Chung minh rang:
a,1-1/2+1/3-1/4+...+1/199-1/200=1/101+1/102+...+1/200
chung minh rang 1-1/2+1/3-1/4+...+1/99-1/200=1/101+1/102+...+1/199+1/200
chung minh rang 1-1/2+1/3-1/4+.....+1/199-1/200=1/101+1/102+.....+1/200
bien doi so sdau tien
1-1/2+1/3-1/4+...+1/199-1/200
(1+1/3+1/5+...+1/199)-(1/2+1/4+1/6+...+1/200)
(1+1/2+1/3+1/4+1/5+1/6+...+1/199+1/200)-2*(1/2+1/4+1/6+,,,+1/200)
(1+1/2+1/3+1/4+...+1/200)-((1+1/2+1/3+...+1/100)
1/101+1/102+1/103+...+1/200=so bewn canh
Chứng minh :1-1/2+1/3-1/4+...+1/199-1/200=1/101+1/102+....+1/200
Chứng minh:1-1/2+1/3-1/4+..........+1/199-1/200=1/101+1/102+...........+1/200
Chứng minh rằng ; 1-1/2+1/3-1/4+...+1/199-1/200=1/101+1/102+000+1/200
\(VT=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(VT=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)-2.\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)\)
\(VT=\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}+\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(VT=\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}+\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(VT=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}=VP\)=> ĐPCM
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}\)
\(=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{199}+\frac{1}{200}-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{200}\right)\)
\(=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{199}+\frac{1}{200}-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\left(\text{đ}pcm\right)\)
mình ko hiểu cánh làm của các bạn
ghi thật chi tiết cho mình hiểu được ko
Chứng minh rằng :
1-1/2+1/3-1/4+.......+1/199-1/200 = 1/101+ 1/102+.......+1/200
Chứng minh rằng:
1 - 1/2 + 1/3 -1/4 + ... + 1/199 - 200= 1/101 + +1/102 + 1/103 + ... + 1/200
Làm ơn giải giúp mình nhanh nhanh nhé, mình đang cần gấp, ai giải được mình k cho
sory nhin nham mik rõ đầu bài rồi để mik giải cho
chứng minh rằng :1-1/2+1/3-1/4+...+1/199-1/200 = 1/101+1/102+1/103+1/104+...+1/200.
1/101+1/102+..+1/200=(1+1/2+1/3+...+1/100)+1/101+1/102+1/103+...+1/200-(1+1/2+1/3+...+1/100)
=(1/2+1/4+1/6+...+1/200)+(1+1/3+1/5+...+1/199)-2(1/2+1/4+1/6+...+1/200)
=(1+1/3+1/5+...+1/199)-(1/2+1/4+1/6+...+1/200)
=1-1/2+1/3-1/4+1/5-1/6+...+1/199-1/200
suy ra ĐPCM
nguyen thieu cong thanh ơi cho mình hỏi:
sao lại là :2(1/2+1/4+1/6+...+1/200)
phải là : (1/2+1/4+1/6+...+1/200) chứ
đúng hok?????
cmr : -1/2 + 1/3 + -1/4 + ..... + 1/199 + -1/200 = 1/101 + 1/102 + .... + 199 + 1/200