a) 14-(7-x+3)=5-{4-(5- |3| ) }

   14-(10-x) = 5-{4-(5-3) }

     x +14-10=5-(4-2)

     x+4        = 5-2

     x+4         =3

     x             =3-4

     x              =-1 Vậy x= -1

-7 + [ - (-3) + |6| - (544 + |-6 |) ] = 5 - ( 7 - x + 4)

-7+{ 3+6-(544+6) }                  =5-(11-x)

-7+(9-600)                               =x+5-11

-7+-591                                   =x+(-6)

-598                                       = x+ (-6)

x                                             =-598 - (-6)

x                                             = -592

Vậy x= -592

tick mình nha

Cảm ơn bạn nhiều nhé,vậy mình làm giống bạn rồi!!!

2/3×3/4×4/5÷1/5=2

2/5×3/4×5/6÷3/4=0.33333333333......

2/3 x 3/4 x 4/5 : 1/5 = 6/12 x 4/5 :1/5 = 24/60 :1/5 = 4/10 : 1/5 = 4/10 x 5/1 = 20/10 = 2

2/5 x 3/4 x 5/6 : 3/4 = 6/20 x 5/6 : 3/4 = 3/10 x 5/6  : 3/4 = 15/60 : 3/4 = 1/4 : 3/4 = 1/4 x 4/3 = 4/12 = 1/3

k cho mk nha!

\(\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\div\frac{1}{5}\)

\(=\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\times\frac{5}{1}\)

\(=\frac{2\times3\times4\times5}{3\times4\times5\times1}\)

\(=\frac{2}{1}\)

\(=2\)

Câu 1:a) \(\left(\frac{-5}{12}+\frac{6}{11}\right)+\left(\frac{7}{17}+\frac{5}{11}+\frac{5}{12}\right)\)

\(=\left(\frac{-5}{12}+\frac{5}{12}\right)+\left(\frac{6}{11}+\frac{5}{11}\right)+\frac{7}{17}\)

\(=0+1+\frac{7}{17}\)

\(=\frac{17}{17}+\frac{7}{17}\)

\(=\frac{24}{17}\)

b) \(\frac{7}{12}-\left(\frac{5}{12}-\frac{5}{6}\right)\)

\(=\frac{7}{12}-\frac{5}{12}+\frac{5}{6}\)

\(=\frac{7}{12}-\frac{5}{12}+\frac{10}{12}\)

\(=\frac{7-5+10}{12}\)

\(=1\)

c) \(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}\)

\(=\frac{1}{12}+\frac{1}{30}\)

\(=\frac{5}{60}+\frac{2}{60}\)

\(=\frac{7}{60}\)

Câu 2:a) \(\frac{x}{8}=2+\frac{-3}{2}\)

\(\Leftrightarrow\frac{x}{8}=\frac{4-3}{2}\)

\(\Leftrightarrow\frac{x}{8}=\frac{1}{2}\)

\(\Leftrightarrow2x=8\)

\(\Leftrightarrow x=\frac{8}{2}\)

\(\Leftrightarrow x=4\)

b) \(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)

\(\Leftrightarrow\frac{-18}{6}\le x\le4\)

\(\Leftrightarrow-3\le x\le4\)

\(\Leftrightarrow x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

nhanh lên

bài này khó

12000

1 ) 

(-10 + 5) -(4-x)=12 -(5-6)                                   

<=> -10 + 5 - 4 + x = 12 - 5 + 6 

<=> x = 12 - 5 + 6 + 10  - 5 + 4 

<=> x = 22

2 )

14-(5-8+3-x)=|-7+10|

<=> 14 - 5 + 8 - 3 + x = | 3 | 

<=> x = | 3 | -14 + 5 - 8 + 3 

<=> x = 3 - 14 + 5 - 8 + 3 

<=> x = -11 

3 )

-19-(3 +x-5)=|4-15+2|

<=> -19 - 3 - x + 5 = | -9 | 

<=> -x = | -9 | - 5 + 19 + 3 

<=> -x = 9 - 5 + 19 + 3 

<=> -x = 26

<=> x = -26 

4 )

45-(x+45-3)=|-7+3|

<=> 45 - x - 45 + 3 = | -4 | 

<=> -x + 3 = | -4 |

<=> -x = 4 - 3

<=> -x = 1

<=> x =-1

10 )

-(-12 +4-10)-(4-x)=-(-3)

<=> 12 - 4 + 10 - 5 + x = 3 

<=> x = 3 -12 + 4 - 10 +  5

<=> x = -10 

Mình là Siêu Phẩm Hacker , rất mong được thi đấu một lần vs Edokawa conan  

1) (-10 + 5) - (4 - x) = 12 - (5 - 6)

=> -5 - 4 + x = 12 + 1

=> -5 - 4 + x = 13

=> 4 + x = -5 - 13

=> 4 + x = - 18

=> x = -18 - 4

=> x = -22

2) 14 - (5 - 8 + 3 - x) = |-7 + 10|

=> 14 + 5 + 8 - 3 + x = |3|

=> 24 + x = 3

=> x = 3 - 24

=> x = -21

3) -19 - (3 + x - 5) = |4 - 15 + 2|

=> -19 - 3 - x + 5 = |-9|

=> -17 - x = 9

=> x = -17 - 9

=> x = -26

4) 45 - (x + 45 - 3) = |-7 + 3|

=> 45 - x - 45 + 3 = |-4|

=> 3 - x = 4

=> x = 3 - 4

=> x = -1

5) -(-12 + 4 - 10) - (4 - x) = -(-3)

=> -(-29) - (4 - x) = 3

=> 29 - (4 - x) = 3

=> 4 - x = 29 - 3

=> 4 - x = 26

=> x = 4 - 26

=> x = -22

= nhau nha

\(2/3*4/5=8/15\)

\(4/5*2/3=8/15\)

\(=>2/3*4/5=4/5*2/3\) nhé

8/15=8/15

x - 4/5 = 3/7

x = 3/7 + 4/5

x = 43/35

x + 3/7 = 4/5

x = 4/5 - 3/7

x = 13/35

19/20 - x = 8/5 - 3/4

19/20 - x =  17/20

x = 19/20 - 17/20

x = 2/20 = 1/10

4/5 x X = 6/9 - 4/7

4/5 x X = 2/21

x = 2/21 : 4/5

x =5/42

x : 7/9 = 6/8

x = 6/8 x 7/9

x = 7/12

2/3 - x/6 = 6/18

x/6 = 2/3 - 6/18

x/6 = 1/3

x/6 = 2/6

=> x =2

1. x = 43/35

2. x = 13/35

3. x = 1/10

còn lại tự tính nhá

tui bận òi

(dấu . là dấu nhân )

a, \(\frac{3}{2}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{3}{2}\)

= \(\frac{3}{2}\left(\frac{4}{7}+\frac{3}{7}\right)\)

=\(\frac{3}{2}\cdot\frac{7}{7}=\frac{3}{2}\)

b, \(\frac{12}{5}\cdot4-4\cdot\frac{7}{5}\)

=\(4\left(\frac{12}{5}-\frac{7}{5}\right)=4\cdot\frac{5}{5}=4\)

c, \(\frac{5}{11}:\frac{1}{2}+\frac{6}{11}:\frac{1}{2}\)

=\(2\left(\frac{5}{11}+\frac{6}{11}\right)=2\cdot\frac{11}{11}=2\)

a;3/2x(4/7+3/7)

=3/2x1

=3/2

b;12/5x4-4x7/5

=4x(12/5-7/5)

=4x1

=4

c;5/11:1/2+6/11:1/2

=1/2:(5/11+6/11)

=1/2:1

=1/2

a) 3/2 * 4/7 +3/7 * 3/2

= 3/2*(4/7+3/7)

= 3/2*1

=3/2

b) 12/5 * 4 -4*7/5

=4*(12/5-7/5)

= 4*1

=4

c) 5/11 :1/2 + 6/11 : 1/2

=1/2 : (5/11 +6/11)

=1/2 : 1

=1/2