-5 x ( x + 1/5 ) - 1/2 x ( x - 2/3 ) = 3/2x - 5/6

<=> -5x^2 - x - 1/2 x^2 + 1/3 = 3/2x - 5/6

<=> -3x^2 - x + 1/3 = 3/2x - 5/6

<=> -3x^2  - 5/2 x + 7/6 = 0

<=> ( 3x - 1 ) ( 6x + 7 ) = 0

=> x = 1/3 ; x = -7/6 .

Vậy x = 1/3 , x = -7/6.

\(\frac{x}{2}-\frac{11}{5}=\frac{7}{5}.\frac{64}{49}\)

\(\frac{x}{2}-\frac{11}{5}=\frac{64}{35}\)

\(\frac{x}{2}=\frac{64}{35}+\frac{11}{5}\)

\(\frac{x}{2}=\frac{141}{35}\)

\(\Leftrightarrow x.35=2.141\)

\(\Leftrightarrow x.35=282\)

\(\Leftrightarrow x=282:35\)

\(\Leftrightarrow x=\frac{282}{35}\)

x/2 - 11/5 = 7/5.64/49

=> x/2 - 11/5 = 64/35

=> x/2 = 64/35 + 11/5

=> x/2 = 141/35

=> 35x = 2.141

=> 35x = 282

=> x = 282 : 35 = 282/35

(đã xóa câu trả lời) _by tth

\(x+y=5\)

,=>  \(\left(x+y\right)^3=125\)

<=>  \(x^3+y^3+3xy\left(x+y\right)=125\)

<=>  \(x^3+y^3+3.3.5=125\)

<=> \(x^3+y^3=80\)

Vậy...

1/4 + 1/3 : (2x - 1) = -5

=> 1/3 : (2x - 1) = -21/4

=> 2x - 1 = -63/4

=> 2x = -59/4

=> x = -59/8

\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)

\(\frac{1}{3}:\left(2x-1\right)=\left(-5\right)-\frac{1}{4}\)

\(\frac{1}{3}:\left(2x-1\right)=\frac{-21}{4}\)

\(2x-1=\frac{1}{3}:\frac{-21}{4}\)

\(2x-1=\frac{-4}{63}\)

\(2x=\frac{-4}{63}+1\)

\(2x=\frac{59}{63}\)

\(x=\frac{59}{63}:2\)

\(x=\frac{59}{126}\)

1/4 + 1/3 : ( 2x - 1 ) = -5

1/3 : ( 2x - 1 ) = - 5 - 1/4

1/3 : ( 2x - 1 ) = -21/4

2x - 1 = 1/3 : ( - 21/4 )

2x - 1 = -4/63

2x = ( -4/63 ) + 1

2x = 59/63

x = 59/126

Vậy x = 59/126

Ta có \(\frac{3}{2}-\frac{5}{2}.\left(1,2x-3\right)^2=-0,9\)

\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{3}{2}+0,9\)

\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{21}{2}\)

\(\Rightarrow\left(1,2x-3\right)^2=\frac{21}{5}\)

đề sai hay mình sai ????

12x+3.2³=2³.x-4.3²

12x+3.8=8.x-4.9

12x+24=8x-36

12x-8x=36-24

4x=12

x=12:4=3

      \(12x+3\cdot2^3=2^3x-4\cdot3^2\)

\(\Rightarrow12x+24=8x-36\)

\(\Rightarrow12x-8x=-36-24\)

\(\Rightarrow4x=-60\)

\(\Rightarrow x=-15\)

Vay x=-15

k mk nhA