrac{2}{3}\)

d) 

\(a,\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{17}{-35}\)

=\(-\frac{5}{13}+\left(\frac{3}{17}+\frac{14}{17}\right)+\left(\frac{-18}{35}+\frac{-17}{35}\right)\)

= \(-\frac{5}{13}+1+\left(-1\right)\)

=\(-\frac{5}{13}\)

\(b,\frac{-3}{8}.\frac{1}{6}+\frac{3}{-8}.\frac{5}{6}+\frac{-10}{6}\)

=\(\frac{-3}{8}.\left(\frac{1}{6}+\frac{5}{6}\right)+\frac{-10}{6}\)

=\(\frac{-3}{8}.1+\frac{-10}{6}\)

=\(-\frac{49}{24}\)

\(c,\frac{-4}{11}.\frac{5}{15}.\frac{11}{-4}\)

=\(\left(\frac{-4}{11}.\frac{11}{-4}\right).\frac{1}{3}\)

=\(1.\frac{1}{3}=\frac{1}{3}\)

\(d,\frac{13}{8}+\frac{1}{8}:\left(0,75-\frac{1}{2}\right)-25\%.\frac{1}{2}\)

=\(\frac{13}{8}+\frac{1}{8}:\left(\frac{3}{4}-\frac{1}{2}\right)-\frac{1}{4}.\frac{1}{2}\)

=\(\frac{13}{8}+\frac{1}{8}:\frac{1}{4}-\frac{1}{8}\)

=\(\frac{13}{8}+\frac{1}{2}+\frac{-1}{8}\)

=\(\left(\frac{13}{8}+\frac{-1}{8}\right)+\frac{1}{2}\)

=\(\frac{3}{2}+\frac{1}{2}=2\)

\(e,\frac{-1}{2^2}-\left(-2\right)^2-5\)

=\(\frac{-1}{4}-4-5\)

=\(-\frac{37}{4}\)

\(f,\frac{121}{3}-\frac{5}{7}:\left(24-\frac{23}{57}\right)\)

=\(\frac{121}{3}-\frac{5}{7}:\frac{1345}{57}\)

=\(\frac{121}{3}-\frac{57}{1883}\)

\(\approx40,4\)

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địt con mẹ bọn onlinemath sex

\(\dfrac{17}{17}+\dfrac{-13}{13}+\left(\dfrac{-2}{3}\right)\)

\(=1+\left(-1\right)+\left(\dfrac{-2}{3}\right)\)

\(=0+\left(\dfrac{-2}{3}\right)\)

\(=\dfrac{2}{3}\)