the sum A of 191 consecutive positive integers is a perfect square . Find the largest of those 191 positive integers so that A has the smallest value  

Several pairs of whole numbers (m,n) satisfy 19m + 90 + 8n = 1998 (100,1) is the pair with the smallest value for n. Find m such that (m,n) is t he pair with the smallest value for m

Find the smallest póitive integer n such that the number \(2^n+2^8+2^{11}\)is a perfect square

the units digit of a positive number is 2. if we move it to the other rnd, we get a new number which is twice the old number. what is the smallest value of the old number?

the units digit of a positive number is 2. if we move it to the other end, we get a new number which is twice the old number. what is the smallest value of the old number?

Several pairs of whole numbers (m;n) satisfy :

19m+90+8n=1998

(100;1) í the pair with the smallest value for n.

Find ma such that (m;n) is the pair with the smallest value of n.

Answer: .......

Each digit of a positive integer is 1 or 2 or 3 . Given that each of the digit 1;2 and 3 occurs at least twice
What is the smallest such integer that is not divisible by 2 or 3? 

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the units digit of a positive number is 2. if we move it to the other end, we get a new number which is twice the old number. what is the smallest value of the old number?