\(\frac{-3.7^4+7^3}{7^5.6-7^3.2}=\frac{7^3\left(-3.7+1\right)}{7^3\left(7^2.6-2\right)}=\frac{-21+1}{49.6-2=4}=\frac{-20}{290}\)

\(\left(6x-3^3\right).5^3=3.5^4\)

\(\Rightarrow\left(6x-27\right)=3\left(5^4\div5^3\right)\)

\(\Rightarrow\left(6x-27\right)=3.5\)

\(\Rightarrow6x-27=15\)

\(\Rightarrow6x=42\)

\(\Rightarrow x=7\)

Bằng nhau

Bạn ghi rõ ràng đề.            

33 phần 47 < 3774 phần 5217 

a) \(\left(3^4.57-9^2.21\right):3^5\)

\(=\left(3^4.57-3^4.21\right):3^5\)

\(=\left[3^4\left(57-21\right)\right]:3^5\)

\(=3^4.36:3^5\)

\(=3^4.2^2.3^2:3^5\)

\(=3.4\)

\(=12\)

b) Ta có; \(1^3+2^3+...+9^3=2025\)

\(\Leftrightarrow2^3.\left(1^3+2^3+....+9^3\right)=2^3.2025\)

\(\Leftrightarrow2^3+4^5+...+18^3=16200\)

Khó hiểu quá

`x^3 - 3x^2y + x + 3xy^2 - y - y^3`

`=(x)^3 - 3*(x)^2*y + 3*x*y^2 - (y)^3 + (x - y)`

`= (x - y)^3 + (x - y)`

`= (x - y)[(x - y)^2 + 1]`

`= (x - y)(x - y - 1)(x - y + 1)`

____

`@` CT:

`(A - B)^3=A^3-3A^2B+3AB^2- B^3`

a) 1^3 + 2^3 = 1 + 8 = 9 (phải, vì 9 = 3^2)

b) 1^3 + 2^3 + 3^3 = 1 + 8 + 27 = 36 (phải, vì 36 = 6^2)

c) 1^3 + 2^3 + 3^3 + 4^3 = 1 + 8 + 27 + 64 = 100 (phải, vì 100 = 10^2)