\(1.x-\dfrac{2}{3}\times\left(x+9\right)=1\)

\(x-\dfrac{2}{3}\times x-6=1\)

\(x\times\left(1-\dfrac{2}{3}\right)=7\)

\(x\times\dfrac{1}{3}=7\)

\(x=21\)

\(2.x-\dfrac{11}{15}=\dfrac{3+x}{5}\)

\(\dfrac{15x}{15}-\dfrac{11}{15}=\dfrac{9+3x}{15}\)

\(15x-11=9+3x\)

\(12x=20\)

\(x=\dfrac{5}{3}\)

a) \(5^{x-1}+5^{x-3}=650\)

\(\Rightarrow5^x\left(\frac{1}{5}+\frac{1}{125}\right)=650\)

\(\Rightarrow5^x=650:\frac{26}{125}\)

\(\Rightarrow5^x=3125\)

\(\Rightarrow5^x=5^5\)

\(\Rightarrow x=5\)

suy ra3.(5x-1) - 4.(5x-1) + 6(5x-1) =15

suy ra 5.(5x-1) = 15

suy ra 5x-1=3 

suy ra x=4/5

\(\Leftrightarrow3\left(5x-1\right)-4\left(5x-1\right)+6\left(5x-1\right)=15\)

\(\Leftrightarrow\left(3-4+6\right)\left(5x-1\right)=15\)

\(\Leftrightarrow5\left(5x-1\right)=15\)

\(\Leftrightarrow5x-1=\frac{15}{5}=3\)

\(\Leftrightarrow5x=3+1=4\)

\(\Leftrightarrow x=\frac{4}{5}\)

Vậy \(x=\frac{4}{5}\)

\(\sqrt{9\left(5x-1\right)}-\sqrt{16\left(5x-1\right)}+\sqrt{36\left(5x-1\right)}=15\)

<=> \(3\sqrt{5x-1}-4\sqrt{5x-1}+6\sqrt{5x-1}=15\)

<=> \(5\sqrt{5x-1}=15\)

<=>  \(25\left(5x-1\right)=225\) (bình phương 2 vế)

<=> 5x - 1 = 225 : 25

<=> 5x - 1 = 9

<=> 5x = 9 + 1

<=> 5x = 10

<=> x = 2

Lời giải:
a.

$x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{7-5}{25}=\frac{2}{25}$

b.

$x=\frac{5}{11}+\frac{4}{-9}=\frac{5}{11}-\frac{4}{9}=\frac{45}{99}-\frac{44}{99}=\frac{1}{99}$

c.

$\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}=\frac{-3}{9}-\frac{5}{9}=\frac{-8}{9}$

$x=(-1).\frac{-8}{9}=\frac{8}{9}$

minh@@22@22222@@@@? 

a) Rút gọn VT = 45x + 8. Từ đó tìm được x = 2 15 .  

b) Rút gọn VT = -25x – 8. Từ đó tìm được x = − 11 25 .

x + 1 + x + 3 +x + 5 + x + 7 + x + 9 = 750

  ( x + x + x + x + x ) + ( 1 + 3 + 5 + + 7 + 9 ) = 750

     x x 5 + 25 = 750

     x x 5 = 750 - 25

     x x  5 = 725

           x = 725 :5

           x = 145

x=750:(1+3+5+7+9)

x=750:25

x=30

x+1+x+3+x+5+...+x+9 

= ( x+x+x+x)+ (1+3+5+9)

=x*5+25=750

  x*5=750-25

  x*5=725

     x= 725:5

     x=145