\(P=\left(-0,5-\frac{3}{5}\right):\left(-3\right)+\frac{1}{3}-\left(-\frac{1}{6}\right):\left(-2\right)\)

\(P=\left(-\frac{11}{10}\right):\left(-3\right)+\frac{1}{3}-\frac{1}{12}\)

\(P=\frac{11}{30}+\frac{1}{4}\)

\(P=\frac{37}{60}\)

\(Q=\left(\frac{2}{25}-1,008\right):\frac{4}{7}:\left[\left(\frac{13}{4}-\frac{59}{9}\right).\frac{36}{17}\right]\)

\(Q=\left(-\frac{116}{125}\right):\frac{4}{7}:\left(-7\right)\)

\(Q=\left(-\frac{203}{125}\right):\left(-7\right)\)

\(Q=\frac{29}{125}\)

1 ) 5/4 + 1/6 : 7/9

= 5/4 + 1/6 . 9/7

= 5/4 + 1 . 9 / 6 . 7

= 5/4 + 3/14

= 35/28 + 6/28

= 41/28

                 #Cothanhkhe

2) -1,6  : ( 1 + 2/3 )

= -16/10 : ( 3/3 + 2/3 )

= -8/5 : 3 + 2 /3

= -8/5 : 5/3

= -8/5 . 3/5

= -8 . 3 / 5 . 5

= -24/25

                    #Cothanhkhe

a:41/26

C = 59/10 : 3/2 - ( 5/3 x 9/2 x 14/3) : 7/4

= 59/15 - 35 : 7/4

= 59/15 - 20

= -241/15

1-2-3+4+5-6-7+....+100=(1-2-3+4)+(5-6-7+8)+.....+(97-98-99+100)=0+0+...+0=0

=(1-2-3+4)+(5-6-7+8)+...+(97-98-99+100)

=0+0+...+0

=0

vậy 0 là giá trị của biểu thức 1-2-3+4+5-6-7+...+97-98-99+100

   BÀI NÀY MÌNH HỌC RỒI NÊN MÌNH LÀM ĐÚNG ĐÓ NHA!

\(\frac{6:\frac{3}{5}-1\frac{1}{6}.\frac{6}{7}}{4\frac{1}{5}.\frac{10}{11}+5\frac{2}{11}}=\frac{10-\frac{7}{6}.\frac{6}{7}}{\frac{21}{5}.\frac{10}{11}+\frac{57}{11}}=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{9}=1\)

\(A=\dfrac{2}{3}+\dfrac{3}{4}\cdot\dfrac{-4}{9}=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}=\dfrac{100}{300}\)

\(B=\dfrac{25}{11}\cdot\dfrac{13}{12}\cdot\dfrac{-11}{5}=\dfrac{-65}{12}=\dfrac{-1625}{300}\)

\(C=\left(\dfrac{3}{4}-\dfrac{1}{5}\right)\cdot\left(\dfrac{2}{5}-\dfrac{4}{5}\right)=\dfrac{11}{20}\cdot\dfrac{-2}{5}=\dfrac{-22}{100}=\dfrac{-11}{50}=\dfrac{-66}{300}\)

Vì -1625<-66<100

nên B<C<A

1-2-3-4+5-6-7-8+9-10-11-12+...........+97-98-99-100

=(1-2-3-4)+(5-6-7-8)+(9-10-11-12)+.............+(97-98-99-100)

=-8+(-16)+(-24)+..................+(-200)

=-8.(1+2+3+......+25)

=-8.[(25-1):1+1.26:2]

=-8.325

=-2600