có bạn nào ko giúp mình với 

\(\frac{3^6\times45^4-15^{13}\times5^{-9}}{27^4\times25^3+45^6}\)

\(=\frac{3^6\times\left(3^2\times5\right)^4-\left(3\times5\right)^{13}\times5^{-9}}{\left(3^3\right)^4\times\left(5^2\right)^3+\left(3^2\times5\right)^6}\)

\(=\frac{3^6\times3^8\times5^4-3^{13}\times5^{13}\times5^{-9}}{3^{12}\times5^6+3^{12}\times5^6}\)

\(=\frac{3^{14}\times5^4-3^{13}\times5^4}{3^{12}\times5^6+3^{12}\times5^6}\)

\(=\frac{3^{13}\times5^4\times\left(3-1\right)}{2\times3^{12}\times5^6}\)

\(=\frac{3\times2}{2\times5^2}\)

\(=\frac{3}{25}\)

chịu

2a) \(\frac{3^6+45^4-15^3.4^5}{27^4.25^3+45^6}\)

= \(\frac{3^6+\left(3^2.5\right)^4-\left(3.5\right)^3.\left(2^2\right)^5}{\left(3^3\right)^4.\left(5^2\right)^3+\left(3^2.5\right)^6}\)

= \(\frac{3^6+3^8.5^4-3^3.5^3.4^{10}}{3^{12}.5^6-3^{12}.5^6}=\frac{3^3.\left(3^3+3^5.5^4-5^3.4^{10}\right)}{0}\)(xem lại đề)

b)  \(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{16}{3}\right)^3:\left(\frac{4}{9}\right)^3}{2^7.5^2+512}\)

= \(\frac{\left(\frac{2}{5}.5\right)^7+\left(\frac{16}{3}:\frac{4}{9}\right)^3}{2^7.5^2+2^9}\)

= \(\frac{2^7+12^3}{2^7\left(5^2+2^2\right)}\)

= \(\frac{2^7+\left(2^2.3\right)^3}{2^7.29}\)

= \(\frac{2^7+2^6.3^3}{2^7.29}\)

= \(\frac{2^6\left(1+27\right)}{2^7.29}=\frac{28}{2.29}=\frac{14}{29}\)

mk xin lỗi bn nhé...mk vt nhầm đề...mk vt lại nha:

2a,\(\frac{3^6+45^4-15^3.9^5}{27^4.25^3+45^6}\)

3/25 

ngân đầu tiên

\(=\dfrac{3^6\cdot3^8\cdot5^4-3^3\cdot5^3\cdot5^9}{3^{12}\cdot5^6+3^{12}\cdot5^6}=\dfrac{5^4\cdot3^3\cdot\left(3^{11}-5^8\right)}{3^{12}\cdot5^6\cdot2}=\dfrac{-106739}{3^9\cdot5^2}\)

a,=0

b,\(5\sqrt{5}\)

c=\(8\sqrt{7a}\)

d,=\(11\sqrt{3}\)

bạn lm ra luôn đc ko