\(a,2\times31\times12+4\times6\times42+8\times27\times3\)

\(=24\times31+24\times42+24\times27\)

\(=24\times\left(31+42+27\right)\)

\(=24\times100\)

\(=2400\)

\(b,583.931+69.\left(170+583\right)+31.170\)

\(=583.931+69.170+69.583+31.170\)

\(=583.\left(931+69\right)+170.\left(69+31\right)\)

\(=583.1000+170.100\)

\(=583000+17000\)

\(=600000\)

\(c,732.976+24.\left(680+732\right)+76.680\)

\(=732.976+24.680+24.732+76.680\)

\(=732.\left(976+24\right)+680.\left(24+76\right)\)

\(=732.1000+680.100\)

\(=732000+68000\)

\(=800000\)

Học tốt

a)2400

b)600000

c)800000

a) 2 x 31 x 12 + 4 x 6 x 42 + 8 x 27 x 3

= 24 x 31 + 24 x 42 + 24 x 27

= 24 x ( 31 + 42 + 27 )

= 24 x 100

= 2400

b) 583 x 931 + 69 x ( 170 + 583 ) + 31 x 170

= 583 x 931 + 69 x 170 + 69 x 583 + 31 x 170

= 583 x ( 931 + 69 ) + 170 x ( 69 + 31 )

= 583 x 1000 + 170 x 100

= 583000 + 17000

= 600000

c) 732 x 976 + 24 x ( 680 + 732 ) + 76 x 680

= 732 x 976 + 24 x 680 + 24 x 732 + 76 x 680

= 732 x ( 976 + 24 ) + 680 x ( 24 + 76 )

= 732 x 1000 + 680 x 100

= 732000 + 68000

= 800000

Bạn kiểm tra lại giùm mình đi nha:

15.37.4+120.21+21.5.12                                                         16.64+76.34

=15.37.4+(6.7).4.(5.3)+(3.5).(7.3).4                                          =

=15.37.4+42.4.15+15.21.4

=15.4.(37+42+21)

=60.100

=6000

\(583.931+69\left(170+583\right)+31.170\)

\(=583.931+69.170+69.583+31.170\)

\(=593\left(931+69\right)+170\left(69+31\right)\)

\(=593.100.10+170.100\)

\(=100\left(593.10+170\right)\)

\(=100.6000=600000\)

a) \(136+326+64\)

\(=\left(136+64\right)+326\)

\(=200+326\)

\(=526\)

b) \(69+\left(31+57\right)\)

\(=\left(69+31\right)+57\)

\(=100+57\)

\(=157\)

c) \(755+321+145+179\)

\(=\left(755+145\right)+\left(321+179\right)\)

\(=900+500\)

\(=1400\)

d) \(17+123+378+583+122\)

\(=\left(17+583\right)+\left(378+122\right)+123\)

\(=600+500+123\)

\(=1100+123\)

\(=1223\)

d . 70514

Số bé nhất là : 70514

D . 70 514 nhé bạn

Vì \(\frac{19^{30}+5}{19^{31}+5}< 1\); \(\frac{19^{31}+5}{19^{30}+5}>1\)

Nên A  < B

\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+.......+\dfrac{1}{x\cdot\left(x+1\right)}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow1-\dfrac{1}{x+1}=\dfrac{122}{123}\)

\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{123}\)

\(\Leftrightarrow x=122\)