2020*2018+2019
__________________
2019*2019+2018
Tính nhanh
Những câu hỏi liên quan
giúp em với, em sẽ tick ạ
Tính nhanh 2020/2019 - 2019/2018 + 1/2019 x 2018
\(\dfrac{2020}{2019}-\dfrac{2019}{2018}+\dfrac{1}{2019}x2018\)
\(=\dfrac{2020}{2019}-\dfrac{2019}{2018}+\dfrac{2018}{2019}=2-\dfrac{2019}{2018}=\dfrac{2017}{2018}\)
Đúng 0
Bình luận (0)
cho A=2^2018/2^2018 +3^2019 + 3^2019/3^2019+5^2020 + 5^2020/5^2020+2^2018
cho B=1/1x2+1/3x4+1/4x5+...+1/2019x1/2020 so sánh A và B làm nhanh nha các bạn
Tính nhanh 2016/2017 nhân 2017/2018 nhân 2018/2019 nhân 2019/2020
\(\frac{2016}{2017}\)x \(\frac{2017}{2018}\)x \(\frac{2019}{2020}\)=\(\frac{504}{505}\)
đ/s:\(\frac{504}{505}\)
Đúng 0
Bình luận (0)
\(\frac{2016}{2017}\cdot\frac{2017}{2018}\cdot\frac{2018}{2019}\cdot\frac{2019}{2020}=\frac{504}{505}\)
Đúng 0
Bình luận (0)
Cho A=1/2018+2/2019+3/2020+.....+2019/4036-2019 và B =1/2018+1/2019+1/2020+....+1/4036. CMR A/B là một số nguyên
Nhanh minh ticks cho
So sánh hai phân số
A=2017/2018+2018/2019+2019/2020 và B=(2017+2018+2019)/(2018+2019+2020)
tính nhanh
2017/2018-2019/2018-2020/2019. các bạn ơi giúp mình giải câu này với
= (1-1/2018)-(1+1/2018)-2020/2019
= 1-1/2018-1-1/2018-2020/2019
= -2/2018-2020/2019
vậy thôi
Đúng 0
Bình luận (0)
=(1-1/2018)-(1+1/2018)-2020/2019
=1-1/2018-1-1/2018-2020/2019
=-2/2018-2020/2019
Đúng 0
Bình luận (0)
\(\dfrac{2020^{2018}-1}{2020^{2019}+2019}\)với B=\(\dfrac{2020^{2019}+1}{2020^{2020}+2019}\)
\(A=\dfrac{2020^{2018}-1}{2020^{2019}+2019}\)
\(B=\dfrac{2020^{2019}+1}{2020^{2020}+2019}\)
Ta có :
\(A-B=\dfrac{2020^{2018}-1}{2020^{2019}+2019}-\dfrac{2020^{2019}+1}{2020^{2020}+2019}\)
\(\Rightarrow A-B=\dfrac{\left(2020^{2018}-1\right)\left(2020^{2020}+2019\right)-\left(2020^{2019}+2019\right)\left(2020^{2019}+1\right)}{\left(2020^{2019}+2019\right)\left(2020^{2020}+2019\right)}\)
\(\Rightarrow A-B=\dfrac{2020^{4038}+2019.2020^{2018}-2020^{2020}-2019-2020^{4038}-2020^{2019}-2019.2020^{2018}-2029}{\left(2020^{2019}+2019\right)\left(2020^{2020}+2019\right)}\)
\(\Rightarrow A-B=\dfrac{-\left(2020^{2020}+2020^{2019}+2.2019\right)}{\left(2020^{2019}+2019\right)\left(2020^{2020}+2019\right)}\)
mà \(\left\{{}\begin{matrix}-\left(2020^{2020}+2020^{2019}+2.2019\right)< 0\\\left(2020^{2019}+2019\right)\left(2020^{2020}+2019\right)>0\end{matrix}\right.\)
\(\Rightarrow A-B< 0\)
\(\Rightarrow A< B\)
Vậy ta được \(A< B\)
Đúng 4
Bình luận (0)
TÍNH:
\(\frac{2^{2018}}{2^{2018}+3^{2019}}+\frac{3^{2019}}{3^{2019}+5^{2020}}+\frac{5^{2020}}{5^{2020}+2^{2018}}\)
Cho a/b=c/d.CMR:
(a^2018+b^2018)^2019/(c^2018+d^2018)^2019=(a^2019-b^2019)^2020/(c^2019-d^2019)^2020
MONG CÁC BẠN GIẢI SỚM, MÌNH ĐANG CẦN GẤP!!!!
