cho N=\(\left(\frac{1}{x^2+x}-\frac{2-x}{x+1}\right)\cdot\frac{3x}{x^2-2x+1}\)
tìm x để N nguyên
Những câu hỏi liên quan
Cho N = \(\frac{3x+\sqrt{9x}-3}{x+\sqrt{x}-2}-\frac{\sqrt{x}+1}{\sqrt{x}+2}+\frac{\sqrt{x}-2}{\sqrt{x}}\cdot\left(\frac{1}{1-\sqrt{x}}-1\right)\)
a, Rút gọn N
b, Tìm x nguyên để N nguyên
c, Tìm x để N = \(\sqrt{x}\)
Cho N = \(\frac{3x+\sqrt{9x}-3}{x+\sqrt{x}-2}-\frac{\sqrt{x}+1}{\sqrt{x}+2}+\frac{\sqrt{x}-2}{\sqrt{x}}\cdot\left(\frac{1}{1-\sqrt{x}}-1\right)\)
a, Rút gọn N
b, Tìm x nguyên để N nguyên
c, Tìm x để N = \(\sqrt{x}\)
\(P=\left(\frac{x^2-2x}{2x^2+8}-\frac{2x^2}{8-4x+2x^2-x^3}\right)\cdot\left(1-\frac{1}{x}-\frac{2}{x^2}\right),vớix\ne0;x\ne2\)
1) Rút gọn P
2) Tìm giá trị nguyên của x để biểu thức A=2.P nhận giá trị nguyên
A,left(frac{x+1}{x-1}-frac{x-1}{x+1}right):left(frac{1}{x+1}-frac{x}{1-x}+frac{2}{x^2-1}right)frac{4x}{left(x+1right)^2}B,frac{2+x}{2-x}:frac{4x^2}{4-4x+x^2}cdotleft(frac{2}{2-x}-frac{4}{8+x^2}cdotfrac{4-2x+x^2}{2-x}right)frac{1}{2x}C,left[left(frac{3}{x-y}+frac{3x}{x^2-y^2}right):frac{2x+y}{x^2+2xy+y^2}right]cdotfrac{x-y}{3}xyChứng minh đẳng thức ( tìm x)mọi người giải dùm mình cảm ơn
Đọc tiếp
\(A,\left(\frac{x+1}{x-1}-\frac{x-1}{x+1}\right):\left(\frac{1}{x+1}-\frac{x}{1-x}+\frac{2}{x^2-1}\right)=\frac{4x}{\left(x+1\right)^2}\)
\(B,\frac{2+x}{2-x}:\frac{4x^2}{4-4x+x^2}\cdot\left(\frac{2}{2-x}-\frac{4}{8+x^2}\cdot\frac{4-2x+x^2}{2-x}\right)=\frac{1}{2x}\)
\(C,\left[\left(\frac{3}{x-y}+\frac{3x}{x^2-y^2}\right):\frac{2x+y}{x^2+2xy+y^2}\right]\cdot\frac{x-y}{3}=xy\)
Chứng minh đẳng thức ( tìm x)
mọi người giải dùm mình cảm ơn
a VT=.\(\left(\frac{x+1}{x-1}-\frac{x-1}{x+1}\right):\left(\frac{1}{x+1}-\frac{x}{1-x}+\frac{2}{x^2-1}\right)\)
=\(\frac{\left(x+1\right)^2-\left(x-1\right)^2}{\left(x+1\right)\left(x-1\right)}:\frac{x-1+x\left(x-1\right)+2}{\left(x+1\right)\left(x-1\right)}\)
\(=\frac{x^2+2x+1-x^2+2x-1}{\left(x+1\right)\left(x-1\right)}.\frac{\left(x+1\right)\left(x-1\right)}{x^2+2x+1}\)
\(=\frac{4x}{\left(x+1\right)^2}\)=VP
b.VT\(=\frac{2+x}{2-x}.\frac{\left(2-x\right)^2}{4x^2}.\left(\frac{2}{2-x}-\frac{4}{\left(x+2\right)\left(x^2-2x+4\right)}.\frac{4-2x+x^2}{2-x}\right)\)
=\(\frac{4-x^2}{4x^2}.\left(\frac{2}{2-x}-\frac{4}{4-x^2}\right)=\frac{4-x^2}{4x^2}.\frac{2\left(2+x\right)-4}{4-x^2}\)
=\(\frac{2x}{4x^2}=\frac{1}{2x}\)=VP
c VT=.\(\left[\left(\frac{3}{x-y}+\frac{3x}{x^2-y^2}\right).\frac{\left(x+y\right)^2}{2x+y}\right].\frac{x-y}{3}\)
\(=\left[\frac{3\left(x+y\right)+3x}{\left(x+y\right)\left(x-y\right)}.\frac{\left(x+y\right)^2}{2x+y}\right].\frac{x-y}{3}\)
\(=\frac{3\left(2x+y\right)\left(x+y\right)^2}{\left(x+y\right)\left(x-y\right)\left(2x+y\right)}.\frac{x-y}{3}\)
\(=x+y=\)VP
Vậy các đẳng thức được chứng minh
=
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Cho biểu thức: \(P=\left(\frac{x+1}{x-1}-\frac{4x^2}{1-x^2}-\frac{x-1}{x+1}\right)\cdot\frac{x^2-2x+1}{4x^2-4}\)
a) Rút gọn P
b) Tính P khi \(\left|x-\frac{2}{3}\right|=\frac{1}{3}\)
c) Tìm x nguyên để P có giá trị nguyên
d) Tìm x để P > 1
e) Tìm m để x thỏa mãn P = m - 1
a) Đk \(x\ne\pm1\), sau khi rút gọn ta được: (bạn tư làm)
\(P=\frac{x}{x+1}\)
b) Khi \(\left|x-\frac{2}{3}\right|=\frac{1}{3}\) thì hoặc \(x-\frac{2}{3}=\frac{1}{3}\) hoặc \(x-\frac{2}{3}=-\frac{1}{3}\)
Hay là \(x=1\) hoặc \(x=\frac{1}{3}\)
Do để P có nghĩa thì \(x\ne\pm1\) nên \(x=\frac{1}{3}\), khi đó:
\(P=\frac{\frac{1}{3}}{\frac{1}{3}+1}=\frac{1}{4}\)
c) P > 1 khi \(\frac{x}{x+1}>1\)
\(\Leftrightarrow1-\frac{1}{x+1}>1\)
\(\Leftrightarrow\frac{1}{x+1}< 0\)
\(\Leftrightarrow x< -1\)
e) Đề không rõ ràng
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\(P=\left[\left(\frac{1}{X^2}+1\right)\cdot\frac{1}{x^2+2x+1}+\frac{2}{\left(x+1\right)^3}\cdot\left(\frac{1}{x}+1\right)\right]\cdot\frac{x-1}{x^3}\)
a. Rút gọn P
b, tìm x để P>0
c. tìm x để P=4
d. tim x\(\in\)z để P \(\in\)z
I don't now
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\(P=\left[\left(x^4-x+\frac{x-3}{x^3+1}\right)\cdot\left(\frac{\left(x^3-2x^2-2x-1\right)\cdot\left(x+1\right)}{x^9+x^7-3x^2-3}\right)+1-\frac{2\left(x+6\right)}{x^2+1}\right]\cdot\frac{4x^2+4x+1}{\left(x+3\right)\left(4-x\right)}\)
a, Tìm ĐKXD của P
b,Rút Gọn P
c,Chứng Minh Với các giá trị của x mà biểu thức P có nghĩa thì \(-5\le P\le0\)
tìm xa) frac{x-1}{2}+frac{x-2}{5}frac{1}{4}+frac{x-7}{10}b) 3-frac{2}{2x-3}frac{2}{5}+frac{1}{2x-3}-frac{3}{2}c)7cdotleft(x-1right)+2xcdotleft(1-xright)0d) frac{x+1}{2008}+frac{x+2}{2017}+frac{x+3}{2016}frac{x+10}{2009}+frac{x+11}{2008}+frac{x+12}{2007}e) frac{2}{left(x-1right)cdotleft(x-3right)}+frac{5}{left(x-3right)cdotleft(x-8right)}+frac{12}{left(x-8right)cdotleft(x-20right)}-frac{1}{x-20}frac{-3}{4}
Đọc tiếp
tìm x
a) \(\frac{x-1}{2}+\frac{x-2}{5}=\frac{1}{4}+\frac{x-7}{10}\)
b) \(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{1}{2x-3}-\frac{3}{2}\)
c)\(7\cdot\left(x-1\right)+2x\cdot\left(1-x\right)=0\)
d) \(\frac{x+1}{2008}+\frac{x+2}{2017}+\frac{x+3}{2016}=\frac{x+10}{2009}+\frac{x+11}{2008}+\frac{x+12}{2007}\)
e) \(\frac{2}{\left(x-1\right)\cdot\left(x-3\right)}+\frac{5}{\left(x-3\right)\cdot\left(x-8\right)}+\frac{12}{\left(x-8\right)\cdot\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
thực hiện phép tính
a) (x3+8y3):(2y+x) b.frac{a-1}{2left(a-4right)}+frac{a}{a-4} c. (x3+3x2y+3xy2+y3):(2x+2y)
d. (x-5)2+(7-x)(x+2) e.frac{3x}{x-2}-frac{2x+1}{2-x} f. left(frac{x+2}{x+1}-frac{2x}{x-1}right)cdotfrac{3x+3}{x}+frac{4x^2+x+7}{x^2-x}
g.left(frac{1}{x+1}-frac{3}{x^{3^{ }}+1}+frac{3}{x^2-x+1}right)cdotleft(frac{3x^2-3x+3}{left(x+1right)left(x+2right)}right) h.frac{1}{3x-2}-frac{1}{3x+2}-frac{3x+6}{4-9x^2}
Nguyễn Nam giúp giùm
Đọc tiếp
thực hiện phép tính
a) (x3+8y3):(2y+x) b.\(\frac{a-1}{2\left(a-4\right)}+\frac{a}{a-4}\) c. (x3+3x2y+3xy2+y3):(2x+2y)
d. (x-5)2+(7-x)(x+2) e.\(\frac{3x}{x-2}-\frac{2x+1}{2-x}\) f. \(\left(\frac{x+2}{x+1}-\frac{2x}{x-1}\right)\cdot\frac{3x+3}{x}+\frac{4x^2+x+7}{x^2-x}\)
g.\(\left(\frac{1}{x+1}-\frac{3}{x^{3^{ }}+1}+\frac{3}{x^2-x+1}\right)\cdot\left(\frac{3x^2-3x+3}{\left(x+1\right)\left(x+2\right)}\right)\) h.\(\frac{1}{3x-2}-\frac{1}{3x+2}-\frac{3x+6}{4-9x^2}\)
Nguyễn Nam giúp giùm
) \(\dfrac{x^3+8y^3}{2y+x}\)
\(=\dfrac{x^3+\left(2y\right)^3}{x+2y}\)
\(=\dfrac{\left(x+2y\right)\left[x^2+x.2y+\left(2y\right)^2\right]}{x+2y}\)
\(=x^2+2xy+4y^2\)
b) \(\dfrac{a-1}{2\left(a-4\right)}+\dfrac{a}{a-4}\) MTC: \(2\left(a-4\right)\)
\(=\dfrac{a-1}{2\left(a-4\right)}+\dfrac{2a}{2\left(a-4\right)}\)
\(=\dfrac{a-1+2a}{2\left(a-4\right)}\)
\(=\dfrac{3a-1}{2\left(a-4\right)}\)
c) \(\dfrac{x^3+3x^2y+3xy^2+y^3}{2x+2y}\)
\(=\dfrac{\left(x+y\right)^3}{2\left(x+y\right)}\)
\(=\dfrac{\left(x+y\right)^2}{2}\)
d) \(\left(x-5\right)^2+\left(7-x\right)\left(x+2\right)\)
\(=\left(x^2-2.x.5+5^2\right)+\left(7x+14-x^2-2x\right)\)
\(=x^2-10x+25+7x+14-x^2-2x\)
\(=39-5x\)
e) \(\dfrac{3x}{x-2}-\dfrac{2x+1}{2-x}\)
\(=\dfrac{3x}{x-2}+\dfrac{2x+1}{x-2}\)
\(=\dfrac{3x+2x+1}{x-2}\)
\(=\dfrac{5x+1}{x-2}\)
h) \(\dfrac{1}{3x-2}-\dfrac{1}{3x+2}-\dfrac{3x+6}{4-9x^2}\)
\(=\dfrac{1}{3x-2}-\dfrac{1}{3x+2}+\dfrac{3x+6}{9x^2-4}\)
\(=\dfrac{1}{3x-2}-\dfrac{1}{3x+2}+\dfrac{3x+6}{\left(3x-2\right)\left(3x+2\right)}\) MTC: \(\left(3x-2\right)\left(3x+2\right)\)
\(=\dfrac{3x+2}{\left(3x-2\right)\left(3x+2\right)}-\dfrac{3x-2}{\left(3x-2\right)\left(3x+2\right)}+\dfrac{3x+6}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\dfrac{\left(3x+2\right)-\left(3x-2\right)+\left(3x+6\right)}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\dfrac{3x+2-3x+2+3x+6}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\dfrac{3x+10}{\left(3x-2\right)\left(3x+2\right)}\)
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