A = \(\frac{3^4\left(5.79-1\right)}{2^2.3^2\left(5.79-1\right)}=\frac{9}{4}\); B = \(\frac{3.7.13.37\left(5.11-1\right)}{4.3.7.13.37\left(3.5-1\right)}=\frac{54}{4.14}=\frac{2.9}{4.2.7}=\frac{9}{28}\)

Câu a)  \(\dfrac{31995-81}{42660-108}=\dfrac{31914}{42552}=\dfrac{31914:10638}{42552:10638}\)

             =\(\dfrac{3}{4}\)

Câu b) \(\dfrac{\left(3.5.7.11.13.15.37-10101\right)}{121212+40404}\)

          =\(\dfrac{\left(3.5.7.11.13.15.37-3.7.13.37\right)}{3.7.13.37.12+3.7.13.37.4}\)

          =\(\dfrac{3.7.13.37\left(5.11.15-1\right)}{3.7.13.37\left(12+4\right)}\)

          = \(\dfrac{824}{16}\)=\(\dfrac{103}{2}\)

?

a) \(\dfrac{31995-81}{42660-108}=\dfrac{31914}{42552}=\dfrac{3}{4}\)

b: \(\dfrac{3\cdot5\cdot7\cdot11\cdot37-10101}{1212120+40404}=\dfrac{32634}{1252524}=\dfrac{21}{806}\)

\(\frac{27}{62}\)

\(\frac{27}{62}\)

A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62

đúng nhé

\(a,A=\dfrac{201220122012}{201320132013}=\dfrac{201220122012:100010001}{201320132013:100010001}=\dfrac{2012}{2013}\)

\(b,B=\dfrac{3.5.7.11.13.37-10101}{1212120+40404}=\dfrac{5.11.10101-10101}{10101.120+10101.4}=\dfrac{10101.\left(5.11-1\right)}{10101.\left(120+4\right)}=\dfrac{54}{124}=\dfrac{27}{62}\)

Ta có:

\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)

\(=\frac{\left(3.7.11.13.37\right).5-10101.1}{120.10101+4.10101}\)

\(=\frac{10101.\left(5-1\right)}{10101.\left(120+4\right)}\)

\(=\frac{4}{124}=\frac{1}{31}\)

Sai rồi:

A = 5.11.(3.7.13.37) - 10101/(10101.120 + 10101.4)

= (5.11.10101 - 10101)/(10101.120+10101.4)

= 10101(5.11-1)/10101(120+4)

= 27/62.

A= 5.11.(3.7.13.37)-10101/(10101.120+10101.4)

=(5.11.10101-10101)/(10101.120+10101.4)

=10101.(5.11-1)/10101(120+4)

=27/62

k mik nha mik k lại 100 cái lun

.5.7.11.13.37-10101/1212120+40404

=3.5.7.11.13.37-10101/1212120.1/10+40404 (vì 1/1212120=1/121212.1/10)

= 3.37.7.11.13.5-101010/121212.1/100+40404

=111.1001.5-5/6.1/100+40404

=151515.5-250/3

=595959-250/3

=1787876/3

1787876/3

A=3.5.7.11.13.37-10101/1212120+40404

A=(5.11).(3.7.13.37)-10101/10101.120+4.10101

A=55.10101-10101/10101.(120+4)

A=10101.(55-1)/10101.124

A=54/124

A=27/62

\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)

\(A=\frac{\left(3.7.13.17\right).\left(5.11\right)-10101}{120.10101+4.10101}\)

\(A=\frac{10101.55-10101.1}{120.10101+4.10101}\)

\(A=\frac{10101.\left(55-1\right)}{10101.\left(120+4\right)}\)

\(A=\frac{10101.54}{10101.124}\)

\(A=\frac{54}{124}\)

\(A=\frac{27}{62}\)

- chúc bn hok tốt

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