\(5.\left[225-\left(x-10\right)-125\right]=0\)

\(225-\left(x-10\right)-125=0:5\)

\(225-\left(x-10\right)-125=0\)

\(\left(x-10\right)-125=225-0\)

\(\left(x-10\right)-125=225\)

\(x-10=225+125\)

\(x-10=350\)

Mấy bài này làm theo thứ tứ trái sang phải, nhân chia trc cộng trừ sau thoi mà :>>>?

Quên, thứ tự ngoặc là { [ ( ) ] } nha :))))))))))))))))

a,\(\left(x-15\right):50+22=24\)

\(< =>\frac{\left(x-15\right)}{50}=2< =>x-15=100\)

\(< =>x=100+15=115\)

b,\(42-\left(2x+32\right)+12:2=6\)

\(< =>42-2x-32=0\)

\(< =>10-2x=0< =>x=\frac{10}{2}=5\)

Làm nốt :

c) \(134-2\left\{156-6\cdot\left[54-2\cdot\left(9+6\right)\right]\right\}\cdot x=86\)

=> 134 - 2{156 - 6 . [54 - 2 . 15]} . x = 86

=> 134 - 2{156 - 6 . [54 - 30]} . x = 86

=> 134 - 2{156 - 6. 24} . x = 86

=> 134 - 2{156 - 144} . x = 86

=> 134 - 2.12 . x = 86

=> 134 - 24 . x = 86

=> 24.x = 48

=> x = 2

Bài 2 : a) 120 : [21 - (4x - 4)] = 2³.3

=> 120 : [21 - (4x - 4)] = 8.3

=> 120 : [21 - (4x - 4)] = 24

=> 21 - (4x - 4) = 5

=> 4x - 4 = 16

=> 4x = 20

=> x = 5

b) 3.[205 - (x - 9)] - 486 = 0

=> 3.[205 - (x - 9)] = 486

=> 205 - (x - 9) = 162

=> x - 9 = 205 - 162 = 43

=> x = 43 + 9 = 52

c) 204 - 2{200 - 5.[64 - 2.(11 + 6)]} . x = 4

=> 204 - 2{200 - 5.[64 - 2.17]} . x = 4

=> 204 - 2{200 - 5 .[64 - 34]}.x = 4

=> 204 - 2{200 - 5.30} . x = 4

=> 204 - 2{200 - 150}.x = 4

=> 204 - 2.50 . x = 4

=> 2.50.x = 200

=> 100.x = 200

=> x = 2

42 -(2x + 32) + 12 :2 =6

42 - 2x - 32 + 6 = 6

42 - 2x - 32 = 0

42 - 2x = 32

2x = 42 - 32 = 10

x = 5

134 - 2 . {156 - 6.[54 -2.(9+6) ] } x = 86

134 - 2.{ 156 - 6.[54 - 2 . 15 ]} x = 86

134 - 2.{ 156 - 6 . 24} x = 86

134 - 2. 12 .x = 86

134 - 24x = 86

24x = 48

x = 2 

\(42-\left(2x+32\right)+12:2=6\)

\(\Rightarrow42-2x-32=0\)

\(\Rightarrow2x=10\)

\(\Rightarrow x=5\)

Bài 1:

a) 8² . 2² = 64 . 4 = 256

b) 2⁵. 4 = 2⁵. 2²= 2⁵⁺² = 2⁷

c) 9⁴. 243 = 9⁴. 3⁵=(3²)⁴.3⁵=3⁸.3⁵=3⁸⁺⁵=3¹³

Bài 1 :

\(a.8^2.2^2=\left(8.2\right)^2=16^2\)

\(b.2^5.4=2^5.2^2=2^7\)

\(c.9^4.243=\left(3^2\right)^4.3^5=3^8.3^5=3^{13}\)

Bài 2:

a. ( đề sai =.= )

\(b.12.\left(x-1\right):3=43+2^3\)

\(\Leftrightarrow12.\left(x-1\right)=43+2^3.3\)

\(\Leftrightarrow12.\left(x-1\right)=67\)

\(\Leftrightarrow x-1=\frac{67}{12}\)

\(\Leftrightarrow x=\frac{79}{12}\)

a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)

=>\(\left[2\left(10-x\right)+51\right]:3=5\)

=>\(\left[2\left(10-x\right)+51\right]=15\)

=>\(2\left(10-x\right)=15-51=-36\)

=>10-x=-36/2=-18

=>\(x=10-\left(-18\right)=10+18=28\)

b: \(\left(x-12\right)-15=20-\left(17+x\right)\)

=>\(x-12-15=20-17-x\)

=>\(x-27=3-x\)

=>\(2x=30\)

=>\(x=\dfrac{30}{2}=15\)

c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)

=>\(720-\left[41-2x+5\right]=8\cdot5=40\)

=>\(\left[41-2x+5\right]=720-40=680\)

=>-2x+46=680

=>-2x=680-46=634

=>\(x=\dfrac{634}{-2}=-317\)

\(\text{a/96-3(x+1)=42}\)

\(3\left(x+1\right)=54\)

\(x+1=54:3\)

\(x+1=18\)

\(\Rightarrow x=17\)

\(\text{b/2.x-18=20}\)

\(2x=38\)

\(x=38:2\)

\(x=19\)

\(\text{c/134-5.(x+4)=34}\)

\(5\left(x+4\right)=100\)

\(x+4=100:5\)

\(x+4=20\)

\(\Rightarrow x=16\)

học tốt

a) 96-3(x+1)=42

3(x+1)=96-42

3(x+1)=54

x+1=54:3

x+1=18

x=18-1

Vậy x=17

b) 2x-18=20

2x=20+18

2x=38

x=38:2

x=19

Vậy x=19.

c) 134-5(x+4)=34

5(x+4)=134-34

5(x+4)=100

x+4=100:5

x+4=20

x=20-4

x=16

Vậy x=16.

a) 96-3(x+1)=42

          3(x+1)=96-42

          3(x+1)=54

               x+1=54:3

               x+1=18

                   x=18-1

                   x=17

Vậy x=17

b)2.x-18=20

   2.x     =20+18

   2.x     =38

      x     =38:2

      x     =19

Vậy x=19

c)134-5.(x+4)=34

          5.(x+4)=134-34

          5.(x+4)=100

              x+4 =100:5

              x+4 =20

                  x =20-4

                  x =16

Vậy x=16
 

4.\(\left(2-x\right)\left(5-x\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}2-x=0\\5-x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=2\\x=5\end{cases}}}\)

5.\(\left(4x-16\right)\left(8-2x\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}4x-16=0\\8-2x=0\end{cases}\Leftrightarrow\hept{\begin{cases}4x=16\\-2x=-8\end{cases}\Leftrightarrow}\hept{\begin{cases}x=4\\x=4\end{cases}}}\)

Câu 4:

(  2- x ) . ( 5 - x ) = 0

=> 2 - x = 0 hoặc 5 - x = 0

=> x = 2 hoặc x = 5

Vậy x \(\in\){ 2 ; 5 }

Cậu 5:

( 4x - 16 ) . ( 8 - 2x ) = 0

=> 4x - 16 = 0 hoặc 8 - 2x = 0

=> 4x = 16 hoặc 2x = 8

=> x = 4 hoặc x = 4

Vậy x = 4

câu 4 

a)x=2;x=5

câu5

x=4;

~~~~~~~~~ai đi ngang qua nhớ để lại ti k ~~~~~~~~~~~

a, 315+(125-x)=435

<=>  125 - x = 435 - 315

<=> 125 - x  = 120

<=>          x  = 5

b, 6x-5=613

<=> 6x = 613 + 5

<=> 6x = 618

<=> x = 103

c, 128-3(x+4)=23

<=> 3(x +4 ) = 105

<=> x + 4     = 35

<=> x           = 31

 e, -x +8=17

<=> x = -9

a, 315+(125-x)=435

125-x=435-315=120

x=125-120=5

=>x=5

b,6x-5=613

6x=613+5=618

x=618:6=103

c, 128-3(x+4)=23

3(x+4)=128-23=105

x-4=105:3=35

x=35+4=39

Ý D NHẦM ĐẦU BÀI BẠN ƠI.