(2400+4600)-3.x=1200
[(6.x-72):2-84 ] .28=5628
42x=39.42-37.42
Tìm số tự nhiên x,biết:
a)(2600+6400)-3.x=1200
b)[(6.x-72):2-84].28=5628
c)2.x-138=23.32
d)42.x=39.42-37.42
a) ( 2600 + 6400 ) - 3 . x = 1200
9000 - 3 . x = 1200
3 . x = 9000 - 1200
3 . x = 7800
x = 7800 : 3
x = 2600
b) [ ( 6 . x - 72 ) : 2 - 84 ] . 28 = 5628
[ ( 6 . x - 72 ) : 2 - 84 ] = 5628 : 28
[ ( 6 . x - 72 ) : 2 - 84 ] = 201
( 6 . x - 72 ) : 2 = 201 + 84
( 6 . x - 72 ) : 2 = 285
( 6 . x - 72 ) = 285 . 2
( 6 . x - 72 ) = 570
6 . x = 570 + 72
6 . x = 642
x = 642 : 6
x = 107
c) 2 . x - 138 = 23 . 32
2 . x - 138 = 8 . 9
2 . x - 138 = 72
2 . x = 72 + 138
2 . x = 210
x = 210 : 2
x = 105
d, 42 . x = 39 . 42 - 37 . 42
42 . x = 42 . ( 39 - 37 )
42 . x = 42 . 2
\(\Rightarrow\) x = 2
Tìm số tự nhiên x, biết:
a) (2600 + 6400) - 3.x = 1200; b) [(6.x - 72) : 2 -84] .28 = 5628;
c) 2x - 138 = 23.32; d) 42x = 39.42 - 37.42.
kb nhé !!!
a) (2600 + 6400) - 3.x = 1200 c)2x-138=2^3 . 3^2
9000 - 3.x=1200 2x-138=8.9
3.x=9000-1200 2x-138=72
3.x=7800 2x=72+138
x=7800:3 2x=210
x=2600 x=210:2
b) [(6x-72):2-84].28=5628 x=105
[(6x-72):2-84]=5628:28 d)42x = 39.42-37.42
(6x-72):2-84=201 42x = (39-37).42
(6x-72):2=201+84 42x = 2.42
(6x-72):2=285 42x=84
6x-72=285.2 x=84:42
6x-72=570 x=2
6x=570+72
6x=642
x=642:6
x=107
a, ( 2600 + 6400 ) - 3x = 1200
=> 9000 - 3x - 1200
=> 3x = 9000 - 1200 = 7800
=> x = 7800 : 3 = 2600
b, [( 6x - 72) : 2 - 84] .28 = 5628
=> (6x - 72 ) : 2 - 84 = 5628 : 28 = 201
=> ( 6x - 72) : 2 = 201 + 84 = 285
=> 6x - 72 = 285 x 2 = 570
=> 6x = 570 + 72 = 642
=> x = 642 : 6 = 107
Tìm x :
( x-2 ) . 3 = 18
135 - 3 (x+1)=30
(123-x)-72=28
(158-x):7=20
42.x=39.42-37.42
( x-2) .3 =18 135-3(x+1)=30
(x-2) =18:3 3(x+1)=135-30
(x-2) =6 3(x+1)=105
x =6+2 x+1 =105:3
x =8 x+1 =35
x =35-1
x =34
(123-x)-72=28 (158-x):7=28
(123-x) =28+72 (158-x) =28.7
(123-x) =100 (158-x) =784
x =123-100 x =158-784
x =23 x =-626
42.x=39.42-37.42
42.x=42.(39-37)
42.x=42.2
x=42.2:42
x =2
bài này dài lắm đó k mik nha
( x - 2 ) . 3 = 18 135 - 3( x + 1 ) = 30 ( 123 - x ) - 72 = 28
x - 2 = 18 : 3 3( x + 1 ) = 135 - 30 123 - x = 28 + 72
x - 2 = 6 3( x + 1 ) = 105 123 - x = 100
x = 6 + 2 x + 1 = 105 : 3 x = 123 - 100
x = 8 x + 1 = 35 x = 23
x = 35 - 1
x = 34
( 158 - x ) : 7 = 20 42 . x = 39 . 42 - 37 . 42
158 - x = 20 x 7 42 . x = 42 . ( 39 - 37 )
158 - x = 140 42 . x = 84
x = 158 - 140 x = 84 : 42
x = 18 x = 2
a) (2600+6400)-3.x=1200b) (( 6.x-72)/2-84). 28=5628c) 2x-138 =23.32
d) 42x=39.42-37.42
làm dùng minh nhé. dễ lắm
a.(2600+6400)-3.x=1200
9000-3.x=1200
3.x=9000-1200
3.x=7800
x=7800/3
x=2600
Vậy x=2600
b.[(6.x-72):2-84].28=5628
(6.x-72):2-84=5628:28
(6.x-72):2-84=201
(6.x-72):2=201+84
(6.x-72):2=285
6.x-72=285.2
6.x-72=570
6.x=570+72
6.x=642
x=642:6
x=107
vậy x=107
c.2x-138=\(2^3\).\(3^2\)
2x-138=8.9
2x-138=72
2x=72+138
2x=210
x=210:2
x=105
vậy x=105
tìm số tự nhiên x
a, (2600+6400) - 3 . x = 1200
b,[ (6.x -72 ) : 2 - 84 ] . 28 = 5628
a,(2600+6400)-3 .x = 1200
=> 9000-3 .x= 1200
=> 3.x= 7800
=. x=2600
b, (6.x-72):2-84= 201
(6x-72):2=285
6x-72=570
6x=642
x=107
a) ( 2600 + 6400 ) - 3 . x = 1200
9000 - 3 . x = 1200
3 . x = 9000 - 1200
3 . x = 7800
x = 7800 : 3
x = 2600
tìm số tư nhiên x
a,(2600+6400)-3-x=1200
b,[(6.x-72):2-84].28=5628
a) \(\left(2600+6400\right)-3-x=1200\)
\(\Rightarrow9000-3-x=1200\)
\(\Rightarrow3-x=9000-1200\)
\(\Rightarrow3-x=7800\)
\(\Rightarrow x=7797\)
b) \(\left[\left(6\cdot x-72\right):2-84\right]\cdot28=5628\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=5628:28\)
\(\Rightarrow\left[\left(6\cdot x-72\right):2-84\right]=201\)
\(\Rightarrow\left(6\cdot x-72\right):2=201+84\)
\(\Rightarrow\left(6\cdot x-72\right):2=285\)
Đến dei bạn tự làm, ý b mình không chắc chắn lắm
Tìm số tự nhiên x, biết :
a) (2600 + 6400) - 3 . =1200;
b) [(6 . x - 72) :2 - 84] . 28 + 5628
GIÚP!!!!!!!!!
a) (2600 + 6400) - 3 . x = 1200
9000 - 3.x = 1200
3x = 9000-1200
3x = 7800
x = 7800:3
x = 2600
b) câu này ko có tổng hả Công chúa nhí nhảnh? check lại giùm Nhi nha!
a) \(\left(2600+6400\right)-3x=1200\)
\(9000-3x=1200\)
\(3x=9000-1200\)
\(3x=7800\)
\(x=\frac{7800}{3}\)
\(x=2600\)
vậy \(x=2600\)
b) \(\left[\left(6x-72\right):2-84\right].28+5628=0\)
\(\left[\frac{6x}{2}-\frac{72}{2}-84\right].28+5628=0\)
\(\left[3x-36-84\right].28=-5628\)
\(3x-120=\frac{-5628}{28}\)
\(3x-120=-201\)
\(3x=-201+120\)
\(3x=-81\)
\(x=-27\)
vậy \(x=-27\)
Bài 1 :
a) ( 2600 + 6400 ) - 3 . x = 1200
b) [( 6 . x - 72 ) : 2 - 84 ] . 28 = 5628
Mình cần gấp !! bạn nào nhanh mình tick .
a, ( 2600 + 6400 ) - 3.x = 1200
9000 - 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 2600
b, [ ( 6.x - 72 ) : 2 - 84 ] .28 = 5628
( 6.x - 72 ) : 2 - 84 = 5628 : 28
( 6.x - 72 ) : 2 - 84 = 201
( 6.x - 72 ) : 2 = 201 + 84
( 6.x - 72 ) : 2 = 285
6.x - 72 = 208 x 2
6.x - 72 = 416
6.x = 416 + 72
6.x = 488
x = 244/3
a)(2600 + 6400) - 3.x = 1200
9000 -3.x = 1200
3.x =9000-1200
3.x=7800
x=7800:3
=2600
nói chung bài bn CÔNG CHÚA XINH XẮN ĐÚNG RỒI
a) ( 2600 + 6400 ) - 3 . x = 1200
<=> 9000 - 3.x = 1200
<=> 3 . x = 9000 - 1200
<=> 3 . x = 7800
<=> x = 7800 : 3 = 2600
b) [( 6 . x - 72 ) : 2 - 84 ] . 28 = 5628
<=> [ ( 6 . x - 72 ) : 2 - 84 ] = 5628 : 28 = 201
<=> [ ( 6 . x - 72 ) : 2 = 201 - 84 = 117
<=> [ ( 6 . x - 72 ) = 117 x 2 = 234
<=> 6.x = 234 + 72 = 306
<=> x = 306 : 6 = 51
Tìm số tự nhiên x , biết rằng :
- a: (2600 + 6400 ) - 3 x X = 1200
- b: [ ( 6 x X - 72 0 : 2 - 84 ] x 28 = 5628
------------------------- Hai ý ------------------------- a và b