Ta có: \(1,\left(279\right)=1+279.0,\left(001\right)=1+279.\frac{1}{999}=\frac{142}{111}\);

          \(2,\left(720\right)=2+720.0,\left(001\right)=2+720.\frac{1}{999}=\frac{302}{111}\)

\(\Rightarrow1,\left(279\right)+2,\left(720\right)=\frac{142}{111}+\frac{302}{111}=4\)

1,(279)+2,(720)=\(\frac{142}{111}+\frac{302}{111}=\frac{444}{111}=4\)

1,(279) + 2(720) = 2 + 1 + [0,(279 + 0,(720)]

= 3 + 1 = 4        

1,(279)=1+0,(279)=1+279/999=142/111

2,(720)=2+0,(720)=2+720/999=302/111

=>1,(279)+2,(720)=142/111+302/111=444/111=4

tick nhé

1,(279)+2,(720)

=\(\left(1+\frac{279}{999}\right)+\left(2+\frac{720}{999}\right)\)

=\(\frac{142}{111}+\frac{302}{111}\)

=4

ko ai tính ra ddc ak???? ai tính đc cho 2 l i k e

1,(279) + 2,(720) = 1 + 2 + 1/999*(279 + 720)

= 3 + 1 = 4  

\(=1+0,\left(001\right).279+2+0,\left(001\right).720=3+\frac{279}{999}+\frac{720}{999}=3+\frac{999}{999}=3+1=4\)

a,  2 3 x + 5 2 x = 2 5 2 + 2 3 - 33

8x+25x = 33

33x = 33

x = 1

b,  260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2

260:(x+4) = 5.13–3.13

x+4 = 260:26

x+4 = 10

x = 6

c,  720 : [ 41 - 2 x - 5 ] = 2 3 . 5

41–(2x–5) = 720:40

2x–5 = 41–18

2x = 28

x = 14

d,  3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2

7(x–12)+35 = 56

7(x–12) = 21

x–12 = 3

x = 15