=> 1+2+3+4+5+....+x = 190

x(x+1) = 190.2 = 380

x(x+1) = 19.(19 + 1)

VẬy x = 19 

3.3².3³.3⁴......3^x=3¹⁹⁰

=>3^{(1+2+3+...........+x)}=3¹⁹⁰

=>1+2+3+.........+x=190

=>\(\frac{x.\left(x+1\right)}{2}\)=180

=>x.(x+1)=190.2

=>x.(x+1)=380

=>x=19

\(3\cdot3^2\cdot3^3\cdot3^4\cdot....\cdot3^x=3^{190}\)

\(\Leftrightarrow3^{1+2+3+...+x}=3^{190}\)

\(\Leftrightarrow1+2+3+...+x=190\)

\(\Leftrightarrow\dfrac{x\left(x+1\right)}{2}=190\Leftrightarrow x\left(x+1\right)=380\)

\(\Leftrightarrow x^2+x-380=0\)

\(\Leftrightarrow x^2-19x+20x-380=0\)

\(\Leftrightarrow x\left(x-19\right)+20\left(x-19\right)=0\)

\(\Leftrightarrow\left(x-19\right)\left(x+20\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-19=0\\x+20=0\end{matrix}\right.\)\(\Leftrightarrow x=19\left(x>0\right)\)

dễ

3.3^2.3^3.............3^x=3^190

3^1+2+3+4+....+x=3^190

nên 1+2+3+.........+x=190

hay (x+1).x :2 =190        nen 190.2= (x+1) . x hay 380 =19.20

vay x=19

Đáp số Ra 19 đó các bạn ạ

=>3^{1+2+3+4+...+x}=3¹⁹⁰

=>1+2+3+4+...+x=190

=>(x+1).x:2=190

=>(x+1).x=380

mà 380 chỉ có thể ptích thành: 380=20.19

=>x+1=20 và x=19

vậy x=19

làm ơn giúp mình ,bạn nào làm nhanh đúng mình chọn cho nhanh nha mọi người

nhanh nha mọi người

T.T

Bài làm

2².4⁴.2⁶.2.2=2².2⁸.2⁶.2²=2¹⁸

2.2³.2⁷.2⁴=2¹⁵

3².3=3³=27

3⁴.3³.3=3⁸

3.3⁵.3⁴.3²=3¹²

3.3⁶.3⁷.3⁴=3¹⁸

4.4³=4⁴

4⁵.4.4⁷=4¹³

4.4³.4⁵.4⁶=4¹⁵

5.5⁶=5⁷

5.5⁴=5⁵

5.5².5⁴=5⁷

5.5³.5⁴.5⁶=5¹⁴

5.5⁶.5⁴.5³=5¹⁴

x.x²=x³

x.x³.x⁵=x⁹

a.a⁴=a⁵

a.a².a⁴.a⁵.a⁷=a¹⁹

a.a³.a⁵.a⁶=a¹⁵

a.a⁴.a.a⁵.a⁶.a=a¹⁸

x.x³.x⁴=x⁸

x⁵.x⁴.x.x⁷.x⁶=x²³

7.7²=7³

7.7².7⁴.7⁵=7¹²

7³.7⁵.7⁴.7=7¹³

7².7.7⁶.7⁶.7³=7¹⁸

10.10²=10³

10.100.10³=10⁶

10.100.10⁴.1000=10¹⁰

10².10⁴.100.1000=10¹¹

Tk nha !

3S= 3+2.3²+3.3³+...+101.3¹⁰¹

<=> 2S= 101.3¹⁰¹-(3¹⁰⁰+3⁹⁹+3⁹⁸+....+3⁾-1            (1)

Ta có 

A=3¹⁰⁰+3⁹⁹+...+3

<=> 3A=3¹⁰¹+3¹⁰⁰+...+3²

<=> A=\(\frac{3^{101^{ }}-3}{2}\)(2)

Thay (2) vào (1) ta có

S=        \(\frac{101.3^{101}-\frac{3^{101}-3}{2}-1}{2}\)

<=> S=\(\frac{3^{101}.201-1}{2}.\frac{1}{2}\)=\(\frac{3^{101}.201-1}{4}\)

Mik nghĩ vậy k bt đúng k

\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}+\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{12}}\)

\(=\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}-\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{12}}\)

\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6-2^{12}.3^5}-\frac{2^{12}.3^{10}-2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{12}.3^{12}}\)

\(=\frac{2^{12}.\left(3^5-3^4\right)}{2^{12}.\left(3^6-3^5\right)}-\frac{2^{12}.3^{10}-2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{12}.3^{12}}\)

\(=\frac{3^5-3^4}{3^6-3^5}-\frac{2^{12}.3^{10}.\left(1-5\right)}{2^{13}.3^{12}}\)

\(=\frac{162}{486}-\frac{2^{12}.3^{10}.\left(-4\right)}{2^{13}.3^{10}.3^2}=\frac{1}{3}-\frac{2^{14}.3^{10}.\left(-1\right)}{2^{13}.3^{10}.9}\)

\(=\frac{1}{3}-\frac{2.1.\left(-1\right)}{1.1.9}=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)