8 mu 10 - 8 mu 9 -8 mu 8 /55
8 mu 10 - 8 mu 9-8 mu 8/ 55
81 mu 7-27 mu 9-9 mu 13/45
10 mu9 +10 mu 8+10 mu7/555
bai 1 ;chung minh rang abcd chia het 99 thi ab cong cd chia het 99 va nguoc lai
bai 2;a.8 mu 10 tru 8 mu 9 tru 8 mu 8 chia het 55
b.7mu 6 cong 7 mu 5 tru 7 mu 4 chia het 11
d.10 mu 9 cong10 mu 8 cong 10 mu 7 chia het 555
c.81mu 7 cong 27 mu 9 tru 9 mu 13 chia het 45
Bài 1:
Ta có: abcd=100ab+cd=99ab+(ab+cd)
Vì 99 chia hết cho 99 =)ab chia hết cho 99=>(ab+cd) chia hết cho 99
Hay abcd chia hết cho 99;(ab+cd) chia hết cho 99
Vậy nếu abcd chia hết cho 99 thì (ab+cd) chia hết cho 99 và ngược lại
CMR
8 mu 10 -8 mu 9- 8 mũ 8 chia hết cho 55
ai dung minh se tick cho
\(8^{10}-8^9-8^8=8^8\left(8^2-8-1\right)=8^8\left(64-8-1\right)=55.8^8⋮55\)
\(=8^8\left(8^2-8-1\right)=8^8.65⋮65\)
cac bn giup mk nka
rut gon a=4 mu 5. 9 mu 4 - 2 . 6mu 9/2 mu 10. 3 mu 8+ 6mu 8 .20
1) chung to rang
a) 76 + 75 - 74 chia het cho 11
b )278 - 321 chia het cho 26
c) 812 - 2 33 - 230 chia het cho 55
2) tim chu so tan cung cua tong
30 mu 4 mu 1 mu 9 mu 9 mu 9 + 15 mu 5 mu 1 mu 9 mu 9 mu 9
a) 76 + 75 - 74=74.72+75.7-74.1 =74.(72+7-1)=74.55
vì 55 chia hết cho 11 nên 74.55 cũng chia hết cho 11
=> 76 + 75 - 74 chia hết cho 11
b)278 - 321=(33)8-321=324-321=321.33-321.1=321.(33-1)=321.26
=>278 - 321 chia het cho 26
c) 812 - 2 33 - 230
=(23)12-233-230=236-233-230=230.26-230.23-230.1=230.(26-23-1)
=230.55
=> 812 - 2 33 - 230 chia het cho 55
a) 76 + 75 - 74 = 74.(72 + 7 -1) = 74.5.11
Vậy chia hết cho 11
1) chung to rang
a) 76 + 75 - 74 chia het cho 11
b )278 - 321 chia het cho 26
c) 812 - 2 33 - 230 chia het cho 55
2) tim chu so tan cung cua tong
30 mu 4 mu 1 mu 9 mu 9 mu 9 + 15 mu 5 mu 1 mu 9 mu 9 mu 9
a) 76 + 75 - 74=74.72+75.7-74.1 =74.(72+7-1)=74.55
vì 55 chia hết cho 11 nên 74.55 cũng chia hết cho 11
=> 76 + 75 - 74 chia hết cho 11
b)278 - 321=(33)8-321=324-321=321.33-321.1=321.(33-1)=321.26
=>278 - 321 chia het cho 26
c) 812 - 2 33 - 230
=(23)12-233-230=236-233-230=230.26-230.23-230.1=230.(26-23-1)
=230.55
=> 812 - 2 33 - 230 chia het cho 55
chung minh rang
5 mu 15 .5 mu 14+5mu 13 : cho 21
10 mu 8+ 10 muu 7 +10 mu 6 :55
[n +3] . [n+24] :2
5 mu 10 *9+5 mu 9 *8
\(5^{10}.9+5^9.8\)
\(=5^9.5.9+5^9.8\)
\(=5^9.\left(45+8\right)\)
\(=5^9.53\)
còn lại thì mình ko biết
Tính A= 2 mu 10 -2 mu 9 - 2 mu 8 - .... - 2 mu 2 - 2 -1
10-[(8 mu 2 .8).5+(2 mu 3.10+8)]:28
\(10-\left[\left(8^2.8\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[8^3.5+\left(2^4.5+2^3\right)\right]:28\)
\(=10-\left[8^3.5+\left(2^3.\left(10+1\right)\right)\right]:28\)
\(=10-\left[2^9.5+2^3.11\right]:28\)
\(=10-\left[2^3.\left(8.5+11\right)\right]:28\)
\(=10-\left[8.51\right]:28\)
\(=10-408:28\)
\(=10-\frac{102}{7}\)
\(=\frac{-32}{7}\)