\(\left(7x+3\right)^2-\left(7x-1\right)\left(7x-3\right)=-12\)

\(\Rightarrow49x^2+42x+9-\left(49x^2-21x-7x+3\right)=-12\)

\(\Rightarrow70x+18=0\) \(\Rightarrow x=-\dfrac{18}{70}=-\dfrac{9}{35}\)

do các phân số ở hàng số thứ 2  đã tối giản nên x=0=>7x=0 =>tổng các phân số sau đều tối giản

I don't now 

sorry 

...................

nha

a)   \(\left(3x-1\right)^2+2\left(3x-1\right)\left(2x+1\right)+\left(2x+1\right)^2=0\)

\(\Leftrightarrow\)\(\left[\left(3x-1\right)+\left(2x-1\right)\right]^2=0\)

\(\Leftrightarrow\)\(\left(5x-2\right)^2=0\)

\(\Leftrightarrow\)\(5x-2=0\)

\(\Leftrightarrow\)\(x=\frac{2}{5}\)

Vậy...

b)  \(\left(7x+2\right)^2+\left(7x-2\right)^2-2\left(7x+2\right)\left(7x-2\right)=0\)

\(\Leftrightarrow\)\(\left[\left(7x+2\right)-\left(7x-2\right)\right]^2=0\)

\(\Leftrightarrow\)\(4^2=0\)  vô lí

Vậy pt vô nghiệm

-7X-3X

\(7x.\left(x-2\right)-5.\left(x-1\right)=7x^2+3\)

\(7x^2-14x-5x+5=7x^2+3\)

\(7x^2-19x+5=7x^2+3\)

\(7x^2-19x+5-\left(7x^2+3\right)=0\)

\(7x^2-19x+5-7x^2-3=0\)

\(-19x+2=0\)

\(-19x=0-2\)

\(-19x=-2\)

\(x=\frac{2}{19}\)

\(a)\frac{1}{7}x-\frac{1}{2}x+\frac{5}{7}x=-\frac{1}{2}\)

\(\Rightarrow\left(\frac{1}{7}-\frac{1}{2}+\frac{5}{7}\right)x=-\frac{1}{2}\)

\(\Rightarrow\left(\frac{2}{14}-\frac{7}{14}+\frac{10}{14}\right)x=-\frac{1}{2}\)

\(\Rightarrow\frac{5}{14}x=-\frac{1}{2}\)

\(\Rightarrow x=-\frac{1}{2}:\frac{5}{14}\)

\(\Rightarrow x=-\frac{1}{2}.\frac{14}{5}\)

\(\Rightarrow x=-\frac{7}{5}\)

\(b)(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{49.51})x=-\frac{1}{3}\)

\(\Rightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{49}-\frac{1}{51}\right)x=-\frac{1}{3}\)

\(\Rightarrow\left(\frac{1}{11}-\frac{1}{51}\right)x=-\frac{1}{3}\)

\(\Rightarrow\left(\frac{51}{561}-\frac{11}{561}\right)x=-\frac{1}{3}\)

\(\Rightarrow\frac{40}{561}x=-\frac{1}{3}\)

\(\Rightarrow x=-\frac{1}{3}:\frac{40}{561}\)

\(\Rightarrow x=-\frac{1}{3}.\frac{561}{40}\)

\(\Rightarrow x=-\frac{187}{40}\)

Chúc bạn học tốt !!! 

địt mẹ mày

Tìm x để đa thức trên có nghiệm là 0

tục quá 

x=1/3 nhé bạn

tick tớ nhé

tick tớ đi buồn quá nãy giờ chưa ai tick.coi như giúp tớ đi

a) x² - 4x - 5 = 0

=> x² - 5x + x - 5 = 0

=> x(x - 5) + (x - 5) = 0

=> (x + 1)(x - 5) = 0

=> \(\orbr{\begin{cases}x+1=0\\x-5=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=-1\\x=5\end{cases}}\)

b) 4x² + 7x - 11 = 0

=> 4x² + 11x - 4x - 11 = 0

=> x(4x + 11) - (4x + 11) = 0

=> (x - 1)(4x + 11) = 0

=> \(\orbr{\begin{cases}x-1=0\\4x+11=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=1\\x=-\frac{11}{4}\end{cases}}\)

c) -7x² + 6x + 1 = 0

=> -7x² + 7x - x + 1 = 0

=> -7x(x - 1) - (x - 1) = 0

=> (-7x - 1)(x - 1) = 0

=> \(\orbr{\begin{cases}-7x-1=0\\x-1=0\end{cases}}\)

=> \(\orbr{\begin{cases}-7x=1\\x=1\end{cases}}\)

=> \(\orbr{\begin{cases}x=-\frac{1}{7}\\x=1\end{cases}}\)

d) -10x² + 7x + 3 = 0

=> -10x² + 10x - 3x + 3 = 0

=> -10x(x - 1) - 3(x - 1) = 0

=> (-10x - 3)(x - 1) = 0

=> \(\orbr{\begin{cases}-10x-3=0\\x-1=0\end{cases}}\)

=> \(\orbr{\begin{cases}-10x=3\\x=1\end{cases}}\)

=> \(\orbr{\begin{cases}x=-\frac{3}{10}\\x=1\end{cases}}\)

\(a,x^2-4x-5=0\)

\(\Rightarrow x^2-5x+x-5=0\)

\(\Rightarrow x\left(x-5\right)+\left(x-5\right)=0\)

\(\Rightarrow\left(x-5\right)\left(x+1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)

\(b,4x^2+7x-11=0\)

\(\Rightarrow4x^2-4x+11x-11=0\)

\(\Rightarrow4x\left(x-1\right)+11\left(x-1\right)=0\)

\(\Rightarrow\left(x-1\right)\left(4x+11\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-1=0\\4x+11=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-\frac{11}{4}\end{cases}}}\)

\(c,-7x^2+6x+1=0\)

\(\Rightarrow-7x^2+7x-x+1=0\)

\(\Rightarrow-7x\left(x-1\right)-\left(x-1\right)=0\)

\(\Rightarrow\left(x-1\right)\left(-7x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-1=0\\-7x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-\frac{1}{7}\end{cases}}}\)

\(d,-10x^2+7x+3=0\)

\(\Rightarrow-10x^2+10x-3x+3=0\)

\(\Rightarrow-10x\left(x+1\right)-3\left(x+1\right)=0\)

\(\Rightarrow\left(x+1\right)\left(-10x-3\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+1=0\\-10x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\x=-\frac{3}{10}\end{cases}}}\)