bạn ơi  bạn viết sai đề có đề nào viết  thế này đâu?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????

Uchiha Itachi

Trả lời:

x³ - 2x² + 2x - 4

= ( x³ - 2x² ) + ( 2x - 4 )

= x² ( x - 2 ) + 2 ( x - 2 )

= ( x - 2 ) ( x² + 2 )

\(x^2-y^2+z^2-t^2-2xz+2yt=\)

\(=\left(x^2-2xz+z^2\right)-\left(y^2-2yt+t^2\right)=\)

\(=\left(x-z\right)^2-\left(y-t\right)^2=\)

\(=\left[\left(x-z\right)-\left(y-t\right)\right]\left[\left(x-z\right)+\left(y-t\right)\right]\)

   \(x^2-y^2+z^2-t^2-2xz+2yt\)

\(=\left(x^2-2xz+z^2\right)-\left(y^2+2yt+t^2\right)\)

\(=\left(x-z\right)^2-\left(y-t\right)^2\) 

\(=\left(x-z+y-t\right)\times\left(x-z-y+t\right)\)

\(x^2-y^2+z^2-t^2-2xz+2yt\)

\(=x^2-2xz+z^2-\left(y^2-2yt+t^2\right)\)

\(=\left(x-z\right)^2-\left(y-t\right)^2\)

\(=\left(x-z+y-t\right)\left(x-z-y+t\right)\)

6, x mũ 4 - 4x mũ 3 - 8x mũ 2 + 8x =x (x+2) (x^2-6x+4)

8, x mũ 4 + 2x mũ 3 + x mũ 2 - y mũ 2  = -(y-x^2-x) (y+x^2+x)

10, 4x mũ 2 ( x + y ) -x - y  = (2x-1) (2x+1) (y+x)

a, \(x^2-4-3\left(x-2\right)=\left(x-2\right)\left(x+2\right)-3\left(x-2\right)=\left(x-1\right)\left(x-2\right)\)

b, \(x^2-xy+5y-25=\left(x-5\right)\left(x+5\right)-y\left(x-5\right)=\left(x+5-y\right)\left(x-5\right)\)

c, \(x^3+x^2-2x-8=\left(x-2\right)\left(x^2+2x+4\right)+x\left(x-2\right)=\left(x-2\right)\left(x^2+3x+4\right)\)

d, \(x^3-4x^2-8x+8=\left(x+2\right)\left(x^2-2x+4\right)-4x\left(x+2\right)=\left(x^2-6x+4\right)\left(x+2\right)\)

Trả lời:

1, x² - 4 - 3 ( x - 2 )

= ( x² - 4 ) - 3 ( x - 2 )

= ( x - 2 ) ( x + 2 ) - 3 ( x - 2 )

= ( x - 2 ) ( x + 2 - 3 )

= ( x - 2 ) ( x - 1 )

2, x² - xy + 5y - 25

= ( x² - 25 ) - ( xy - 5y )

= ( x - 5 ) ( x + 5 ) - y ( x - 5 )

= ( x - 5 ) ( x + 5 - y )

3, x³ + x² - 2x - 8

= ( x³ - 8 ) + ( x² - 2x )

= ( x - 2 ) ( x² + 2x + 4 ) + x ( x - 2 )

= ( x - 2 ) ( x² + 2x + 4 + x )

= ( x - 2 ) ( x² + 3x + 4 )

4, x³ - 4x² - 8x + 8 

= ( x³ + 8 ) - ( 4x² + 8x )

= ( x + 2 ) ( x² - 2x + 4 ) - 4x ( x + 2 )

= ( x + 2 ) ( x² - 2x + 4 - 4x )

= ( x + 2 ) ( x² - 6x + 4 )

xin lỗi em lớp 3 :>>>>

𝑥2−3𝑥+2

(x-5)^2

k nhé tó k lại

.....me chịu.

KHông thì. bạn tải qanda nhé.

chụp bài rồi gửi ,người ta giải cho .

nhưng nó ko quét bài viết bài tay đâu nhé,chỉ quét chữ in thôi.

a)x²−2x−4y²−4ya)x²-2x-4y²-4y

=x²−2x−4y²−4y+2xy−2xy=x²-2x-4y²-4y+2xy-2xy

=(x²−2xy−2x)+(2xy−4y²−4y)=(x²-2xy-2x)+(2xy-4y²-4y)

=x(x−2y−2)+2y(x−2y−2)=x(x-2y-2)+2y(x-2y-2)

=(x+2y)(x−2y−2)=(x+2y)(x-2y-2)

b)x4+2x³−4x−4b)x4+2x³-4x-4

=x4+2x³+2x²−2x²−4x−4=x4+2x³+2x²-2x²-4x-4

=(x4+2x³+2x²)−(2x²+4x+4)=(x4+2x³+2x²)-(2x²+4x+4)

=x²(x²+2x+2)−2(x²+2x+2)=x²(x²+2x+2)-2(x²+2x+2)

=(x²−2)(x²+2x+2)=(x²-2)(x²+2x+2)

c)x³+2x²y−x−2yc)x³+2x²y-x-2y

=x²(x+2y)−(x+2y)=x²(x+2y)-(x+2y)

=(x²−1)(x+2y)=(x²-1)(x+2y)

=(x+1)(x−1)(x+2y)=(x+1)(x-1)(x+2y)

d)3x²−3y²−2(x−y)²d)3x²-3y²-2(x-y)²

=3(x²−y²)−2(x−y)²=3(x²-y²)-2(x-y)²

=3(x+y)(x−y)−2(x−y)²=3(x+y)(x-y)-2(x-y)²

=(x−y)[3(x+y)−2(x−y)]=(x-y)[3(x+y)-2(x-y)]

=(x−y)(3x+3y−2x+2y)=(x-y)(3x+3y-2x+2y)

=(x−y)(x+5y)=(x-y)(x+5y)

e)x³−4x²−9x+36e)x³-4x²-9x+36

=(x³−4x²)−(9x−36)=(x³-4x²)-(9x-36)

=x²(x−4)−9(x−4)=x²(x-4)-9(x-4)

=(x−4)(x²−9)=(x-4)(x²-9)

=(x−4)(x²−3²)=(x-4)(x²-3²)

=(x−4)(x+3)(x−3)=(x-4)(x+3)(x-3)

f)x²−y²−2x−2yf)x²-y²-2x-2y

=(x²−y²)−(2x+2y)=(x²-y²)-(2x+2y)

=(x+y)(x−y)−2(x+y)=(x+y)(x-y)-2(x+y)

=(x+y)(x−y−2)

hok tốt nhé

k đi

haha quá dễ

c, x mũ 2 + 3x - 4 = x^2 + 3 x X -4

c, x mũ 2 + 3x - 18= x^2 + 3xX -18

c, 2x mũ 2 + 3x - 5=  2xX^2 + 3xX -5

c, 3x mũ 2 - 8x + 4= 3 x X^2 - 8 x X + 4

c, 8x mũ 2 + 2x - 3= 8 x X^2 + 2 x X -3

a) = x² - 4x + x - 4 = x( x - 4 ) + ( x - 4 ) = ( x - 4 )( x + 1 )

b) = x² - 3x + 6x - 18 = x( x - 3 ) + 6( x - 3 ) = ( x + 6 )( x - 3 )

c) = 2x² - 2x + 5x - 5 = 2x( x - 1 ) + 5( x - 1 ) = ( x - 1 )( 2x + 5 )

d) = 3x² - 6x - 2x + 4 = 3x( x - 2 ) - 2( x - 2 ) = ( x - 2 )( 3x - 2 )

e) = 8x² - 4x + 6x - 3 = 4x( 2x - 1 ) + 3( 2x - 1 ) = ( 2x - 1 )( 4x + 3 )