a) (x-5)2 =225
b) (x-2)5 =32
a 5 . [ 225 - (x -10) -125 = 0
b (x-15) : 5 + 22 =24
c 42 - (2x +32) + 12 : 2 =6
d 134 - 2 : { 156 - 6 .[54 -2 . (9 + 6)]} .x =86
Mh cần gấp nha
\(5.\left[225-\left(x-10\right)-125\right]=0\)
\(225-\left(x-10\right)-125=0:5\)
\(225-\left(x-10\right)-125=0\)
\(\left(x-10\right)-125=225-0\)
\(\left(x-10\right)-125=225\)
\(x-10=225+125\)
\(x-10=350\)
Mấy bài này làm theo thứ tứ trái sang phải, nhân chia trc cộng trừ sau thoi mà :>>>?
Quên, thứ tự ngoặc là { [ ( ) ] } nha :))))))))))))))))
1) 79 - 5 . ( 11 - x ) = 34
2) 32 + 2 . ( 7 - x ) = 40
3) ( 166 - 2 . x ) . 89 = 2 . 811
4) 52 . x - 23 . x = 51
5) 3x + 4 . 3x = 5 . 37
6) 7 . 2x - 2x = 6 . 32
7) 153 - x = 225
8) 4 . 5x - 3 = 97
9) 171 - 3 . 2x = 123
10) 180 - 4 . x5 = 32
1)\(79-5\left(11-x\right)=34\)
\(\Rightarrow79-55+5x=34\)
\(\Rightarrow24+5x=34\)
\(\Rightarrow5x=-10\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
2)\(32+2\left(7-x\right)=40\)
\(\Rightarrow32+14-2x=40\)
\(\Rightarrow46-2x=40\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
3)\(\left(166-2x\right).8^9=2.8^{11}\)
\(\Rightarrow\left(83-x\right).2.8^9=2.8^{11}\)
\(\Rightarrow83-x=8^3\)
\(\Rightarrow83-x=512\)
\(\Rightarrow x=-429\)
Vậy \(x=-429\)
4)\(5^2.x-2^3.x=51\)
\(\Rightarrow x\left(5^2-2^3\right)=51\)
\(\Rightarrow x\left(25-8\right)=51\)
\(\Rightarrow17x=51\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
5)\(3^x+4.3^x=5.3^7\)
\(\Rightarrow3^x\left(1+4\right)=5.3^7\)
\(\Rightarrow5.3^x=5.3^7\)
\(\Rightarrow3^x=3^7\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
6)\(7.2^x-2^x=6.32\)
\(\Rightarrow2^x\left(7-1\right)=6.2^5\)
\(\Rightarrow6.2^x=6.2^5\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
7)\(15^{3-x}=225\)
\(\Rightarrow15^{3-x}=15^2\)
\(\Rightarrow3-x=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
8)\(4.5^x-3=97\)
\(\Rightarrow4.5^x=100\)
\(\Rightarrow5^x=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
9)\(171-3.2^x=123\)
\(\Rightarrow3.2^x=48\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
10)\(180-4.x^5=32\)
\(\Rightarrow4.x^5=148\)
\(\Rightarrow x^5=37\)//Đề có lỗi không ???
Mình làm mãi mới xong nên k đúng hộ mình nha
1) \(79-5.\left(11-x\right)=34\) 2) \(32+2.\left(7-x\right)=40\)
\(5.\left(11-x\right)=79-34\) \(2.\left(7-x\right)=40-32\)
\(5.\left(11-x\right)=45\) \(2.\left(7-x\right)=8\)
\(11-x=45:5\) \(7-x=8:2\)
\(11-x=9\) \(7-x=4\)
\(x=11-9\) \(x=7-4\)
\(x=2\) \(x=3\)
3) \(\left(166-2.x\right).8^9=2.8^{11}\) 4) \(5^2.x-2^3.x=51\)
\(\left(166-2.x\right)=2.8^{11}:8^9\) \(25.x-8.x=51\)
\(\left(166-2.x\right)=2.8^2\) \(\left(25-8\right).X=51\)
\(\left(166-2.x\right)=2.64\) \(17.x=51\)
\(166-2.x=128\) \(x=51:17\)
\(2.x=166-128\) \(x=3\)
\(2.x=38\)
\(x=38:2\)
\(x=19\)
5) \(3^x+4.3^x=5.3^7\) 6) \(7.2^x-2^x=6.32\)
\(3^x+4.3^x=5.2187\) \(7.2^x-2^x=192\)
\(\left(1+4\right).3^x=10935\) \(\left(7-1\right).2^x=192\)
\(5.3^x=10935\) \(6.2^x=192\)
\(3^x=10935:5\) \(2^x=192:6\)
\(3^x=2187\) \(2^x=32\)
\(3^x=3^7\) \(2^x=2^5\)
\(=>x=7\) \(=>x=5\)
7)\(15^{3-x}=225\) 8) \(4.5^x-3=97\)
\(15^{3-x}=15^2\) \(4.5^x=97+3\)
\(=>x=3-2\) \(4.5^x=100\)
\(x=1\) \(5^x=100:4\)
\(5^x=25\)
\(5^x=5^2\)
\(=>x=2\)
9) \(171-3.2^x=123\)
\(3.2^x=171-123\)
\(3.2^x=48\)
\(2^x=48:3\) \(\)
\(2^x=16\)
\(2^x=2^4\)
\(=>x=4\)
Tìm x, biết:
a) (x + 5)2 - (x - 5)2 - 2x + 1 = 0
b) (2x - 7)2 - (x + 3)2 = 3x2 + 6
c) (3x + 2)2 - 9(x - 5) (x + 5) = 225 - 5x
a: \(\left(x+5\right)^2-\left(x-5\right)^2-2x+1=0\)
=>\(x^2+10x+25-\left(x^2-10x+25\right)-2x+1=0\)
=>\(x^2+8x+26-x^2+10x-25=0\)
=>18x+1=0
=>\(x=-\dfrac{1}{18}\)
b: \(\left(2x-7\right)^2-\left(x+3\right)^2=3x^2+6\)
=>\(4x^2-28x+49-\left(x^2+6x+9\right)-3x^2-6=0\)
=>\(x^2-28x+43-x^2-6x-9=0\)
=>34-34x=0
=>34x=34
=>x=1
c: \(\left(3x+2\right)^2-9\left(x-5\right)\left(x+5\right)=225-5x\)
=>\(9x^2+12x+4-9\left(x^2-25\right)-225+5x=0\)
=>\(9x^2+17x+4-225-9x^2+225=0\)
=>17x+4=0
=>x=-4/17
Tìm x, biết:
2/3: x/5 +5/7=2/7:3/5+10/9
A: x= 225/42
B: x = 11/42
C: 45/42
D: 42/11
\(\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{2}{7}:\frac{3}{5}+\frac{10}{9}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{2}{7}.\frac{5}{3}+\frac{10}{9}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{10}{21}+\frac{10}{9}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{100}{63}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}=\frac{100}{63}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}=\frac{55}{63}\)
\(\Rightarrow\frac{x}{5}=\frac{2}{3}:\frac{55}{63}\)
\(\Rightarrow\frac{x}{5}=\frac{2}{3}.\frac{63}{55}\)
\(\Rightarrow\frac{x}{5}=\frac{42}{55}\)
\(\Rightarrow x=\frac{42.5}{55}=\frac{42}{11}\)
Nên ta chọn đáp án D là đáp án đúng!
( trong bài có dấu . tức là dấu dấu nhân bn nhé )
2/3 : x/5 + 5/7 = 2/7 : 3/5 + 10/9
2/3 : x/5 + 5/7 = 10/21 + 10/9
2/3 : x/5 + 5/7 = 100/63
2/3 : x/5 = 100/63 - 5/7
2/3 : x/5 = 55/63
2/3 . 5/x= 55/63
=) 5/x = 55/63 : 2/3
=) 5/x = 55/42
ta có : a/b = c/d =) a.d=b.c
(=) 55.x = 5.42
55.x = 210
=) x = 210 : 55 = 42/11
vậy đáp án đúng là D
chúc bn học tốt
tìm x,y biết : a) (x-3)(y+5)=13 ; b) x-3=y(x+2) ; c) 1+3+5+...+(2x-1)=225 ( câu c x thuộc N*)
Tìm số nguyên x, biết:
a) 1 6 = x + 3 18
b) x − 2 8 = − 1 4
c) 4 − 5 = x : 2 10
d) 11 5 = − 22 5 − x
e) x : 2 + 1 8 = 8 x : 2 + 1
f) x : 2 − 11 = − 11 x : 2
a) x = 0
b) x= 0
c) x = -16
d) x = 15
e) x : 2 +1 = 8 hoặc x:2+1 = -8 . Do đó x = 14 hoặc x = -18.
f) x: 2 = 11 hoặc x : 2 = -11 . Do đó x = 22 hoặc x = -2
Tìm x ,biết
a)1440:[41-(2x-5)]=2^4.3
b)5.[225-(x-10)]-125=0
c)6: (chia hết) x
d)|x|=|-3|
e)2|x|+(-5)=7
a) 1440: [41-{2x-5}]=16.3
41-(2x-5)=1440-48
41-(2x-5)=1392
2x-5=41-1392
2x-5=-1351
2x=-1351+5
2x=-1346
x=(-1346):2
x=-673
b) 5.[225-(x-10)]-125=0
5.[225-(x-10)=0+125
225-(x-10)=125:5
225-(x-10)=25
x-10=225-25
x-10=200
x=200+10
x=210
thực hiện các phép tính sau
a) 12 x 31+225 : 52
b) 124 : 22 + 52 x 51 - 9
a) 12 x 31 + 225 : 52
= 12 x 3 + 225 : 25
= 36 + 9
= 45
b) 124 : 22 + 52 x 51 - 9
= 124 : 4 + 25 x 5 - 9
= 31 + 125 - 9
= 156 - 9
= 147
a) 12 x 31 + 225 : 52 b) 124 : 22 + 52 x 51 - 9
= 12 x 3 + 1,8 = 124 : 4 + 53 - 9
= 36 + 1,8 = 31 + 125 - 9
= 37,8 = 156 - 9
= 147
Hok tốt :3
Tìm x, biết
a) 21x = 63;
b) 32. |x| = 96;
c) 11x + 5 = 60;
d) 2 . |x| + 5 = 32 - 13.
a) x = 3.
b) x Î {-3; 3}.
c) x = 5.
d) x Î {-7; 7).