tìm x thuộc N
(x+15) \(⋮\)(x+5)
(x+10)\(⋮\)x-3
2x +9 \(⋮\)x+2
4x+20 \(⋮\)(x+3)
Những câu hỏi liên quan
tìm x thuộc Z
a) -30+ ( 25-x)= -1
b) (x+5) + ( x-9)=x+ 2
c) 30(x+2) - 6(x-5)-24x =100
d) 2(x-5) - 3(x-4)=-6+15.(-3)
a, Ta có :\(-30+\left(25-x\right)=-1\)
\(\Leftrightarrow\left(-30\right)+25-x=-1\)
\(\Leftrightarrow25-x=\left(-1\right)-\left(-30\right)\)
\(\Leftrightarrow25-x=29\\ \Leftrightarrow x=25-29\)
\(\Leftrightarrow x=\left(-4\right)\)
Vậy \(x=-4\)
b,Ta có :\(\left(x+5\right)+\left(x-9\right)=x+2\)
\(\Leftrightarrow x+5+x-9=x+2\)
\(\Leftrightarrow2.x+\left(5-9\right)=x+2\)
\(\Leftrightarrow\) \(2.x+\left(-4\right)=x+2\)
\(\Leftrightarrow2.x-x=4+2\)
\(\Leftrightarrow x=6\)
Vậy \(x=6\)
tìm x thuộc Z
a)30(x+20)-6(x-5)-24x=100
b)52-/x/=80
c)(-3).x+(-5)^1=(-2)^3.(-5)+1
tìm x:
a)(2x-3)+(3x^2+1)-6x*(x^2-x+1)+3x^2-2x=10
b)(3x+1)*(x-2)-x*((3x-5)=-8-5x
c)(4x-3)*(16x^2+12+9)-32x^2*(2x-1)-32x^2+x=20
a: \(\left(2x-3\right)\left(3x^2+1\right)-6x\left(x^2-x+1\right)+3x^2-2x=10\)
\(\Leftrightarrow6x^3+2x-9x^2-3-6x^3+6x^2-6x+3x^2-2x=10\)
\(\Leftrightarrow-6x-3=10\)
=>-6x=13
hay x=-13/6
b: \(\Leftrightarrow3x^2-3x+x-2-3x^2+5x=-8-5x\)
=>3x-2=-5x-8
=>8x=-6
hay x=-3/4
c: \(\Leftrightarrow64x^3-27-64x^3+32x^2-32x^2+x=20\)
=>x-27=20
hay x=47
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c,\(^{x^{20}-32x^{15}}\)=0
d,\(3^x+3^{x+4}=738,v\text{ới}x\in N\)
e,\(4^{x-1}+5\times4^{x-2}=576\)với x thuộc N
giúp mk nha gấp lắm lun
d) \(3^x+3^{x+4}=738\)
\(3^x+3^x.3^4=738\)
\(3^x.\left(1+3^4\right)=738\)
\(3^x.82=738\)
\(3^x=9\)
\(3^x=3^2\)
\(\Rightarrow x=2\)
Vậy x=2
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c) \(x^{20}-32x^{15}=0\)
\(\Leftrightarrow x^{15}.\left(x^5-32\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^{15}=0\\x^5-32=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x^5=32\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=0\\x=2\end{cases}}}\)
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\(4^{x-1}+5.4^{x-2}=576\)
\(\Leftrightarrow4^{x-1}+5.4^{x-1}.\frac{1}{4}=576\)
\(\Leftrightarrow4^{x-1}.\left(1+5.\frac{1}{4}\right)=576\)
\(\Leftrightarrow4^{x-1}.\frac{9}{4}=576\)
\(\Leftrightarrow4^{x-1}=256\)
\(\Leftrightarrow4^{x-1}=4^4\)
\(\Leftrightarrow x-1=4\)
\(\Leftrightarrow x=5\)
Vậy x=5
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Xem thêm câu trả lời
Tìm x thuộc Z biết
a/ (x-3)+(x-2)+(x-1)+...+10+11=11
b/ 30(x+2)-6(x-5)-24x=100
c/ -12(x-5)+7(x-3)=5
Tim cac so nguyen x, biet:
1. -10<x<-5
2. -4<hoac= x <hoac=3
3. n+9<x<hoac=n+12
4. n+15<x<n+15
5. x<-9 va x<9
6. |x|=|10|
7. |x|=20 va x>0
8. |x|=-100
9. |-5|+|-9|+x=14+|12|
10. 8+x=|-8|+20
Tìm x thuộc Z, biết
a) (x +5)+(x - 9) = x + 2
b) |x + 3|+|x + 2| = x
c) 2. |x - 20|= 10
d) 2.|x - 5| = 25
e) -5x+(7 - 15)= -6x +5
f) 23 - 3 |2x+6| = -7
tìm x,y thuộc N biết
a) 2^x+1 . 3^y = 12^x
b)10^x : 5^y = 20^y
c)3^2x-2 . 5^2y = 15^x
d) 3^-3 . 3^x + 7 . 3^x = 190 . 3^5
\(a,2^{x+1}=3^y=12^x\Rightarrow2^{x+1}.3^y=2^{2x}.3y\)
\(\Rightarrow\frac{2^x}{2^{x+1}}=\frac{3^y}{3^x}\Rightarrow2^{2-x-x-1}=3^{y-x}\)
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Tìm x thuộc z biết:x-14=3x+18 x-13=2x+52 2.(x-5)-3.(x-4)=(-6)+15.(-3) 30.(x+2)-6.(x-5)-24x=100+x
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2. 3x-x = -14-18
2x=-32 suy ra x=-2
3. 2x-x = -13-52
x= -65
4, 2x-10 - 3x +12 = - 6 - 45
x = 2+51 suy ra x= 53
5, 30x + 60 - 6x +30 -24 x =100 +x
x = -10
x-14=3x+18
<=> x-14-3x-18=0
<=> -2x-32=0
<=>-2x=32
<=>x=-16
Vậy x=-16
x-13=2x+52
<=> x-13-2x-52=0
<=> -3x-65=0
<=>-3x=65
<=>x=-65/3
Vậy x=-65/3
2.(x-5)-3.(x-4)=(-6)+15.(-3)
<=> x-5-3x+12=-6-45
<=> 7-2x=-51
<=> 2x=58
<=>x=29
Vậy x=29
30.(x+2)-6.(x-5)-24x=100+x
<=> 30x+60-6x+30-24x=100+x
<=> 90=100+x
<=>x=-10
Vậy x=-10