\(M=\frac{1}{201}+\frac{1}{202}+...+\frac{1}{299}+\frac{1}{300}\)

\(\Rightarrow\)Có 100 phân số

Ta có: \(\frac{1}{201}>\frac{1}{300}\)

          \(\frac{1}{202}>\frac{1}{300}\)

             ...................

            \(\frac{1}{299}>\frac{1}{300}\)

            \(\frac{1}{300}=\frac{1}{300}\)

\(\Rightarrow M>\left(\frac{1}{300}+\frac{1}{300}+...+\frac{1}{300}\right)=\frac{100}{300}=\frac{1}{3}\)

Vậy....

Ta chia A ra lam 2 khoang la tu B=1/201+1/202+...+1/250 (50 so hang)va tu C=1/251+1/252+...+1/300 (50 so hang)

ta thay 1/201=1/201, 1/202<1/201,....1/250<1/201

cong  ca 2 ve cua 50 bat dang thuc cung chieu ta duoc B<50.1/201=> B<50/201

ta cung thay 1/251=1/251,1/252<1/251,....1/300<1/251

cong 2 ve cua 50 bat dang thuc cung chieu ta lai duoc C<50.1/251=> C<50/251

Ta thay A= B+C

suy ra A< 50/201+50/251=> A<0,448

ma tha thay 0,448<9/20

SUY RA A<9/20 (dpcm)

Thoi mik ko lay tien cua ban dau

Co gang len! Chuc ban hoc tot!

Really ? 

Có chắc là có 50K thật không ??