Chứng tỏ 31/2.32/2...60/2=1.3.5....59
giải hộ mình thì sẽ tick đúng và follow bạn ấy nhé!
Chứng tỏ 31/2.32/2...60/2 = 1.3.5...59
CMR:31/2.32/2.32/3...60/2=1.3.5...59
mình đang cần gấp các bạn cố giúp nha
CMR : 31/2.32/2....60/2 = 1.3.5...59
ta có:31/2.32.2....60.2=31.32...60/2^30=(31.32.33....60).((1.2.3...30)/2^30.(1.2.3...30)=(1.3.5..59).(2.4.6...60)/(2.4.6...60)=1.3.5...59
Ta biến đổi vế phải thành vế trái:
1.3.5....59=1.3.5...59.\(\frac{2.4.6.....60}{2.4.6.....60}=\frac{1.2.3.4.....60}{\left(1.2.3....30\right).\left(2.2.2.....2\right)}=\frac{31.32......60}{2.2.......2}=\frac{31}{2}.\frac{32}{2}.....\frac{60}{2}\)
Vậy chúng = nhau
CMR: 31/2.32/2...60/2=1.3.5...59
Chứng minh rằng:
a)31/2.32/2.33/2....60/2=1.3.5....59
b)2!/3!+2!/4!+2!/5!+...+2!/n! < 1
=1.48/2.2.2.2.40/2.2.2.56/2.2.2.36/2.2.44/2.2.52/2.2.60/2.2.34/2.38/2.42/2.46/2.50/2.54/2.58/2.31.33...59=1.3.5...59 cần chứng minh
so sánh p = 31/2.32/2 + 33/2 + ... + 60/2 và q = 1. 3.5.7...59
Ai nhanh đúng đủ bước tui cho 3 tick
ta thay 31/2.32/2+60/2.59/2=1133
33/2.34/2+58/2.57/2=1107
ta co so hang:
(60/2.59/2-31/2.32/2)/1+1=608 so
so cap la :
608/2=304 cap
tong la :
304.1133-(26.607)=328650
no k cho minh nha
chứng tỏ rằng
31/2+32/2+33/2+....+60/2=1.3.5....59
Chứng tỏ \(\frac{31}{2}.\frac{32}{2}...\frac{60}{2}=1.3.5...59\)
Ta có: \(\frac{31}{2}.\frac{32}{2}...\frac{60}{2}=\frac{31.32...60}{2^{30}}=31.33...57.59.\left(\frac{32.34...58.60}{2^{30}}\right)\)
\(=31.33...57.59.\left(\frac{16.17...29.30}{2^{15}}\right)=17.19...27.29.31.33...57.59.\left(\frac{16.18...30}{2^{15}}\right)\)
\(=17.19...57.59.\left(\frac{8.9...15}{2^7}\right)=9.11.13.15.17...57.59.\left(\frac{8.10.12.14}{2^7}\right)\)
\(=9.11...57.59.\left(\frac{4.5.6.7}{2^3}\right)=5.7.9...57.59.\left(\frac{4.6}{2^3}\right)\)
\(=5.7.9...57.59.3=1.3.5...59\)
Chứng tỏ:
\(\frac{31}{2}.\frac{32}{2}.\frac{33}{2}.\frac{34}{2}....\frac{60}{2}=1.3.5....59\)
\(60!=1\cdot2\cdot3\cdot4\cdot5\cdot...\cdot59\cdot60=1\cdot3\cdot5\cdot...\cdot57\cdot59\times2\cdot4\cdot6\cdot...\cdot58\cdot60\)
\(=1\cdot3\cdot5\cdot...\cdot57\cdot59\times2^{30}\cdot1\cdot2\cdot3\cdot...\cdot30=1\cdot3\cdot5\cdot...\cdot57\cdot59\times2^{30}\times30!\)
\(\Rightarrow1\cdot3\cdot5\cdot...\cdot59=\frac{60!}{30!\times2^{30}}=\frac{31}{2}\cdot\frac{32}{2}\cdot\frac{33}{2}\cdot...\cdot\frac{60}{2}\)đpcm.
\(\frac{31}{2}\cdot\frac{32}{2}\cdot...\cdot\frac{60}{2}\cdot2\cdot4\cdot...\cdot58\cdot60\)
=31.32.33.34...60.1.2.3.4.5...29.30
=1.2.3.4.5.6.7.8.9.10...60
1.3.5.7...59.2.4.6.8...60
=1.2.3.4.5.6...60
Vậy \(\frac{31}{2}\cdot\frac{32}{2}\cdot\frac{33}{2}\cdot...\cdot\frac{60}{2}=1\cdot3\cdot5\cdot...\cdot59\)