chép nhầm đề. Làm lại:

\(C=\frac{\left(3.4.2^4\right)^2}{5.2^5.4^2-16^2}=\frac{3^2.2^4.2^8}{5.2^5.2^4-2^8}=\frac{9.2^{12}}{5.2^9-2^8}=\frac{9.2^{12}}{2^8.\left(5.2-1\right)}=\frac{9.2^4}{9}=\frac{2^4}{1}=2^4=16\)

Gấp lắm thì làm vậy

\(C=\frac{\left(3.4.2^2\right)^2}{5.2^5.4^2-16^2}=\frac{3^2.2^4.2^4}{5.2^5.2^4-2^8}=\frac{3^2.2^8}{5.2^9-2^8}=\frac{3^2.2^8}{2^8.\left(5.2-1\right)}=\frac{9}{9}=1\)

giúp với ,mai mik nộp r

      \(\frac{2^{10}\cdot55+2^{10}\cdot26}{28\cdot27}\)

\(=\frac{2^{10}\cdot\left(55+26\right)}{28\cdot27}\)

\(=\frac{2^{10}\cdot81}{28\cdot27}\)

\(=\frac{1024\cdot81}{756}\)

\(=\frac{20736}{189}\)

\(\text{Nếu còn rút gọn được thì bạn tự rút gọn nha !}\)

\(\dfrac{1}{2}A=\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3+\left(\dfrac{1}{2}\right)^4+...+\left(\dfrac{1}{2}\right)^{2023}\)

\(A-\dfrac{1}{2}A=\left(\dfrac{1}{2}\right)^{2023}-1\)

\(\dfrac{1}{2}A=\left(\dfrac{1}{2}\right)^{2023}-1\)

\(A=\dfrac{1}{2^{2022}}-2\)

A−12A=(12)2023−1A−12A=(12)2023−1

A=122022−2

1)

a)

\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)

\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)

\(\frac{-20}{5}< x< \frac{-3}{10}\)

\(\frac{-40}{10}< x< \frac{-3}{10}\)

\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)

\(\left(\frac{-5}{3}\right)^3< x< \frac{-24}{35}.\frac{-5}{6}\)

\(\frac{25}{3}< x< \frac{-4}{7}.\frac{1}{1}\)

\(\frac{-25}{3}< x< \frac{-4}{7}\)

\(\frac{-175}{21}< x< \frac{-12}{21}\)

\(\Rightarrow Z\in\left\{-13;-14;-15;-16;...;-174\right\}\)

2)

a)

\(\left(\frac{9}{10}-\frac{15}{16}\right).\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)

\(=\left(\frac{72}{80}-\frac{75}{80}\right).\left(\frac{25}{60}-\frac{44}{60}-\frac{21}{60}\right)\)

\(=\frac{-3}{80}.\frac{-40}{60}\)

\(=\frac{-1}{-2}.\frac{-1}{-20}\)

\(=\frac{1}{40}\)

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}=\frac{3^2.2^{36}}{2^{35}\left(11-2\right)}=\frac{3^2.2}{10}=\frac{18}{10}\)

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)

\(=\frac{3^2.2^{36}}{2^{35}\left(11-2\right)}\)

\(=\frac{3^2.2^{36}}{2^{35}.9}\)

\(=\frac{3^2.2^{36}}{2^{35}.3^2}\)

\(=2\)

           ~~~Hok tốt~~~

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